5555+ Aptitude and Reasoning Questions, Answers With Explanation

Q:

The total of 324 of 20 paise and 25 paise make a sum of Rs. 71. The no of 20 paise coins is :

A) 50	B) 100
C) 150	D) 200

Answer & Explanation Answer: D) 200

Explanation:

Let the number of 20 paise coins be x. Then the no of 25 paise coins = (324 - x).

0.20 * (x) + 0.25 (324 - x) = 71 => x = 200..

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Filed Under: Simplification

19 16897

Q:

If the cost price of a certain object doubles, then the loss gets tripled of what it was initially. The initial loss % was ?

A) 0 %	B) 25 %
C) 75 %	D) 50 %

Answer & Explanation Answer: D) 50 %

Explanation:

Let the cost price be x and selling price be y.
Loss = x – y

When the cost price doubles, the loss gets tripled.
So it becomes like this, 2x – y = 3(x-y)

=> x = 2y

Loss % = (loss/ C.P) x 100 = [(2y-y)/2y] x 100= 50 %

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Filed Under: Profit and Loss
Exam Prep: CAT
Job Role: Bank PO

24 16885

Q:

Arrange the following words as per order in the dictionary

1. Sinister 2. Sinuous 3. Sinhalese 4.Sinusitis 5. Sinecure

A) 5, 3, 2, 4, 1	B) 5, 2, 4, 3, 1
C) 5, 2, 1, 3, 4	D) 5, 3, 1, 2, 4

Answer & Explanation Answer: D) 5, 3, 1, 2, 4

Explanation:

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Filed Under: Logical Sequence of Words
Exam Prep: Bank Exams

0 16884

Q:

The cube root of .000216 is:

A) .6	B) .06
C) 77	D) 87

Answer & Explanation Answer: B) .06

Explanation:

${(. 000216)}^{\frac{1}{3}} = {(\frac{216}{10^{6}})}^{\frac{1}{3}} = {[\frac{6 * 6 * 6}{10^{2} * 10^{2} * 10^{2}}]}^{\frac{1}{3}} = [\frac{6}{10^{2}}] = 0.06$

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Filed Under: Square Roots and Cube Roots

72 16877

Q:

Statements followed by some conclusions are given below.

Statements:
1. A bag has 2 white, 3 black, 4 red and 6 green balls.
2. 2 balls are selected at random from the bag.

Conclusions:
1. The probability that a black ball is selected is 1/5.
2. The probability that a red ball is selected is 6/15.

Find which of the conclusions logically follows from the given statements.

A) Only conclusion 1 follows	B) Only conclusion 2 follows
C) Both 1 and 2 follow	D) Neither 1 nor 2 follows

Answer & Explanation Answer: A) Only conclusion 1 follows

Explanation:

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Filed Under: Statement and Conclusions
Exam Prep: Bank Exams

0 16854

Q:

If you deposit $6500 into an account paying 8% annual interest compounded monthly, how
much money will be in the account after 7 years?

A) 11358.24	B) 12334
C) 15789	D) 12386

Answer & Explanation Answer: A) 11358.24

Explanation:

FV=P(1+r/n)^nt

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

19 16837

Q:

Amit can do a piece of work in 45 days, but Bharath can do the same work in 5 days less, than Amit, when working alone. Amit and Bharath both started the work together but Bharath left after some days and Amit finished the remaining work in 56 days with half of his efficiency but he did the work with Bharath with his complete efficiency. For how many days they had worked together?

A) 6	B) 8
C) 9	D) 12

Answer & Explanation Answer: B) 8

Explanation:

$\begin{matrix} A m i t & B h a r a t \\ N o . o f D a y s & 45 & 40 \\ E f f i c i e n c y & 2.22 P e r c e n t (= \frac{1}{45}) & 2.5 P e r c e n t (= \frac{1}{40}) \end{matrix}$

Amit did the work in 56 days = $56 \times \frac{1}{45 \times 2} = \frac{28}{45}$

Therefore, Rest work 17/45 was done by Amit and Bharath = $\frac{\frac{17}{45}}{\frac{17}{360}}$ = 8 days

( since Amit and Bharath do the work in one day = $\frac{1}{45} + \frac{1}{40} = \frac{17}{360}$ )

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Filed Under: Time and Work
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

30 16832

Q:

The following table shows the number of new employees added to different categories of employees in a company and also the number of employees from these categories who left the company every year

1.What is the difference between the total number of Technicians added to the Company and the total number of Accountants added to the Company during the years 1996 to 2000?

A. 128 B. 112 C. 96 D. 88

2. What was the total number of Peons working in the Company in the year 1999?

A. 1312 B. 1192 C. 1088 D. 968

3. For which of the following categories the percentage increase in the number of employees working in the Company from 1995 to 2000 was the maximum?

A. Managers B. Technicians C. Operators D. Accountants

4. What is the pooled average of the total number of employees of all categories in the year 1997?

A. 1325 B. 1195 C. 1265 D. 1235

5. During the period between 1995 and 2000, the total number of Operators who left the Company is what percent of total number of Operators who joined the Company?

A. 19% B. 21% C. 27% D. 29%

Answer

1. ANSWER : D

Explanation - Required difference

= (272 + 240 + 236 + 256 + 288) - (200 + 224 + 248 + 272 + 260)

= 88.

2. ANSWER : B

Explanation - Total number of Peons working in the Company in 1999

= (820 + 184 + 152 + 196 + 224) - (96 + 88 + 80 + 120)

= 1192.

3. ANSWER : A

Explanation - Number of Managers working in the Company:

In 1995 = 760.
In 2000 = (760 + 280 + 179 + 148 + 160 + 193) - (120 + 92 + 88 + 72 + 96)= 1252.

Therefore, Percentage increase in the number of Managers

= $\frac{(1252 - 760)}{760} \times 100$ %= 64.74%

Number of Technicians working in the Company:
In 1995 = 1200.
In 2000 = (1200 + 272 + 240 + 236 + 256 + 288) - (120 + 128 + 96 + 100 +112) = 1936.

Therefore, Percentage increase in the number of Technicians

= $\frac{(1936 - 1200)}{1200} \times 100$ % = 61.33%

Number of Operators working in the Company:

In 1995 = 880.
In 2000 = (880 + 256 + 240 + 208 + 192 + 248) - (104 + 120 + 100 + 112 + 144) = 1444.

Therefore, Percentage increase in the number of Operators

= $\frac{(1444 - 880)}{880} \times 100$ % = 64.09%

Number of Accountants working in the Company:

In 1995 = 1160.
In 2000 = (1160 + 200 + 224 + 248 + 272 + 260) - (100 + 104 + 96 + 88 + 92) = 1884.

Therefore, Percentage increase in the number of Accountants

= $\frac{(1884 - 1160)}{1160} \times 100$ % = 62.14%

Number of Peons working in the Company:

In 1995 = 820.
In 2000 = (820 + 184 + 152 + 196 + 224 + 200) - (96 + 88 + 80 + 120 + 104) = 1288.

Therefore, Percentage increase in the number of Peons

= $\frac{(1288 - 820)}{820} \times 100$ % = 57.07%

Clearly, the percentage increase is maximum in case of Managers.

4. ANSWER : B

Explanation - Total number of employees of various categories working in the Company in 1997 are:

Managers = (760 + 280 + 179) - (120 + 92) = 1007.

Technicians = (1200 + 272 + 240) - (120 + 128) = 1464.

Operators = (880 + 256 + 240) - (104 + 120) = 1152.

Accountants = (1160 + 200 + 224) - (100 + 104) = 1380.

Peons = (820 + 184 + 152) - (96 + 88) = 972.

Therefore, Pooled average of all the five categories of employees working in the Company in 1997 = 1/5 x (1007 + 1464 + 1152 + 1380 + 972)

= 1/5 x (5975)

= 1195.

5. ANSWER : D

Explanation - Total number of Operators who left the Company during 1995 - 2000

= (104 + 120 + 100 + 112 + 144)

= 580.

Total number of Operators who joined the Company during 1995 - 2000

= (880 + 256 + 240 + 208 + 192 + 248

= 2024.

Therefore, Required Percentage

= (580/2024)x100% = 28.66% ~= 29%.

Aptitude and Reasoning Questions

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Why Aptitude and Reasoning Questions?

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Non Verbal Reasoning

Quantitative Aptitude - Arithmetic Ability

Quantitative Aptitude - Data Interpretation

Verbal Reasoning - Logical Deduction

Verbal Reasoning - Mental Ability

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