Aptitude and Reasoning Questions

Q:

Study the following table and answer the questions based on it.

 

Below is the Household Expenditure (in Thousands Rupees) per annum.

 

 

What is the average spending on Leisure per annum?

 

A) Rs. 7040 B) Rs. 6500
C) Rs. 7100 D) Rs. 7400  
 
Answer & Explanation Answer: A) Rs. 7040

Explanation:
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Filed Under: Table Charts
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Q:

Main street high school has 10 members on its football team and 14 members on its science club. 5 members at the school belong to both the football and science teams. How many students belong to only science club team or football team?

A) 9 B) 14
C) 24 D) 21
 
Answer & Explanation Answer: A) 9

Explanation:

Given that,

Members in football team = n(f) = 10

Members in science club = n(s) = 14

Members in both football team and science club = n(f ^ s) = 5

 

Then, Members in only football team = n(F) = 10 - 5 = 5

Members in only science team = n(S) = 14 - 5 = 9

football_science_teams1533013879.jpg image

 

Hence, members in only football or science team = n(FUS) = n(F) + n(S) - n(f^s) 

= 9 + 5 - 5

= 9.

 

Hence, many students belong to only science club team or football team = 9.

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Filed Under: Logical Venn Diagram
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Q:

Refer the below data table and answer the following question.

What was the total profit or loss of the company in last 5 years?

A) Loss of Rs 65 crores B) Profit of Rs 75 crores
C) Profit of Rs 65 crores D) Loss of Rs 75 crores
 
Answer & Explanation Answer: C) Profit of Rs 65 crores

Explanation:
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Q:

A box contains 2 white balls, 3 black balls and 4 red balls. In how many ways can 3 balls be drawn from the box, if at least one black ball is to be included in the draw?

A) 48 B) 64
C) 63 D) 45
 
Answer & Explanation Answer: B) 64

Explanation:

We may have(1 black and 2 non-black) or (2 black and 1 non-black) or (3 black).

 

Required number of ways=3C1*6C2+3C2*6C1+3C3 = (45 + 18 + 1) =64

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Q:

Refer the below data and answer the following question.

Between 10pm to 6am, a fitness band records the following data. How long was the user in light Sleep or was in Extremely light sleep?

 

A) 4.4 hours B) 3.9 hours
C) 2.9 hours D) 4.9 hours
 
Answer & Explanation Answer: A) 4.4 hours

Explanation:
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Q:

Pipe A can fill a tank in 16 minutes and pipe B cam empty it in 24 minutes. If both the pipes are opened together after how many minutes should pipe B be closed, so that the tank is filled in 30 minutes  ?

A) 21 min B) 24 min
C) 20 min D) 22 min
 
Answer & Explanation Answer: A) 21 min

Explanation:

Let the pipe B be closed after 'K' minutes.

30/16 - K/24 = 1 => K/24 = 30/16 - 1 = 14/16

=> K = 14/16 x 24 = 21 min.

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Filed Under: Pipes and Cistern
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Q:

A can write 32 pages in 6 hours and B can write 40 pages in 5 hours. If they write together, in how many hours they can write 110 pages ?

A) 7 hrs B) 6 hrs 10 min
C) 5 hrs 25min D) 8 hrs 15 min
 
Answer & Explanation Answer: D) 8 hrs 15 min

Explanation:

A can write in 1hour = 32/6 pages

Similarly, B in 1 hour = 40/5 pages

Together (A+B) in 1 hour = 32/6 + 40/5 = 40/3

So, A+B write 40/3 pages in 1 hour

A+B write 110 pages in (3/40) x 110 Hours = 8 hours 15 min.

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Filed Under: Time and Work
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Q:

A drink vendor has 80 liters of Mazza, 144 liters of Pepsi, and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required?

A) 35 B) 36
C) 37 D) 38
 
Answer & Explanation Answer: C) 37

Explanation:

If we want to pack the drinks in the least number of cans possible, then each can should contain the maximum numbers of liters possible.As each can contains the same number liters of a drink, the number of liters in each can is a comman factor for 80,144 and 368; and it is also the highest such factor, as we need to store the maximum number of liters in each can.

So, the number of liters in each can  = HCF of 80,144 and 368 = 16 liters.

Now, number of cans of Maaza = 80/16 = 5

Number of cans of Pepsi = 144/16 = 9

Number of cans of Sprite = 368/16 = 23

Thus, the total number of cans required = 5 + 9 + 23 = 37 

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Filed Under: HCF and LCM

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