Aptitude and Reasoning Questions

Q:

Calculate the total numbers of prime factors in the expression (5)11 x (5)7 x (7)5 x (3)2 x (17)2.

 

A) 35 B)  36
C) 37 D) 38
 
Answer & Explanation Answer: D) 38

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

7 13733
Q:

A girl counted in the following way on the fingers of her left hand : She started by calling the thumb 1, the index finger 2, middle finger 3, ring finger 4, little finger 5 and then reversed direction calling the ring finger 6, middle finger 7 and so on. She counted upto 1995. She ended counting on which finger ?

A) Thumb B) Index finger
C) Ring finger D) Middle finger
 
Answer & Explanation Answer: D) Middle finger

Explanation:

Clearly, while counting the numbers associated to the thumb will be 1,9,17,25,.........
i.e., numbers of the form (8n + 1 ).
where n=1,2,3...
Since 1994 = 249 × 8 + 2, so 1993 shall correspond to the thumb and 1994 to the index finger and 1995 to the middle finger.

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Filed Under: Arithmetical Reasoning
Exam Prep: Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

9 13726
Q:

There are 6561 balls are there out of them 1 is heavy. Find the minimum number of times the balls have to be weighted for finding out the heavy ball ?

A) 2414 B) 204
C) 87 D) 8
 
Answer & Explanation Answer: D) 8

Explanation:

Suppose there are 9 balls

 

Let us give name to each ball B1 B2 B3 B4 B5 B6 B7 B8 B9

 

Now we will divide all the balls into 3 groups.

 

Group1 - B1 B2 B3

 

Group2 - B4 B5 B6

 

Group3 - B7 B8 B9

 

Step1 - Now weigh any two groups. Let's assume we choose Group1 on left side of the scale and Group2 on the right side.

 

So now when we weigh these two groups we can get 3 outcomes.

 

Weighing scale tilts on left - Group1 has a heavy ball.
Weighing scale tilts on right - Group2 has a heavy ball.
Weighing scale remains balanced - Group3 has a heavy ball.
Lets assume we got the outcome as 3. i.e Group 3 has a heavy ball.

 

Step2 - Now weigh any two balls from Group3. Lets assume we keep B7 on left side of the scale and B8 on right side.

 

So now when we weigh these two balls we can get 3 outcomes.

 

Weighing scale tilts on left - B7 is the heavy ball.
Weighing scale tilts on right - B8 is the heavy ball.
Weighing scale remains balanced - B9 is the heavy ball.
The conclusion we get from this Problem is that each time weigh. We element 2/3 of the balls.

 

As we came to conclusion that Group3 has the heavy ball from Step1, we remove 6 balls from the equation i.e (2/3) of 9.

 

Simillarly we do the ame thing for the Step2.

 

Now going with this conclusion. We have 6561 balls.

 

Step - 1

 

Divided into 3 groups

 

Group1 - 2187Balls

 

Group2 - 2187Balls

 

Group3 - 2187Balls

 

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

 

Step - 2

 

Divided into 3 groups

 

Group1 - 729Balls

 

Group2 - 729Balls

 

Group3 - 729Balls

 

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

 

Step - 3

 

Divided into 3 groups

 

Group1 - 243Balls

 

Group2 - 243Balls

 

Group3 - 243Balls

 

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

 

Step - 4

 

Divided into 3 groups

 

Group1 - 81Balls

 

Group2 - 81Balls

 

Group3 - 81Balls

 

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

 

Step - 5

 

Divided into 3 groups

 

Group1 - 27Balls

 

Group2 - 27Balls

 

Group3 - 27Balls

 

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

 

Step - 6

 

Divided into 3 groups

 

Group1 - 9Balls

 

Group2 - 9Balls

 

Group3 - 9Balls

 

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

 

Step - 7

 

Divided into 3 groups

 

Group1 - 3Balls

 

Group2 - 3Balls

 

Group3 - 3Balls

 

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

 

Step - 8

 

So now when we weigh 2 balls out of 3 we can get 3 outcomes.

 

Weighing scale tilts on left - left side placed is the heavy ball.
Weighing scale tilts on right - right side placed is the heavy ball.
Weighing scale remains balanced - remaining ball is the heavy ball.
So the general answer to this question is, it is always multiple of 3 steps.

 

For 9 balls  32= 9. therefore 2 steps

 

For 6561 balls 38 = 6561 therefore 8 steps

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Filed Under: Arithmetical Reasoning
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13 13714
Q:

A can do a piece of work in 21 days and B in 28 days. Together they started the work and B left after 4 days. In how many days can A alone do the remaining work ?

A) 14 days B) 18 days
C) 21 deays D) 16 days
 
Answer & Explanation Answer: A) 14 days

Explanation:

Let A worked for x days.

x/21 + 4/28 = 1  => x = 18

 

A worked for 18 days. So, A can complete the remaining work in 18 - 4 = 14 days.

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Filed Under: Time and Work
Exam Prep: GATE , CAT , Bank Exams , AIEEE
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4 13713
Q:

There are two containers, the first one contains 1 litre pure water and the second one contains 1 litre pure milk.Now 5 cups of water from the first container is taken out  is mixed well in the second container. Then, 5 cups of this mixture is taken out and is mixed in the first container. Let A denote the proportion of milk in the first container and B denote the proportion of water in the second container then:

A) A B) A=B
C) A>B D) can't be determined
 
Answer & Explanation Answer: B) A=B

Explanation:

Here the ratio of mixtures( i.e milk , water) doesnot matter. But the important point is that whether the total amount ( either pure or mixture ) being transferred is equal or not.Since the total amount ( i.e 5 cups) being transferred from each one to another , hence A =B.

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Filed Under: Ratios and Proportions

18 13712
Q:

Answer the questions based on the following bar chart

 

The following bar chart shows the trends of mutual funds investments into India from all over the world.

 

 

Which year exhibited the highest growth in mutual funds investments in India over the period shown?

A) 1993 B) 1994
C) 1995 D) 1996
 
Answer & Explanation Answer: D) 1996

Explanation:
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Filed Under: Bar Charts
Exam Prep: Bank Exams

0 13711
Q:

In a simultaneous throw of two dice, what is the probability of getting a doublet ?

A) 1/6 B) 1/3
C) 4/7 D) 4/5
 
Answer & Explanation Answer: A) 1/6

Explanation:

In a simultaneous throw of two dice, n(S) = 6 x 6 = 36

 

Let E = event of getting a doublet = { (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}

 P(E)=n(E)n(S)=636=16

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Filed Under: Probability

10 13704
Q:

Directions : For the Assertion (A) and Reason (R) below, choose the correct alternative 

Assertion (A)  :    Leakages in household gas cylinders can be detected. 

Reason (R)     :    LPG has a strong smell. 

A) Both A and R are true and R is the correct explanation of A. B) Both A and R are true but R is NOT the correct explanation of A.
C) A is true but R is false. D) A is false but R is true.
 
Answer & Explanation Answer: C) A is true but R is false.

Explanation:

Leakages in household gas cylinders can be detected because of the strong smell of ethyl merceptan mixed with LPG. 

 

 

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Filed Under: Assertion and Reason

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