Sawaal
  • Home/
  • Aptitude and Reasoning

Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

Should government jobs in rural areas have more incentives

Arguments:

1. Yes. Incentives are essential for attracting government servants there

2. No. Rural areas are already cheaper,healthier and less complex than big cities .So,why offer extra incentives!

A) Only 1 is true B) Only 2 is true
C) Either 1 or 2 is true D) Neither 1 or 2 is true
 
Answer & Explanation Answer: A) Only 1 is true

Explanation:

Government jobs in rural are underlined with several difficulties in love of these .In lieu of these ,extra incentives are needed

Report Error

View Answer Report Error Discuss

Filed Under: Statement and Arguments
Exam Prep: GRE

5 11354
Q:

The value of x satisfying the following relation:

log12x = log23x-2

A) 1/3 B) -1/3
C) 3 D) None of these
 
Answer & Explanation Answer: D) None of these

Explanation:

But at x=-1/3, log x is not defined.

 

The only admissible value of x is 1.

Report Error

View Answer Report Error Discuss

Filed Under: Logarithms
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

16 11351
Q:

There are two mixtures of honey and water in which the ratio of honey and water are as 1:3 and 3:1 respectively. Two litres are drawn from first mixture and 3 litres from second mixture, are mixed to form another mixture. What is the ratio of honey and water in it ?

A) 111:108 B) 11:9
C) 103:72 D) None
 
Answer & Explanation Answer: B) 11:9

Explanation:

From the given data,

 

The part of honey in the first mixture = 1/4

 

The part of honey in the second mixture = 3/4

 

Let the part of honey in the third mixture = x

 

Then,

 

1/4             3/4

 

           x

 

(3/4)-x     x-(1/4) 

 

Given from mixtures 1 & 2 the ratio of mixture taken out is 2 : 3

 

=> 34-xx-14=23

 

=> Solving we get the part of honey in the third mixture as 11/20

 

=> the remaining part of the mixture is water = 9/20

 

Hence, the ratio of the mixture of honey and water in the third mixture is 11 : 9 .

Report Error

View Answer Report Error Discuss

Filed Under: Alligation or Mixture
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

20 11348
Q:

Light : Blind

A) Tongue : Sound B) Voice : Vibration
C) Language : Deaf D) Speech : Dumb
 
Answer & Explanation Answer: D) Speech : Dumb

Explanation:

Here the two pair of words related in such a way that, a blind can't see the light. Similarly, a dumb cannot speech.

 

Hence, Light : Blind :: Speech : Dumb.

Report Error

View Answer Report Error Discuss

Filed Under: Analogy
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

10 11341
Q:

Should school education be made free in India ?

Arguments : 

I. Yes. This is the only way to improve the literacy rate in India.

II. No. It would add the already heavy burden on the exchequer.

A) Only argument I is strong B) Only argument II is strong
C) Neither I nor II is strong D) Both I and II are strong
 
Answer & Explanation Answer: B) Only argument II is strong

Explanation:

Making education free can not ensure full literacy. So argument I is vague. Argument II stands strong.

Report Error

View Answer Report Error Discuss

Filed Under: Statement and Arguments

2 11331
Q:

Which of the following Venn diagrams correctly represents the following classes.

 

Men, Fathers, Doctors

 

 

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: B) 2

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Logical Venn Diagram
Exam Prep: Bank Exams

0 11329
Q:

The average of 26,29,n,35 and 43 lies between 25 and 35. If n is always an integer and greater than the average  of the given integers then the value of n is :

A) 33 B) 34
C) 33 D) None of these
 
Answer & Explanation Answer: C) 33
Explanation:

Average of 26,29,35 and 43 is 33.25 . Also the average of 26 , 29, n, 35 and 43 lies between 25 and 35 i.e,

 25<26+29+n+35+435<35 

=> 125 < 26+29+n+35+43 < 175 

=> 125 < 133 + n < 175

=> n < 42

 Since the value of n is an integer and greater than 33.25 then 33 < n < 42 for every integer n.

Report Error

View Answer Report Error Discuss

Filed Under: Average

9 11306
Q:

From a total of six men and four ladies a committee of three is to be formed. If Mrs. X is not willing to join the committee in which Mr. Y is a member, whereas Mr.Y is willing to join the committee only if Mrs Z is included, how many such committee are possible?

A) 91 B) 104
C) 109 D) 98
 
Answer & Explanation Answer: A) 91

Explanation:

We first count the number of committee in which

(i). Mr. Y is a member
(ii). the ones in which he is not

Case (i): As Mr. Y agrees to be in committee only where Mrs. Z is a member.
Now we are left with (6-1) men and (4-2) ladies (Mrs. X is not willing to join).

We can choose 1 more in5+2C1=7 ways.

Case (ii): If Mr. Y is not a member then we left with (6+4-1) people.
we can select 3 from 9 in 9C3=84 ways.

Thus, total number of ways is 7+84= 91 ways.

Report Error

View Answer Report Error Discuss

Filed Under: Permutations and Combinations

10 11300