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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

A cow s tethered in the middle of a field with a 14feet long rope.If the cow grazes 100 sq feet per day, then approximately what time will be taken by the cow to graze the whole field?

A) 616 B) 716
C) 816 D) 516
 
Answer & Explanation Answer: A) 616

Explanation:

area of the field grazed = (22/7) * 14 * 14 = 616 sq feet

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Q:

Wheels of diameters 7cm and 14cm start rolling simultaneously from x & y which are 1980 cm apart towards each other in opposite directions. Both of them make the same number of revolutions per second. If both of them meet after 10seconds.The speed of the smaller wheel is

A) 22m/s B) 33m/s
C) 44m/s D) 55m/s
 
Answer & Explanation Answer: A) 22m/s

Explanation:

let each wheel make x revolutions per sec. Then2π*72*x+2π*7*x*10=19802*227*72*x+2*227*72*x=198

 66x=198 

distance moved by smaller wheel in 3 revolutions 

=2*227*72*3=66cm 

speed of smaller wheel = 663 m/s = 22m/s

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5 11946
Q:

A square and rectangle have equal areas. If their perimeters are p and q respectively. Then

A) p B) p>q
C) p=q D) none of these
 
Answer & Explanation Answer: A) p
Explanation:

square and a rectangle with equal areas will satisfy the
relation p < q

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5 9586
Q:

The inner circumference of a circular race track, 14m wide is 440m. Find the radius of the outer circle.

A) 84m B) 24m
C) 44m D) 54m
 
Answer & Explanation Answer: A) 84m

Explanation:

let inner radius be r meters. 

2πr=440⇒r=440×744=70mradius of outer circle =70+14m  

 

Therefore, Radius of outer circle = 70 + 14 = 84m

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Q:

The area of a square is 1024 sq.cm. What is the ratio of the length to the breadth of a rectangle whose length is twice the side of the square and breadth is 12 cm less than the side of this square ?

A) 14:9 B) 13:12
C) 16:5 D) 17:13
 
Answer & Explanation Answer: C) 16:5

Explanation:

Area of a square SxS = 1024 => S = 32 cm
Length of the rectangle = 32x2 cm = 64 cm
Breadth of the rectangle = 32 - 12 = 20 cm
Required ratio = 64 : 20 = 16 : 5

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5 9567
Q:

Let A(O,-1), B(0,3) and C(2,1) be three points. Let   △1 be the area of the triangle ABC and △2 be the area of the triangle formed by the mid points of the sides of the triangle whose vertices are A, B and C such that △1=1 ,△2=x Find the value of x .

A) 4 B) 5
C) 2 D) 3
 
Answer & Explanation Answer: D) 3

Explanation:
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5 1228
Q:

The hypotenuse of a right-angled triangle 10 cm and its area is 24 cm^2. If the shorts side is halved and the longer side is double, the new hypotenuse becomes

 

A) √245 cm B) √255 cm
C) √265 cm D) √275 cm
 
Answer & Explanation Answer: C) √265 cm

Explanation:
Hypotenuse = 10cm
Let the other 2 perpendicular sides be a and b
Area ½ a*b = 24
So a*b = 48 cm^2
Also using Pythagoras
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Q:

Find the area (in sq units) enclosed by y = 0, x+6=0 and 2x-3y=6.

A) 9 B) 16
C) 20 D) 27
 
Answer & Explanation Answer: D) 27

Explanation:
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