Aptitude and Reasoning Questions

Q:

An item is sold at a loss of 10%. Had it sold for Rs. 9 more, a profit of 25/2% would have gained. What is the cost price of the item?

A) Rs. 90 B) Rs. 75
C) Rs. 55 D) Rs. 40
 
Answer & Explanation Answer: D) Rs. 40

Explanation:

Let the cost price of the item = Rs. 50

Sold at 10% loss => for Rs. 50 loss  S.P = Rs. 45

From the  given data,

25/2 % gain if it is sold at Rs. 9 more

56.25 - 45 = 9

=> 11.25 = 9

=> 22.5 = 18

=> 45 = 36

=> 50 = ?

=> C.P = 50 x 3645 = 40

 

Hence, the Cost price of the item = Rs. 40.

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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15 10219
Q:

Select from four alternative diagrams, the one that best illustrates the relationship among the three classes  :  Pigeons, Birds, Dogs

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: A) 1

Explanation:

All Pigeons are Birds. But,Dogs are entairly different.

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Filed Under: Logical Venn Diagram

132 10218
Q:

A man goes down stream with a boat to some destination and returns upstream to his original place in 5 hours. If the speed of the boat in still water and the strean are 10km/hr and 14km/hr respectively, the distance of the destination from the string place is 

A) 16 km B) 18 km
C) 21 km D) 25 km
 
Answer & Explanation Answer: C) 21 km

Explanation:

Let the distance covered be D km. 

 D10+4+ D10-4 = 5

 D14+D6=5

 10D = 42 x 5 = 210

 

=> D = 21 km

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT
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32 10209
Q:

A single reservoir supplies the petrol to the whole city, while the reservoir is fed by a single pipeline filling the reservoir with the stream of uniform volume. When the reservoir is full and if 40,000 liters of petrol is used daily, the suply fails in 90 days.If 32,000 liters of petrol is used daily, it fails in 60 days. How much petrol can be used daily with out the supply ever failing? 

A) 64000 liters B) 56000 liters
C) 78000 liters D) 60000 liters
 
Answer & Explanation Answer: B) 56000 liters

Explanation:

Let x liter be the per day filling and v litr be the capacity of the reservoir, then 

      90x + v = 40000 * 90     -----(1)

      60x + v= 32000 * 60     ------(2)

solving eq.(1) and (2) , we get

      x = 56000

Hence , 56000 liters per day can be used without the failure of supply.

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Filed Under: Time and Work

8 10205
Q:

Mr. Gupta borrowed a sum of money on compound interest. What will be the amount to
be repaid if he is repaying the entire amount at the end of 2 years?
I. The rate of interest is 5 p.c.p.a.
II. Simple interest fetched on the same amount in one year is Rs. 600.
III. The amount borrowed is 10 times the simple interest in 2 years.

A) .I only B) III only
C) I or II D) II and Either I or III only
 
Answer & Explanation Answer: D) II and Either I or III only

Explanation:

   I. gives, Rate = 5% p.a.

 

 II. gives, S.I. for 1 year = Rs. 600.

 

III. gives, sum = 10 x (S.I. for 2 years).

 


 Now I, and II give the sum.


 For this sum, C.I. and hence amount can be obtained.


 Thus, III is redundant.


 Again, II gives S.I. for 2 years = Rs. (600 x 2) = Rs. 1200.


 Now, from III, Sum = Rs. (10 x 1200) = Rs . 12000.


Thus,Rate =100*12002*12000 =5%


Thus, C.I. for 2 years and therefore, amount can be obtained.


Thus, I is redundant.



Hence, I or III redundan
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Filed Under: Compound Interest
Exam Prep: Bank Exams
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5 10190
Q:

In how many ways the letters of the word 'DESIGN' can be arranged so that no consonant appears at either of the two ends?

A) 240 B) 72
C) 48 D) 36
 
Answer & Explanation Answer: C) 48

Explanation:

DESIGN = 6 letters

 

No consonants appear at either of the two ends. 

2 x 4P4 =  2 x 4 x 3 x 2 x 1=  48

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Filed Under: Permutations and Combinations
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10 10178
Q:

If you deposit $8000 into an account paying 7% annual interest compounded quarterly, how long until there is $12400 in the account?

A) 2.3 B) 3.3
C) 4.3 D) 6.3
 
Answer & Explanation Answer: D) 6.3

Explanation:

 

 

FV=P(1+r/n)^nt

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Filed Under: Compound Interest
Exam Prep: Bank Exams
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7 10178
Q:

The probability that z lies between 0 and 3.01

A) 0.4987 B) 0.5
C) 0.9987 D) 0.1217
 
Answer & Explanation Answer: A) 0.4987

Explanation:

Probability between z = 0 and z = 3.01 is given by

P(0<z<3.01) = P(z<3.01) - P(z<0)

Reading from the z-table, we have

P(z<0) = 0.5

P(z<3.01) = 0.9987

Hence, P(0<z<3.01) = 0.9987 - 0.5 = 0.4987.

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Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT
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37 10166