Aptitude and Reasoning Questions

Q:

Twenty men can do a work in eighteen days. Eighteen women can complete the same work in fifteen days. What is the ratio between the capacity of a woman and a man ?

A) 4:5 B) 3:4
C) 4:3 D) 2:3
 
Answer & Explanation Answer: C) 4:3

Explanation:

(20 x 18) men can complete the work in in one day.

one man's one day work = 1/360

(18 x 15) women can complete the work in 1 day

1 woman's one day work = 1/270

So, required ratio = 1270:1360= 4:3

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Filed Under: Time and Work
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13 9521
Q:

Two pipes A and B can fill a tank in 15 min and 20 min respectively. Both the pipes are opened together but after 4 min, pipe A is turned off. What is the total time required to fill the tank ?

A) 15 min 20 sec. B) 16 min 40 sec.
C) 13 min 10 sec. D) 14 min 40 sec.
 
Answer & Explanation Answer: D) 14 min 40 sec.

Explanation:

Part filled in 4 minutes = 4(1/15 + 1/20) = 7/15

 

Remaining part = 1 - 7/15 = 8/15

 

Part filled by B in 1 minute = 1/20

 

1/20 : 8/15 :: 1 : k

 

k = (8/15 )x 1 x 20 = 10( 2/3) min = 10 min 40 sec.

 

The tank will be full in (4 min. + 10 min. 40 sec) = 14 min 40 sec.

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Filed Under: Pipes and Cistern
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7 9520
Q:

How many minutes does a watch lose per day, if its hands coincide every 64 minutes ?

A) 36 7/9 min B) 32 8/11 min
C) 34 3/11 min D) 65 5/11 min
 
Answer & Explanation Answer: B) 32 8/11 min

Explanation:

55 min. spaces are covered in 60 min.

60 min. spaces are covered in open parentheses 60 over 55 cross times 60 close parentheses min. = 65 5 over 11 min.

Loss in 64 min. = open parentheses 65 5 over 11 minus 64 close parentheses equals 16 over 11 min.

Loss in 24 hrs = open parentheses 16 over 11 cross times 1 over 64 cross times 24 cross times 60 close parentheses min. = 32 8 over 11 min.

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Filed Under: Clocks
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36 9517
Q:

The number of permutations of the letters of the word 'MESMERISE' is  ?

A) 9!/(2!)^{2}x3! B) 9! x 2! x 3!
C) 0 D) None
 
Answer & Explanation Answer: A) 9!/(2!)^{2}x3!

Explanation:

n items of which p are alike of one kind, q alike of the other, r alike of another kind and the remaining are distinct can be arranged in a row in n!/p!q!r! ways.
The letter pattern 'MESMERISE' consists of 10 letters of which there are 2M's, 3E's, 2S's and 1I and 1R.
Number of arrangements = 9!(2!)2×3!

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Filed Under: Permutations and Combinations
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3 9516
Q:

A jogger running at 9 km/hr along side a railway track is 260 m ahead of the engine of a 140 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger ?

A) 25 sec B) 40 sec
C) 38 sec D) 32 sec
 
Answer & Explanation Answer: B) 40 sec

Explanation:

Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 x 5/18 = 10 m/sec.

Distance to be covered = 260 + 140 = 400 m.

Time taken = 400/10 = 40 sec.

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Filed Under: Problems on Trains
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5 9507
Q:

Amith can row a boat d km upstream and the same distance downstream in 5 hours 15 minutes. Also, he can row the boat 2d km upstream in 7 hours. How long will it take to row the same distance 2d km downstream for Amith ?

A) 4 hrs 10 min B) 3 hrs 15 min
C) 3 hrs 30 min D) 4 hrs 1 min
 
Answer & Explanation Answer: C) 3 hrs 30 min

Explanation:

Let the speed of boat and stream be x and y kmph respectively.

According to question

d/x+y + d/x-y = 5h 15m or 21/4 hrs ......(i)

and 2d/x-y = 7...... (ii)

From eq. (i) and (ii)

2d/x+y = 7/2

Hence, Amith will take to row 2d km distance downstream in 7/2 hrs

= 3.5 hrs

= 3 hrs 30 min.

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Filed Under: Boats and Streams
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16 9497
Q:

A certain amount is divided among P, Q and R in the ratio of 3 : 7 : 6 respectively. If the difference between share of P and Q is Rs. 2700, what is R's share?

A) Rs. 4050 B) Rs. 2121
C) Rs. 5040 D) Rs. 3550
 
Answer & Explanation Answer: A) Rs. 4050

Explanation:

Let the ratio amount be 'p'

7p - 3p = 2700

4p = 2700

p = 675

R's Share = 675 × 6 = Rs. 4050

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Filed Under: Partnership
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14 9494
Q:

The sum of three consecutive odd numbers is 93. What is the middle number?

A) 31 B) 33
C) 29 D) 27
 
Answer & Explanation Answer: A) 31

Explanation:

Let the three consecutive odd numbers be x, x+2, x+4

Then,

x + x + 2 + x + 4 = 93

=> 3x + 6 = 93

=> 3x = 87

=> x = 29 => 29, 31, 33 are three consecutive odd numbers.

 

Therefore, the middle number is 31.

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Filed Under: Numbers
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14 9489