5555+ Aptitude and Reasoning Questions, Answers With Explanation

Q:

Two trains namely X & Y leave station 'A' at 6.30am and 7.40am and travel at 30km/hr and 40 km/hr respectively. How many kms from 'A' will the trains meet ?

A) 140 kms	B) 120 kms
C) 96 kms	D) 142 kms

Answer & Explanation Answer: A) 140 kms

Explanation:

It is given train X leave station A at 6:30 am, here it is asked to calculate the distance from A when the trains meet, the
Distance traveled by train left at 6:30 am upto 7:40 am i.e. in 1 hr. 10 min. or 7/6 hours = 30 x 7/6 = 35 km
So train leaving at 7:40 am will meet first train after covering a distance of 35 km. with relative speed of 40-30=10 km/hr.
Hence time taken = 35/10 = 3.5 hours or 3 hours 30 minutes
So distance from A = Distance traveled by 2nd train in 3 hr. 30 min
= 40 x 3.5 = 140 km.

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO

15 9236

Q:

If $\frac{a}{b} = \frac{4}{5}$ and $\frac{b}{c} = \frac{15}{16}$ , then $\frac{c^{2} - a^{2}}{c^{2} + a^{2}}$ is :

A) 7/5	B) 7/25
C) 7/125	D) 7

Answer & Explanation Answer: B) 7/25

Explanation:

$\frac{a}{b} \times \frac{b}{c} = \frac{4}{5} \times \frac{15}{16} = \frac{3}{4} = \frac{16 - 9}{16 + 9}$

= $\frac{7}{25}$

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Filed Under: Simplification

7 9232

Q:

Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

A) 648	B) 1800
C) 2700	D) 10800

Answer & Explanation Answer: B) 1800

Explanation:

Let the required number of bottles be x.

More machines, More bottles (Direct Proportion)

More minutes, More bottles (Direct Proportion)

$\begin{array}{r} \begin{matrix} m a c h i n e s & 6 : 10 \end{matrix} \\ \begin{matrix} t i m e (i n m i n) & 1 : 4 \end{matrix} \end{array}\} ⋮ ⋮ 270 : x$

=> 6 * 1 * x = 10 * 4 * 270

=> x= 1800

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Filed Under: Chain Rule

3 9231

Q:

Find out the wrong term in the series 3, 4, 10, 32, 136, 685, 4116

A) 4116	B) 685
C) 136	D) 32

Answer & Explanation Answer: D) 32

Explanation:

The correct pattern is *1+1, *2+2, *3+3, *4+4, . . . . .
So,32 is wrong term and must be replaced by (10 * 3 + 3) = 33

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Filed Under: Number Series

20 9228

Q:

There is an empty reservoir whose capacity is 30 litres. There is an inlet pipe which fills at 5 L/min and there is an outlet pipe which empties at 4 L/min. Both the pipes function alternately for 1 minute. Assuming that the inlet pipe is the first one to function, how much time will it take for the reservoir to be filled up to its capacity?

A) 49.5 min	B) 50 min
C) 51 min	D) 52 min

Answer & Explanation Answer: C) 51 min

Explanation:

The work to be done = Capacity of reservoir = 30 litres.

1^st Minute ---> inlet pipe opened ---> 5 lit filled

2^nd minute ---> inlet pipe closed; outlet pipe opened ---> 4 lit emptied

In 2 minutes (5 litres - 4 litres = 1lit) is filled into the reservoir.

It takes 2 minutes to fill 1lit ---> it takes 50 minutes to fill 25 litres into the reservoir.

In the 51^st minute inlet pipe is opened and the reservoir is filled.

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Filed Under: Pipes and Cistern
Exam Prep: CAT
Job Role: Bank PO

24 9223

Q:

Identify the diagram that best represents the relationship among the given classes.

Human, Men, Brothers

A) 1	B) 2
C) 3	D) 4

Answer & Explanation Answer: B) 2

Explanation:

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Filed Under: Logical Venn Diagram
Exam Prep: Bank Exams

2 9220

Q:

A train moving at 2/3 rd of its normal speed reaches its destination 20 minutes late. Find the normal time taken ?

A) 4/3 hrs	B) 2/3 hrs
C) 3/2 hrs	D) 1/4 hrs

Answer & Explanation Answer: B) 2/3 hrs

Explanation:

Let the original speed and time is S and T
then distance = S x T
Now the speed changes to 2/3S and T is T+20
As the distance is same
S x T = 2/3Sx(T+20)
solving this we get t = 40 minutes
=40/60 = 2/3 hour

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

5 9216

Q:

A man sells Rs.5000, 12 % stock at 156 and uinvests the proceeds parity in 8 % stock at 90 and 9 % stock at 108. He hereby increases his income by Rs. 70. How much of the proceeds were invested in each stock?

A) 4000	B) 4200
C) 4002	D) 4020

Answer & Explanation Answer: B) 4200

Explanation:

S.P of Rs. 5000 stock = $R s . (\frac{156}{100} * 5000)$ = Rs. 7800.

Income from this stock = $R s . (\frac{12}{100} * 5000)$ = Rs. 600.

Let investment in 8 % stock be x and that in 9 % stock = (7800 - x).

Therefore,

$(x * \frac{8}{90}) + (7800 - x) * \frac{9}{108} = [600 + 70]$

$\frac{4 x}{45} + \frac{7800 - x}{12} = 670 \Leftrightarrow x = 3600$

Therefore, Money invested in 8 % stock at 90 = Rs. 3600.

Money invested in 9 % at 108 = Rs. (7800-3600) = Rs. 4200.

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Filed Under: Stocks and Shares

14 9215

Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

Why Aptitude and Reasoning Questions?

What type of questions are there in Aptitude and Reasoning tests?

Non Verbal Reasoning

Quantitative Aptitude - Arithmetic Ability

Quantitative Aptitude - Data Interpretation

Verbal Reasoning - Logical Deduction

Verbal Reasoning - Mental Ability

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