Aptitude and Reasoning Questions

For convenience , we assign numbers to each word :

allow  children  to  play  on  the  ground

   1         2      3    4      5    6       7

It has been coded as : 

play  allow  on  children  the  to  ground

  4       1     5        2       6    3      7

------------------------------------------------------------------------

Hence the given code is :

the  do  open  not  electric  touch  wires

 4     1      5     2       6         3       7

Now arranging them as 1 2 3 4 5 6 7, we have "do not touch the open electric wires'.

Hence, option (3) is correct answer. 

6.72/100 = 672/10000 = 42/625

Given Word is PROMISE.

Number of letters in the word PROMISE = 7

Number of ways 7 letters can be arranged = 7! ways

Number of Vowels in word PROMISE = 3 (O, I, E)

Number of ways the vowels can be arranged that 3 Vowels come together = 5! x 3! ways

Now, the number of ways of arrangements so that three vowels should not come together

= 7! - (5! x 3!) ways = 5040 - 720 = 4320.

19th April, 1986 = (1985 years + Period from 1.1.1986 to 19.4.1986)

Odd days in 1600 years = 0

Odd days in 300 years = 1

85 years has 21 leap years + 64 ordinary years.

Number of odd days in 85 years =( 21 x 2 + 64) = 1 odd day.

Jan. Feb. March April

(31 + 28 + 31 + 19) = 109 days

109 days = 15 weeks + 4 days= 4 odd day.

Total number of odd days = (1 + 0 + 1 + 4) = 6.

Given day is Saturday.

Let A be the event of driver A drive safely after consuming liquor. 

Let B be the event of driver B drive safely after consuming liquor. 

Let C be the event of driver C drive safely after consuming liquor. 

P(A)=2/5,P(B)=3/7,P(C)=3/4

The events A, B and C are independent . Therefore,

PA∩B∩C=P(A)P(B)P(C)=25*37*34=970

Therefore, The probability that all the drivers will drive home safely after consuming liquor is 9/70

A : B = 100 : 75

B : C = 100 : 96.

A : C = (A/B*B/C) = (100/75*100/96) = 100/72  =100:72     

   A beats C by (100 - 72) m = 28 m.