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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is :

A) 83 B) 89
C) 85 D) 79
 
Answer & Explanation Answer: C) 85

Explanation:

Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F of 551 and 1073 = 29;
First number = 551/29 = 19
Third number = 1073/29 = 37.
Required sum = 19 + 29 + 37 = 85.

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Filed Under: Problems on Numbers
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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5 6702
Q:

If it is possible to form a word with the first , fourth, seventh and eleventh letters in the word "SUPERFLUOUS" write the first letter of that word. other wise x is the answer.

A) S B) L
C) E D) X
 
Answer & Explanation Answer: B) L

Explanation:

The first, fourth, seventh and eleventh letters of the word 'SUPERFLUOUS' 

The word formed is LESS

Therefore, The first letter is L.

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Filed Under: Alphabet Test

6 6696
Q:

The sum of one-half, one-third and one-fourth of a number exceeds the number by 22. The number is

A) 264 B) 284
C) 215 D) 302
 
Answer & Explanation Answer: A) 264

Explanation:

Let the number be 'x'. Then, from given data

x/2 + x/3 + x/4 = x+22
13x/12 = x+22
x = 264

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Filed Under: Problems on Numbers
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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4 6695
Q:

In a public bathroom there are n taps 1,2,3...n. Tap1 and Tap2 take equal time to fill the tank while Tap3 takes half the time taken by Tap2 and Tap4 takes half the time taken by Tap3. Similarly each next number of tap takes half the time taken by previous number of Tap i.e, K-th Tap takes half the time taken by (K-1)th Tap. If the 10th tap takes 2 hours to fill the tank alone then what is the ratio of  efficiency of 8th tap and 12th tap, respectively?

A) 4:1 B) 5:3
C) 16:1 D) 1:16
 
Answer & Explanation Answer: D) 1:16

Explanation:

Time taken by 8th tap = 2 x 2 x 2= 8 hours

Time taken by 12th tap = 2x (1/2) x (1/2)  = 1/2 hour

Ratio of time taken by 8th tap and 12th tap = 8 : 1/2 =16:1

Therefore, Ratio of efficiencies of 8th tap and 12th tap =1:16

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Filed Under: Time and Work

8 6689
Q:

An electronic device when fed with the numbers, rearranges them in a particular order following certain rules. The following is a step-by-step process of rearrangement for the given input of numbers.

 

Input    :- 85   16   36   04   19   97   63   09

Step I   :- 97   85   16   36   04   19   63   09

Step II  :- 97   85   63   16   36   04   19   09

Step III :- 97   85   63   36   16   04   19   09

Step IV :- 97   85   63   36   19   16   04   09

Step V  :- 97   85   63   36   19   16   09   04

(for the given input step V is the last step).

 

Which of the following will be the last step for the given input ?

Input :- 03   31   43   22   11   09 

A) IV B) V
C) VI D) None of these
 
Answer & Explanation Answer: B) V

Explanation:

Clearly, in the given arrangement, the numbers have been arranged in descending order in a sequence, altering the position of only one number in each step

Input       : 03   31   43   22   11   09

Step I      : 43   03   31   22   11   09
Step II     : 43   31   03   22   11   09
Step III   : 43   31   22   03   11   09
Step IV   : 43   31   22   11   03   09
Step V    : 43   31   22   11   09   03

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Filed Under: Sequential Output Tracing

17 6668
Q:

The arithmetic mean of the following numbers 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6 and 7, 7, 7, 7, 7, 7, 7 is   ?

A) 6 B) 9
C) 7 D) 5
 
Answer & Explanation Answer: D) 5

Explanation:

Arithmatic mean = sum/members 

=> (1x1 + 2x2 + 3x3 + 4x4 + 5x5 + 6x6 + 7x7) / (1 + 2 + 3 + 4 + 5 + 6 + 7)

=> 140/28 = 5

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Filed Under: Arithmetical Reasoning
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4 6666
Q:

When six fairs coins are tossed simultaneously, in how many of the outcomes will at most three of the coins turn up as heads ?

A) 15 B) 42
C) 16 D) 40
 
Answer & Explanation Answer: B) 42

Explanation:

The question requires you to find number of the outcomes in which at most 3 coins turn up as heads.

i.e., 0 coins turn heads or 1 coin turns head or 2 coins turn heads or 3 coins turn heads.

 

The number of outcomes in which 0 coins turn heads is 6C0=1 

The number of outcomes in which 1 coin turns head is =6C1=6 

The number of outcomes in which 2 coins turn heads is6C2=15 

The number of outcomes in which 3 coins turn heads is6C3=20

 

Therefore, total number of outcomes =1+6+15+20= 42 outcomes

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Filed Under: Permutations and Combinations

3 6666
Q:

The length of a brigade which a train 130 m long and traveling at 45kmph can cross in 30 seconds, is 

A) 196 mts B) 220 mts
C) 230 mts D) 245 mts
 
Answer & Explanation Answer: D) 245 mts

Explanation:

Let the length of the brigade is x mts
Then Distance = 130 + x mts
given speed = 45 kmph = 45 x5/18 m/s
Time = 30 sec
T = D/S
=> 30 = 130+x/(45x5/18)
=> x = 245 mts.

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Filed Under: Problems on Trains
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5 6661