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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to ?

A) 13/125 B) 14/57
C) 11/120 D) 16/41
 
Answer & Explanation Answer: C) 11/120

Explanation:

Let the numbers be a and b.
We know that product of two numbers = Product of their HCF and LCM
Then, a + b = 55 and ab = 5 x 120 = 600.
=> The required sum = (1/a) + (1/b) = (a+b)/ab
=55/600 = 11/120

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Filed Under: HCF and LCM
Exam Prep: AIEEE , Bank Exams , CAT
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23 7048
Q:

Ishikha got married 9 years ago. Today her age is 4/3 times her age at the time of marriage. At present her daughter’s age is one-sixth of her age. What was her daughter’s age three years ago?

A) 4 years B) 3 years
C) 2 years D) 1 year
 
Answer & Explanation Answer: B) 3 years

Explanation:

Let Ishika and her daughter present ages be p and q

 From the given data, 

p = 4/3(p - 9)

 => p = 36 years 

Hence, Ishika's present age = 36 years and

Her daughter's present age = 1/6 x 36 = 6 years 

Now, required her daughter’s age three years ago = 6 - 3 = 3 years.

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Filed Under: Problems on Ages
Exam Prep: GATE , CAT , Bank Exams , AIEEE
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13 7043
Q:

In the last month the company decided to increase the cost of its mixer by 10 percent. What is the present price of the mixer? 

I. The cost of mixer and juicer together was Rs 2850 a month ago. 

II. The amount of 10% increase on the mixer comes to Rs 220. 

A) If the data in statement I alone are sufficient to answer the question B) If the data in statement II alone are sufficient answer the question
C) If the data either in I or II alone are sufficient to answer the question; D) If the data even in both the statements together are not sufficient to answer the question
 
Answer & Explanation Answer: B) If the data in statement II alone are sufficient answer the question

Explanation:

The present price of the mixer can he calculated from statement II as follows

Let the earlier price be Rs x.

Then, 10% of x = 220 or x = 2200. Present price = Rs (2200 + 220) = Rs 2420.

So, only II is needed. 

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Filed Under: Data Sufficiency

5 7043
Q:

The 'M' Cooperative housing society has put up a notice at its gate that sales persons are not allowed inside the society

Assumptions: 

1. All the sales persons stay away from 'M' Cooperation society

2. The security guard posted at the gate may be able to stop the sales persons entering the society

A) Only 1 is true B) Only 2 is true
C) Either 1 or 2 is true D) Both 1 and 2 follow
 
Answer & Explanation Answer: D) Both 1 and 2 follow

Explanation:

Since both the assumptions follow from the given statement,So both 1 and 2 are implicit

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Filed Under: Statement and Assumptions
Exam Prep: GRE

6 7042
Q:

In a class of 80 students and 5 teachers, each student got sweets that are 15% of the total number of students and each teacher got sweets that are 25% of the total number of students. How many sweets were there?

A) 1060 B) 960
C) 860 D) 760
 
Answer & Explanation Answer: A) 1060

Explanation:

From the given data,

80 x 15/100 of 80 + 5 x 80 x 25/100

= 960 + 100

= 1060.

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT
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9 7040
Q:

Choose the missing terms out of the given alternatives ADVENTURE,DVENTURE, DVENTUR, ? , VENTU

A) VENTURE B) VENTUR
C) DVENT D) DVENTU
 
Answer & Explanation Answer: B) VENTUR

Explanation:

one of the letter from beginning and one of the letter from the end of a term are removed, one by one, alternate steps

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Filed Under: Number Series

22 7037
Q:

What is the value of 4 in 475?

A) 4 B) 400
C) 475 D) 40
 
Answer & Explanation Answer: B) 400

Explanation:

The value of 4 in 475 means the place value of 4 in 475 and not its face value. Face value means the digit itself though it is at any place in the given number. But place value means the value of digit in its place in the given number.

 

Here the place value of 4 in 475 can be determined by as 4 is in 100's place in 475.

Hence, the place value of 4 in 475 is 4x100 = 400.

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Filed Under: Numbers
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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11 7035
Q:

Four subjects — Physics, Chemistry, Mathematics and Biology were taught in four consecutive periods of one hour each starting from 8.00 a.m. At what time was the Chemistry period scheduled ?  

I. Mathematics period ended at 10.00 a.m. which was preceded by Biology. 

II. Physics was scheduled in the last period. 

III. Mathematics period was immediately followed by Chemistry. 

A) Only I B) Only I or Only II
C) Only II D) I and II together or I and III together
 
Answer & Explanation Answer: D) I and II together or I and III together

Explanation:

From I and II. we conclude that Mathematics period began at 9.00 a.m., Biology period began at 8.00 a.m. and Physics period began at 11 a.m. So. the Chemistry period began at 10.00 a.m. From I and III, we conclude that Mathematics period ended and Chemistry period began at 10.00 a.m.  

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Filed Under: Data Sufficiency

5 7031