Aptitude and Reasoning Questions

Let the number of Rose plants be ‘a’.
Let number of marigold plants be ‘b’.
Let the number of Sunflower plants be ‘c’.
20a+5b+1c=1000; a+b+c=100

Solving the above two equations by eliminating c,
19a+4b=900

b = (900-19a)/4 

b = 225 - 19a/4----------(1)

b being the number of plants, is a positive integer, and is less than 99, as each of the other two types have at least one plant in the combination i.e .:0 < b < 99--------(2)

Substituting (1) in (2),

 0 < 225 - 19a/4 < 99

225 <  -19a/4 < (99 -225)

=> 4 x 225 > 19a > 126 x 4

=> 900/19 > a > 505

a is the integer between 47 and 27 ----------(3)
From (1), it is clear, a should be multiple of 4.

Hence possible values of a are (28,32,36,40,44)

For a=28 and 32, a+b>100
For all other values of a, we get the desired solution:
a=36,b=54,c=10
a=40,b=35,c=25
a=44,b=16,c=40

Three solutions are possible.

Exact interest, I= prt = $8000 × 0.085 × 90/365 = 167.67

Ordinary Interest, I= Prt = $8000 x 0.085 x 90/360 = 170

As given, we have:

Susmitha > Laxmi > Ramya; Ramya = Hema, Ramya > Avanthi

Thus the sequence of heights becomes:

Susmitha > Laxmi > Ramya = Hema > Avanthi

Clearly, Hema is shorter than Laxmi.

If there are x girls, then
x + 15x = 1200
16x = 1200
x= 1200/16 = 75

Let the length of the brigade is x mts
Then Distance = 130 + x mts
given speed = 45 kmph = 45 x5/18 m/s
Time = 30 sec
T = D/S
=> 30 = 130+x/(45x5/18)
=> x = 245 mts.

 The letters in the first row follow the sequence +5, +7.

The letters in the second row follow the sequence +6, +8.
In the third row, the first letter G moves 7 steps forward to give the second letter N.
Clearly, the missing letter will be 9 steps ahead of N i.e. W.

Suppose A, B and C take x, x/2 and x/3 respectively to finish the work. 

Then, (1/x + 2/x + 3/x) = 1/2 

=> 6/x = 1/2      => x = 12 

So, B takes 6 hours to finish the work.

Let the lent at 5% be 'A'

(A x 5 x 1)/100 + [(1500 - A)x 6 x 1]/100 = 85

5A/100 + 90 – 6A/100 = 85

A/100 = 5

=> A = 500