5555+ Aptitude and Reasoning Questions, Answers With Explanation

Q:

The following bar graph indicates the production of sugar (in lakh tonnes) by three different sugar companies P, Q and R over years 2009 to 2013.

Production of Sugar by Companies P, Q and R during 2009 - 2013

1. The percentage increase in production of Company Q from the year 2009 to the year 2013 is :

1. 80% 2. 90% 3. 60% 4. 100%

2. The average production over the years 2009 - 2013 was maximum for the Company(ies):

1. Q 2. P 3. R 4. P and R

3. The percentage rise or fall in production of Company Q as compared to the previous year is the maximum in the year :

1. 2011 2. 2010 3. 2013 4. 2012

4. The percentage of production of Company R to Production of Company Q is the maximum in the year

1. 2010 2. 2009 3. 2011 4. None of these

5. The ratio of the average production of Company P during the years 2011 to 2013 to the average production of Company Q for the same period is :

1. 23 : 25 2. 27 : 29 3. 15 : 17 4. 9 : 11

Answer

1. Answer : 4

Explanation : Required Percentage = $\frac{100 - 50}{50} \times 100$ = 100%

2. Answer : 4

Explanation : The average production of P = $\frac{60 + 90 + 50 + 100 + 80}{5}$ = 76

The average production of Q = $\frac{50 + 70 + 70 + 80 + 100}{5}$ = 74

The average production of R = $\frac{70 + 80 + 90 + 70 + 70}{5}$ = 76

Maximum average production = P and R both

3. Answer : 2

Explanation : The percentage rise in 2010 = $\frac{70 - 50}{50} \times 100$ = 40%

The percentage rise in 2011 = $\frac{70 - 70}{70} \times 100$ = 0%

The percentage rise in 2012 = $\frac{80 - 70}{70} \times 100$ = 14.28%

The percentage rise in 2013 = $\frac{100 - 80}{80} \times 100$ =25%

4. Answer : 2

Explanation : The percentage of production of Company R to production of Company Q

in 2009 = $\frac{70}{50} \times 100$ = 140

in 2010 = $\frac{80}{70} \times 100$ = 114.28

in 2011 = $\frac{90}{70} \times 100$ = 128.57

in 2012 = $\frac{70}{80} \times 100$ = 87.5

in 2013 = $\frac{70}{100} \times 100$ = 70

5. Answer : 1

Explanation : Average production of company P during the years 2011 to 2013 = $\frac{50 + 100 + 80}{3}$ = $\frac{230}{3}$

Average production of company Q during the years 2011 to 2013 = $\frac{70 + 80 + 100}{3}$ = $\frac{250}{3}$

Required ratio = 23 : 25

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Subject: Bar Charts

14 6721

Q:

In a certain code language, "GOAT" is written as "45" and "COAT" is written as "41". How is "BOAT" written in that code language?

A) 40	B) 41
C) 42	D) 43

Answer & Explanation Answer: A) 40

Explanation:

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Filed Under: Coding and Decoding

15 6720

Q:

A sales boy is allowed $4 \frac{1}{2}$ % discount on the total sales made by him plus a bonus of $\frac{1}{4}$ % on the sales over Rs.12,000.If his total earnings were Rs.2400, then his total sales(in Rs.) are ?

A) Rs.60,145.23	B) Rs.54,285.54
C) Rs.52,147.85	D) Rs.50,589.47

Answer & Explanation Answer: D) Rs.50,589.47

Explanation:

Let the total earnings be Rs.x

Then $4 \frac{1}{2}$ % of x + $\frac{1}{4}$ % of (x-12000) =2400

$\Rightarrow \frac{9}{2} \times \frac{x}{100} + \frac{1}{4} \times \frac{x - 12000}{100} = 2400$

=> x=50,589.47

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Filed Under: Percentage
Exam Prep: CAT
Job Role: Bank Clerk

8 6716

Q:

In how many ways can 5 different toys be packed in 3 identical boxes such that no box is empty, if any of the boxes may hold all of the toys?

A) 15	B) 10
C) 25	D) 20

Answer & Explanation Answer: C) 25

Explanation:

The toys are different; The boxes are identical
If none of the boxes is to remain empty, then we can pack the toys in one of the following ways
a. 2,2,1
b. 3,1,1

Case a. Number of ways of achieving the first option 2−2–1

Two toys out of the 5 can be selected in $5 C_{2}$ 5 ways. Another 2 out of the remaining 3 can be selected in $3 C_{2}$ ways and the last toy can be selected in $1 C_{1}$ way.

However, as the boxes are identical, the two different ways of selecting which box holds the first two toys and which one holds the second set of two toys will look the same. Hence, we need to divide the result by 2.

Therefore, total number of ways of achieving the 2−2–1 option is:

$\frac{5 C_{2} * 3 C_{2}}{2} = \frac{10 * 3}{2} = 15$ ways.

Case b. Number of ways of achieving the second option 3−1–1

Three toys out of the 5 can be selected in $5 C_{3}$ ways. As the boxes are identical, the remaining two toys can go into the two identical looking boxes in only one way.
Therefore, total number of ways of getting the 3−1–1 option is $5 C_{3}$ =10 ways.

Total ways in which the 5 toys can be packed in 3 identical boxes
=number of ways of achieving Case a + number of ways of achieving Case b
=15 + 10 = 25 ways

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Filed Under: Permutations and Combinations

0 6714

Q:

The average age of seven persons sitting in a row facing east is 26 years. If the average age of the first three persons is 19 years and the average age of the last three persons is 32 years, then find the age of the person sitting in the middle of the row ?

A) 32 yrs	B) 29 yrs
C) 24 yrs	D) 27 yrs

Answer & Explanation Answer: B) 29 yrs

Explanation:

Total age seven persons = (26 x 7)years
Total age of the first three persons and the last three persons are (19 x 3) years and (32 x 3) years respectively.
Age of the person sitting in the middle of the row = 26 x 7 - 19 x 3 - 32 x 3 = 182 - 57 - 96 = 29 years.

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

5 6709

Q:

When Ankith saw Sanvi, he recalled, " She is the daughter of the father of my daughter's mother." Who is Sanvi to Ankit ?

A) sister	B) daughter-in-law
C) sister-in-law	D) cousin

Answer & Explanation Answer: C) sister-in-law

Explanation:

Ankit's daughter's mother---Ankit's wife; Ankit's wife's father---Ankit's father-in-law;
Father-in-law's daughter--- Ankit's sister-in-law. So, Sanvi is sister-in-law of Ankit.

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Filed Under: Blood Relations
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE , TOEFL
Job Role: Analyst , Bank Clerk , Bank PO

6 6708

Q:

If sum of three consecutive numbers is 42 . What will the sum of the digits of middle number .

Answer

Let the numbers be x, x+1, x+2

Then x + x+1 + x+2 = 42

=> 3x + 3 = 42

=> 3x = 39

=> x = 13

The numbers would be 13, 14, 15

Therefore, Sum of the digits of middle number = 1+4 = 5

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Subject: Problems on Numbers

8 6707

Q:

A 260 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train ?

A) 240 mts	B) 270 mts
C) 260 mts	D) 250 mts

Answer & Explanation Answer: A) 240 mts

Explanation:

Relative speed = 120 + 80 = 200 km/hr.
= 200 x 5/18 = 500/9 m/sec.

Let the length of the other train be L mts.
Then, (L + 260)/9 = 500/9 => L = 240 mts.

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

3 6706

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