Aptitude and Reasoning Questions

In the given series

1st term has odd number starting from 11, So the Series is 11, 13, 15, 17, 19 

2nd term has an alphabet follwed by its alpha numeric number in the order +4, +3, +2, +1. So  the Series is M13, Q17, T20, V22, W23

Therefore, 15T20 is the answer.

The first letter moves two steps forward. The last letter moves one steps backward. The number series runs as follows :
1 x 1 + 1 = 2
2 x 2 + 2 = 6
6 x 3 + 3 = 21
21 x 4 + 4 = 88.

Let the distance be 'd' kms.

According to the given data,

$$\begin{gathered} d30 - d50 = 4060 hrs \\ => 6d = 300 \\ => d = 50 kms. \\ \end{gathered}$$

Let the total number of pages in the book be 'x'.

From given data,

2x/5 + 34x/100 + 52 + 52 = x

 => 40x + 34x + 10400 = 100x

 => 26x = 10400

 => x = 400.

 Hence, total pages in the book are 400.

Putting A=1, B=2, C=3,..., M=13,....,X=24,Y=25, Z=26, we have :

 JR = J + R2 + 2 = 10 + 18 2 + 2 = 16

CK = C + K2 + 2 = 3 + 112 + 2 = 9

TX = T + X2+ 2 = 20 + 242 + 2 = 24

OS = O + S2 + 2 = 15 + 192 + 2 = 19

 So, the missing numbers are :

21 and 14

Hence, the answer is (b).

SP of first article = 1000

Profit = 20%

CP = 100100+P×SP= 5000/6 = 2500/3

SP of second article = 1000

Loss = 20%

CP = 100100-L×SP= 5000/4 = 1250

Total SP = 2000

Total CP = 25003+ 1250 = 6250/3

CP is more than SP, he makes a loss.

Loss = CP-SP = (6250/3)- 2000 = 250/3

Loss Percent =250362503×100= 4%

Given that, upstream distance = 7 kms

Upstream speed = 7/42 x 60 = 10 kms

Speed of the stream = 3 kmph

Let speed in still water = M kmph, then

Upstream speed = M - 3 = 10

=> M = 13 kmph.