Aptitude and Reasoning Questions

Q:

Karthik walks at 5 km/hr and reaches his destination 8 min late. If he walks at 6 km/hr, he reaches his destination on time. What distance he will cover in given time ?

A) 10 kms B) 8 kms
C) 6 kms D) 4 kms
 
Answer & Explanation Answer: D) 4 kms

Explanation:

Let the actual distance be t kms

Now, According to the data,

 

5t + 860 = 6t=> 560t + 860 = 6t=> 60t + 8 = 72t=> 8 = 12t=> t = 8/12 = 2/3 hrs

 

Now, the total distance = 6t = 6 x 2/3 = 2 x 2 = 4 kms.

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Q:

If a girl cycles at 10 kmph, then she arrives at a certain place at 1 p.m. If she cycles at 15 kmph, she will arrive at the same place at 11 a.m. At what speed must she cycle to get there at noon?

A) 14 kmph B) 13 kmph
C) 12 kmph D) 11 kmph
 
Answer & Explanation Answer: C) 12 kmph

Explanation:

The distance is constant in this case.

Let the time taken for travel with a speed of 10 kmph be 't'.

Now the speed of 15 kmph is 3/2 times the speed of 10 kmph.

Therefore, time taken with the speed of 15 kmph will be 2t/3 (speed is inversely proportional to time)

Extra time taken = t - 2t/3 = t/3

=> 1pm - 11am = 2hrs

=> t/3 = 2h

=> t = 6 hrs.

Now, Distance = speed x time = 10 x 6 = 60 kms

Time he takes to reach at noon = 6 - 1 = 5 hrs

Now, Speed = 60/5 = 12 kmph.

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12 5715
Q:

If the average height of boys in a hall is 180 cm and that of girls is 150 cm. If the average height of the gathering is 165 cm, then find the number of girls present in the hall if the number of boys present in the hall are 78 ?

A) 56 B) 64
C) 87 D) 78
 
Answer & Explanation Answer: D) 78

Explanation:

Using Trial and error method,

we get the number of girls in the hall = 78

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27 5711
Q:

If the positions of the first and the fifth digits of the number 14278359 are interchanged, similarly the positions of the second and the sixth digits are interchanged and so on, then which of the following will be the second digit from the right end after the rearrangement ?

A) 5 B) 2
C) 7 D) 4
 
Answer & Explanation Answer: B) 2

Explanation:

Given number is 14278359
As given 1st and 5th digits, 2nd & 6th, 3rd & 7th and 4th & 8th digits are to to be interchanged.
Therfore, the rearranged number is 83591427
Then, the second digit from the right end is 2.

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8 5707
Q:

Sponge is to Porous as Rubber is to

A) Inflexible B) Elastic
C) Solid D) Massive
 
Answer & Explanation Answer: B) Elastic

Explanation:

A sponge is a porous material. Rubber is an elastic material. 

Since Rubber is not a Massive or solid and not an inflexible thing, it is elastic. 

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3 5703
Q:

The ratio of the speeds of a car, a jeeps and a tractor is 3 : 5 : 2. The speed of the jeep is 250 per cent of the speed of the tractor and tractor covers 360 km in 12 hours. What is the average speed of car and jeep together?

A) 50 kmph B) 60 kmph
C) 70 kmph D) 80 kmph
 
Answer & Explanation Answer: B) 60 kmph

Explanation:

Speed of tractor = 360/12 = 30 kmph

Speed of jeep = 250 x 30/100 = 75 kmph

But, given ratio of speed of car, jeep and tractor is 3 : 5 : 2

Speed of car = 3 x 75/5 = 45 kmph

 

Required, average speed of car and jeep = 75 + 45/2 = 60 kmph.

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15 5700
Q:

If it is possible to make a number which is the square of a two-digit odd number using the second, the fourth and the sixth digits of the number  93217648 and using each only once, which of the following is that two-digit odd number?

A) 17 B) 19
C) 15 D) 21
 
Answer & Explanation Answer: B) 19

Explanation:

Second, fourth and the sixth digits of the number are 3, 1 and 6. Using these digits only once we can make 361, which is a perfect square number. Hence, our answer is 19 x 19 = 361

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9 5698
Q:

In what ratio must a merchant mix two varieties of oils worth Rs. 60/kg and Rs. 65/kg, so that by selling the mixture at Rs. 68.20/kg, he may gain 10% ?

A) 2:3 B) 4:3
C) 3:4 D) 3:2
 
Answer & Explanation Answer: D) 3:2

Explanation:

Let he mixes the oils in the ratio = x : y

Then, the cost price of the oils = 60x + 65y

Given selling price = Rs. 68.20

=> Selling price = 68.20(x+y)

Given profit = 10% = SP - CP

=> 10/100 (60x + 65y) = 68.20(x+y)-(60x + 65y)

=> 6x + 6.5y = 8.20x + 3.20y

=>2.2x = 3.3y

=> x : y = 3 : 2

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Filed Under: Alligation or Mixture
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