Aptitude and Reasoning Questions

Q:

O and O' are the center of the two circles with radii 7cm and 9cm respectively. The distance between the centers is 20cm. If PQ be the transverse common tangent to the circles, which cuts OO' at X, what is the length of O'X in cm ?

A) 10 B) 6
C) 35/4 D) 45/4
 
Answer & Explanation Answer: D) 45/4

Explanation:

As clear from the figure itself, triangle OQX and triangle O'PX are similar.

So,

OQ/O'P = OX/O'X

=> OX = (7/9)xO'X

And since, OX + O'X = 20

=> (7/9)xO'X + O'X = 20

=> O'X = 45/4

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Filed Under: Arithmetical Reasoning
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Q:

Aadi can do a piece of work in 12 days alone, Bunny can do the same work in 16 days alone. After Aadi has been working for 5 days and Bunny for 7 days, Charan finishes it in 14 days. In how many days will Charan alone be able to do the work?

A) 96 days B) 48 days
C) 24 days D) 12 days
 
Answer & Explanation Answer: A) 96 days

Explanation:

Let number of days Charan can do the same work alone is 'd' days.

According to the given data,

512 + 716 + 14d = 114d = 1 - 20 + 214814d = 48 - 4148d = 14 x 487d = 96 days

 

Therefore, Charan alone can complete the work in 96 days.

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Filed Under: Time and Work
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Q:

A Bus is running at 9/10 of its own speed reached a place in 22 hours. How much time could be saved if the bus would run at its own speed ?

A) 1.5 hrs B) 1.7 hrs
C) 2.2 hrs D) 3.5 hrs
 
Answer & Explanation Answer: C) 2.2 hrs

Explanation:

Let the original Speed be "s" kmph
And the usual time be "t" hrs
Given that if the bus is running at 9s/10 kmph the time is 22 hrs
=> [9s/10] x 22 = t x s
=> 99/5 = t
=> t = 19.8 hrs

 

Hence, if bus runs at its own speed, the time saved = 22 - 19.8 = 2.2 hrs.

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Filed Under: Time and Distance
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Q:

There are two examinations rooms P and Q. If 10 students are sent from P to Q, then the number of students in each room is the same. If 20 candidates are sent from Q to P, then the number of students in P is double the number of students in Q. The number of students in room Q is ?

A) 100 B) 70
C) 120 D) 80
 
Answer & Explanation Answer: D) 80

Explanation:

If 'k' is number of students in P and 'l' is number of students in Q, then
From the given conditions, we have
=> k - 10 = l + 10 .......(1)
=> k + 20 = 2(l - 20) ....(2)

Solving these eqns, we get
k = 100 and l = 80.
Therefore, number of students in class Q is 80.

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Q:

In a certain code language, "STUBBORN" is written as "VUTAAOSP". How is "SHIPPING" written in that code language?

A) TIJOOHPJ B) QFOLLSLO
C) TIJNNOJH D) JITOOHOJ
 
Answer & Explanation Answer: D) JITOOHOJ

Explanation:
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Q:

112 × 54 =

A) 68947 B) 69874
C) 70000 D) 76000
 
Answer & Explanation Answer: C) 70000

Explanation:

112 × 54112 × 1024= 112 × 1000024= 1120000/16

= 70,000.

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Filed Under: Simplification
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Q:

A piece of paper is folded and punched as shown. Indicate how it is when opened?

 

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: A) 1

Explanation:
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Filed Under: Paper Folding
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Q:

Present ages of Deepa and Hyma are in the ratio of 5:6 respectively. After four years, this ratio becomes 6: 7. What is the difference between their present ages?

A) 6 yrs B) 4 yrs
C) 8 yrs D) 2 yrs
 
Answer & Explanation Answer: B) 4 yrs

Explanation:

Let the present age of Deepa = 5p

Let the present age of Hyma = 6p

After four years their ratio = 6 : 7

=> 5p + 46p + 4 = 67

=> 35p + 28 = 36p + 24

=> p = 4

Therefore, the difference between their ages = 24 - 20 = 4 years.

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Filed Under: Problems on Ages
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