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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

Determine the total number of five-card hands that can be drawn from a deck of 52 cards.

A) 2589860 B) 2598970
C) 2598960 D) 2430803
 
Answer & Explanation Answer: C) 2598960

Explanation:

When a hand of cards is dealt, the order of the cards does not matter. If you are dealt two kings, it does not matter if the two kings came with the first two cards or the last two cards. Thus cards are combinations. There are 52 cards in a deck and we want to know how many different ways we can put them in groups of five at a time when order does not matter. The combination formula is used.

C(52,5) = 2,598,960

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Filed Under: Permutations and Combinations

1 5218
Q:

Lasya alone can do a work in 16 days. Srimukhi’s efficiency is 20 % lesser than that of Laya. If Rashmi and Srimukhi together can do the same work in 12 days, then find the efficiency ratio of Rashmi to that of Lasya?

A) 19 : 7 B) 30 : 19
C) 8 : 15 D) 31 : 17
 
Answer & Explanation Answer: C) 8 : 15

Explanation:

Given Lasya can do a work in 16 days.

 

Now, time taken by Srimukhi alone to complete the work = 16 x 100/80

 

Time taken by Rashmi = n days

 

=> (12 x 20)/(20 - 12) = (12 x 20)/n

 

=> n= 30 days.

 

Required ratio of efficiencies of Rashmi and Lasya = 1/30  ::  1/16  = 8 : 15.

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Filed Under: Time and Work
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

7 5215
Q:

Marked price of an article is 1600 Rs. more than the cost price. When the same article is sold at a discount of Rs. 500 then the percent profit earned is 25%. For earning a profit of 30%, the article should be sold at what price?

A) 5740 B) 5720
C) 5620 D) 5730
 
Answer & Explanation Answer: B) 5720

Explanation:

Ans. B.
According to the question ,
Marked Price = 1600 + Cost price - (i)
MP – 500 = 125/100 * CP - (ii)
MP = 5/4 CP + 500 - (ii)
4MP = 5CP + 2000 -(ii)
Solving (i) and (ii)
Cost Price = 4400
Now , the selling price
= 130/100 * 4400
= 5720

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , GATE

1 5212
Q:

Spelling test - find correct spelling :

A) Skillfull B) Skillfful
C) Skillful D) Skkillful
 
Answer & Explanation Answer: C) Skillful

Explanation:
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Filed Under: Alphabet Test
Exam Prep: AIEEE , Bank Exams , CAT , GRE , TOEFL
Job Role: Bank Clerk

7 5212
Q:

If a cellphone is purchased for Rs.490 and sold for Rs.465.50 find the loss percentage?

A) 10 B) 5
C) 20 D) 15
 
Answer & Explanation Answer: B) 5

Explanation:

loss = C.P - S.P = 490 - 465.50 =24.50 

loss % = (loss x 100)/C.P = (24.50 x 100)/490 = 5%

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Filed Under: True Discount

4 5212
Q:

The calendar for the year 2007 will be the same for the year ?

A) 2014 B) 2019
C) 2021 D) 2018
 
Answer & Explanation Answer: D) 2018

Explanation:

Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.

Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017
Odd day : 1 2 1 1 1 2 1 1 1 2 1

Sum = 14 odd days => 0 odd days.
Calendar for the year 2018 will be the same as for the year 2007.

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Filed Under: Calendar
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO

14 5205
Q:

The Highway police authority put up large boards at regular intervals indicating the speed limit and dangers of over-speeding on the highways.

Assumptions: 

I. Most of the motorists may drive their vehicles within the speed limit on the highways.

II. Motorists generally ignore such cautions and over-speed on the highways.

A) If only assumption I is Implicit B) If only assumption II is Implicit
C) If either I or II is Implicit D) If both I and II are Implicit
 
Answer & Explanation Answer: A) If only assumption I is Implicit

Explanation:

The boards have been put with the assumption that they may have a positive impact.

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Filed Under: Statement and Assumptions

7 5201
Q:

Chennai express left Hyderabad for Chennai at 14 : 30 hours, travelling at a speed of 60 kmph and Charminar Express left Hyderabad for Chennai on the same day at 16 : 30 hours, travelling at a speed of 80 kmph. How far away from Hyderabad will the two trains meet? 

A) 360 kms B) 480 kms
C) 520 kms D) 240 kms
 
Answer & Explanation Answer: B) 480 kms

Explanation:

Now, the distance covered by Chennai express in 2 hrs = 60 x 2 = 120 kms

Let the Charminar Express takes 't' hrs to catch Chennai express

=> 80 x t = 60 x (2 + t)

=> 80 t = 120 + 60t

=> t = 6 hrs

 

Therefore, the distance away from Hyderabad the two trains meet = 80 x 6 = 480 kms.

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Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

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