Aptitude and Reasoning Questions

Q:

Equal distance is covered by a boat in upstream and in downstream in total 5 hours. Sum of speed of a boat in upstream and downstream is 40 km/hr. Speed of boat in still water is 600%
more than the speed of stream. Find theapproximate distance covered by boat in downstream (in km).

A) 45 B) 50
C) 55 D) 60
 
Answer & Explanation Answer: B) 50

Explanation:

let speed of boat= X, speed of stream= Y
Upstream speed= X-Y
Downstream speed= X+Y
Sum of upstream & downstream= (X-Y) +(X+Y)= 2X
So, 2X= 40
X= 20 km/hr
Speed of boat : speed of stream= 600+100 :100= 7:1
So speed of Stream= 20/7 km/hr
ATQ, D/( X-Y) + D/( X+Y) = 5
D/(120/7) + D/(160/7)= 5
D= 480×5/49= 48.97 km= 50 Km(approx)

Report Error

View Answer Report Error Discuss

Filed Under: Boats and Streams
Exam Prep: Bank Exams , GATE

9 4617
Q:

Two parallel chords on the same side of the centre of a circle are 5 cm apart. If the chords are 20 and 28 cm long, what is the radius of the circle? 

A) 14.69 cm B) 15.69 cm
C) 18.65 cm D) 16.42 cm
 
Answer & Explanation Answer: B) 15.69 cm

Explanation:

circle11487663359.jpg image

Draw the two chords as shown in the figure. Let O be the center of the circle. Draw OC
perpendicular to both chords. That divides the two chords in half.
So CD = 10 and AB = 14. Draw radii OA and OD, both equal to radius r.
We are given that BC = 5, the distance between the two chords. Let
OB = x.

We use the Pythagorean theorem on right triangle ABO

AO² = AB² + OB²
r² = 14² + x²

We use the Pythagorean theorem on right triangle DCO

DO² = CD² + OC²

We see that OC = OB+BC = x+5, so

r² = 10² + (x+5)²

So we have a system of two equations:

r² = 14² + x²
r² = 10² + (x+5)²

Since both left sides equal r², set the right sides
equal to each other.

14² + x² = 10² + (x+5)²
196 + x² = 100 + x² + 10x + 25
196 = 125 + 10x
71 = 10x
7.1 = x

r² = 14² + x²
r² = 196 + (7.1)²
r² = 196 + 50.41
r² = 246.41
r = √246.41
r = 15.69745202 cm

Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

4 4616
Q:

A man travels 480 km in 4 hours, partly by air and partly by train. If he had travelled all the way by air, he would have saved 4/5 of the time he would have taken to travel by train and would have arrived at his destination 2 hours early. Find the distance he covered by travelling by train.

A) 80 km B) 120 km
C) 110 km D) 90 km
 
Answer & Explanation Answer: B) 120 km

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Time and Distance
Exam Prep: Bank Exams

23 4612
Q:

An express traveled at an average speed of 100 km/hr, stopping for 4 min after every 75 km. How long did it take to reach its destination 600 km from the starting point ?

A) 6 hrs 24 min B) 6 hrs
C) 7 hrs 21 min D) 6 hrs 28 min
 
Answer & Explanation Answer: D) 6 hrs 28 min

Explanation:

Time taken to cover 600 km = 600/100 = 6 hrs.

Number of stoppages = 600/75 - 1 = 7

Total time of stoppages = 4 x 7 = 28 min

Hence, total time taken = 6 hrs 28 min.

Report Error

View Answer Report Error Discuss

Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

5 4612
Q:

Select a figure from the four alternatives that would complete the Figure Matrix.

     1366338751-11484717348.jpg image

  1366338751-121484717370.jpg image

    (1)   (2)  (3)   (4)

A) 2 B) 3
C) 4 D) 1
 
Answer & Explanation Answer: B) 3

Explanation:

By observing the above pattern Figure (3) will complete the matrix.

Report Error

View Answer Report Error Discuss

Filed Under: Figure Matrix
Exam Prep: Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

7 4611
Q:

If - means ÷ , + means x , ÷ means - , x means +, then which of the following equations is correct?

A) 43 x 7 ÷ 5 + 4 - 8 = 25 B) 48 ÷ 5 + 8 x 10 - 2 = 03
C) 36 x 4 - 12 + 5 ÷ 3 = 420 D) 42 + 5 ÷ 6 x 8 - 3 = 28
 
Answer & Explanation Answer: B) 48 ÷ 5 + 8 x 10 - 2 = 03

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Coding and Decoding

3 4610
Q:

How many such pair of letters are there in the word ‘TROUBLED’ which have as many letters between them in the word as they have between them in the English alphabet?

A) 2 B) 3
C) 4 D) 5
 
Answer & Explanation Answer: A) 2

Explanation:

Hence there are two pairs

Report Error

View Answer Report Error Discuss

13 4601
Q:

What is 15 of 80 with simple method and examples?

A) 12.5% B) 18.75%
C) 16.55% D) 17.80%
 
Answer & Explanation Answer: B) 18.75%

Explanation:

Given that to find 15 of 80

=> What % of 80 is 15

Let it be 'p'

=> p% of 80 = 15

=> p x 80100 = 15p = 15 x 10080p = 150080 = 18.75

 

Therefore, 15 is 18.75% of 80 => 18.75% of 80 = 15

 

Example::

Now, in the similar way we can find 15% of 80 =?

=> 15x80/100 = p

=> p = 4 x 3 = 12

 

Therefore, 15% of 80 = 12

Report Error

View Answer Report Error Discuss

Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO

9 4600