What are Different sections in Aptitude and Reasoning Question and Answers?
In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are:
Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).
Why Aptitude and Reasoning Questions?
Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.
What type of questions are there in Aptitude and Reasoning tests?
Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.
According to the National Agricultural Aviation Society (NAAS), without the use of crop protection products to control insects, weeds, and diseases, crop yields per acre will drop by more than 50 percent. The first aerial appligreion of insecticide occurred in 1921, and it was a huge success. By contrast, in today's economy all aircraft that are classified as aerial appligreors do more than just apply insecticide; today, they also spread seed and apply fertilizer.
From the information given above it CANNOT be validly concluded that
A) In today's economy, if an aerial appligreor is used, then it will be able to spread seed and to apply fertilizer
B) according to the NAAS, if crop yields per acre never drop by more than 50 percent, then crop protection products have been used to control insects, weeds, and diseases
C) in today's economy, any aircraft that cannot be used to apply fertilizer cannot be classified as an aerial appligreor
D) according to the NAAS, if crop yields per acre drop by more than 50 percent, then crop protection products have not been used to control insects, weeds, and diseases.
A) In today's economy, if an aerial appligreor is used, then it will be able to spread seed and to apply fertilizer
B) according to the NAAS, if crop yields per acre never drop by more than 50 percent, then crop protection products have been used to control insects, weeds, and diseases
C) in today's economy, any aircraft that cannot be used to apply fertilizer cannot be classified as an aerial appligreor
D) according to the NAAS, if crop yields per acre drop by more than 50 percent, then crop protection products have not been used to control insects, weeds, and diseases.
Answer & ExplanationAnswer: D) according to the NAAS, if crop yields per acre drop by more than 50 percent, then crop protection products have not been used to control insects, weeds, and diseases.
If the gifts are passed on, the whole purpose of the gift is defeated. Therefore, the gift should be one that is useful and at the same time it attracts you, appeals to you and you retain it.
Conclusions :
I.If gifts are retained , their utility increases.
II.Gifts are not meant for repeated change of hands.
I is not hinted at. It is an invention of the concluder's mind. II follows because if "the whole purpose of something is defeated", it loses its meaning.
The twice of sum of the ages of a father and his son is 8 times the age of the son. If the average age of the father and the son is 30 years, what is father's age ?
There are n boxes and m fruits. If we put 3 fruits in each box 3 fruits will be excess. If we put 4 fruits in each box 1 box will be excess. Find number of boxes and fruits ?
7 boxes & 24 Balls. Let, n = No. of boxes ; m = No. of fruits 3n+3 = m---------->(1) 4(n-1)= m---------->(2) =>4n-4 = 3n+3; =>4n-3n = 4+3 n = 7 Put n=7 in eqn(1) => 3(7)+3 = m 21+3 = m m = 24;
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