Aptitude and Reasoning Questions

Slant surface of a pyramid=1/2 perimeter of base slantheight

=1/2 x (4  x Side of squarebase) x Slantheight

Number of runs made by running = 180 - (11 x 4 + 8 x 6)
= 180 - (92)
= 88
Now, we need to calculate 88 is what percent of 180.
⇒88180×100  = 48.888%.

From statement I. we can conclude that the Chairman visited Purchase department on Monday of the first week of September. So, I alone is sufficient, The time of visit of no department is mentioned in II. which is, therefore, insufficient 

16x8 : Px4 = 5:2

P = 12.8 => Rs.12,800

First ten odd numbers form an arithmetic progression of the form
1,3,5,7,9......
here a = first term = 1
d = common difference = 2
Average of first n numbers = (2a + (n - 1)d)/2
n th term of the AP = a + (n - 1)d
Substituting a = 1, d = 2 and n = 10 in the above formulas
average of first 10 numbers = 10
10 th term of the AP = 19
Therefore average of first 10 terms is 19 - 10 = 9 greater than
the last term. Hence the average is greater than the sum by
9/19 X 100 = 900/19 %

Perimeter of the rectangle is given by 3000/10 = 300 mts

But we know,

The Perimeter of the rectangle = 2(l + b)

Now,

2(8x + 7x) = 300

30x = 300

x = 10

Required, Area of rectangle = 8x x 7x = 56 x 100 = 5600 sq. mts.

CP of bullock and cart = 1800

Let price of bullock be x and cart be (1800 –x)

SP of bullock and cart = 1800 + 155/6 X 1800 = 2265

Also, 1.2x + 1.3 (1800 –x) = 2265

⇒1.2x –1.3x = -75

⇒x = 750

Let father's age be x year and son's age be y year.

According to question,

2(x+y) = 8y _______(I)

and (x+y)/2 = 30

=> x+y = 60 years__________(II)

From equation (I) and (II)

8 y = 120

y = 15 years,

Hence x = 45 years.