Aptitude and Reasoning Questions

The sex of A is not known. So. neither (a) nor (b) is definitely true. Clearly, D is the grandmother of A and F. 

Let the number X is 100

Then, PÃ 80 QÃ 72

So, Percentage decrease from P to Q is à 8/80=0.1-100=10%

1 is the right choice.

Out of 4 fruits, any 3 are chosen by 4 families.So the combinations are
Apple - A Cherries - C Banana - B Grapes - G
1) ACB
2) ACG
3) BCG
4) GAB

By 2nd condition, Miller family uses either i)ACB or ii)ACG
Now we have Robin, Mandy and Miller who uses apples (ACB,ACG,GAB)
while Miller and Mandy both uses A and C. That leaves GAB for Robin.

By 3rd condition Flure uses either C or G. So if we leave out the terms containing both C and G, we are left with ACB and GAB

Now, for the time being let's suppose Robin is not a Flure.
So ACB is taken by Flure.

So ACG has to be Miller and that leaves BCG to be Clark. So we get Robin - Jacob(GAB).

By 4th and 2nd conditions Erica and Mandy belong to the first two. That leaves Stacy - Clark(BCG).

By 2nd condition Mandy is not a Miller, so we get Mandy - Flure(ACB) and that leaves Erica - Miller(ACG).

Sum of decimal places = 7.

Since the last digit to the extreme right will be zero (since 4 x 5 = 20), so there will be 6 significant digits to the right of the decimal point.

(3x + 2) (2x - 5) = ax2+kx+n ...............(1)

But (3x + 2)(2x - 5) = 6x2-11x-10........(2)

so by comparing (1) & (2),

we get a= 6, k= -11 , n= -10

(a - n + k) = 6 + 10 - 11 = 5.