Quantitative Aptitude - Arithmetic Ability Questions

Let breadth=x meters.   Then, Length =115x100 meters 

Given that, x×115x100=460  

=> x = 20  

Breadth = 20 

The watch gains 5 seconds in 3 minutes = 100 seconds in 1 hour.

From 8 AM to 10 PM on the same day, time passed is 14 hours.

In 14 hours, the watch would have gained 1400 seconds or 23 minutes 20 seconds.

So, when the correct time is 10 PM, the watch would show 10 : 23 : 20 PM

Let the required no of hours be x. Then

Less men , More hours    (Indirct Proportion)

Therefore,  15:36 ::25:x 

=> (15 x X)=(36 x 25)  => x = 60

Hence, 15 men can do it in 60 hours.

Let x and y be the length and breadth of the rectangle respectively.
Then, x - 4 = y + 3 or x - y = 7 ----(i)
Area of the rectangle =xy; Area of the square = (x - 4) (y + 3)
(x - 4) (y + 3) =xy <=> 3x - 4y = 12 ----(ii)
Solving (i) and (ii), we get x = 16 and y = 9.
Perimeter of the rectangle = 2 (x + y) = [2 (16 + 9)] cm = 50 cm.

Time from 7 am to 4.15 pm  = 9 hrs 15 min = 374 hrs 

3 min. 5 sec. of this clock = 3 min. of the correct clock. 

Now 3min.5sec. is37720 hrs of this clock = 3 min.is120 hrs of the correct clock 

374 hrs of clock = 120×72037×374 hrs of the correct clock. 

  = 9 hrs of the correct clock. 

 The correct time is 9 hrs after 7 am. i.e., 4 pm.

                                                A    :    B    :    C   

Ratio of efficiency               3     :    1    :    2   

Ratio of No.of days            1/3  :   1/1  :   1/2    

     or                                       2    :    6    :    3   

Hence A is correct.  

Let A's 1 day's work=x and B's 1 day's work=y

Then x+y = 1/40 and 20x+60y=1 

Solving these two equations , we get : x= 1/80 and y= 1/80

Therefore B's  1 day work = 1/80

Hence,B alone shall finish the whole work in 80 days