Quantitative Aptitude - Arithmetic Ability Questions

99 = 1 x 3 x 3 x 11

101 = 1 x 101

176 = 1 x 2 x 2 x 2 x 2 x 11

182 = 1 x 2 x 7 x 13

So, divisors of 99 are 1, 3, 9, 11, 33, .99

Divisors of 101 are 1 and 101

Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176

Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182.

Hence, 176 has the most number of divisors.

Let the sum be Rs. x. Then,

 C.I=x*50300*1003-x=343x216-x=127x216 

⇔127x216=1270 

x=2160 

Thus, the sum is Rs. 2160

 S.I=Rs.2160*503*3*1100=Rs 1080

                                         A                  B                   C

investment                    3x                 4x                  5x

Rate of return              6y%              5y%                4y%

Return                        18xy100 20xy100 20xy100                

               Total = (18+20+20) = 58xy100

     B's earnings - A's earnings  = 2xy100 = 250

     Total earning = 58xy100 = 7250

Let the capacity of the tank be x litres.

Then, (6x/7 - 2x/5) = 16 <=> 30x - 14x = 16*35 <=> x = 35

Let A, B, C be the events of getting a white ball in first, second and third draw respectively, then 

 Required probability = PA∩B∩C 

= PA PBA PCA∩B

 Now, P(A) = Probability of drawing a white ball in first draw = 4/18 = 2/9

When  a white ball is drawn in the first draw there are 17 balls left in the urn, out of which 3 are white

 ∴PBA=317 

Since the ball drawn is not replaced, therefore after drawing a white ball in the second draw there are 16 balls left in the urn, out of which 2 are white.

 ∴PCA∩B =216=18

 Hence the required probability = 29×317×18=1204

At 5% more rate, the increase in S.I for 10 years = Rs.600  (given)

So, at 5% more rate, the increase in SI for 1 year = 600/10 = Rs.60/-

i.e. Rs.60 is 5% of the invested sum

So, 1% of the invested sum = 60/5

Therefore, the invested sum = 60 × 100/5 = Rs.1200

Let the height of the parallelogram be x. cm. Then, base = (2x) cm.

2x×x=72=>2x2=72=>x=6