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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

A jogger is running at 9 kmph alongside a railway track is 240 meters ahead of the engine of a 120 meters long train running at 45 kmph in the same direction. In how much time will the train  pass the jogger ?

A) 48 sec B) 36 sec
C) 18 sec D) 72 sec
 
Answer & Explanation Answer: B) 36 sec

Explanation:

Speed of the train relative to jogger = (45-9) km/hr = 36 km/hr =(36*5/18) m/sec  = 10 m/sec

Distance to be covered =(240 + 120)m = 360 m

 Time taken = 360/10 sec = 36 sec

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Filed Under: Problems on Trains

11 9680
Q:

A train 800 metres long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel (in meters) is :

A) 130 B) 360
C) 500 D) 540
 
Answer & Explanation Answer: C) 500

Explanation:

Speed =[ 78 x ( 5/18 ) ] m/sec = 65/3 m/sec.

 

Time = 1 minute = 60 sec.

 

Let the length of the tunnel be x metres.

 

Then, [ (800 + x )/ 60 ]= 65/3

 

3(800 + x) = 3900

 

 x = 500.

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Filed Under: Problems on Trains

12 9678
Q:

The interest on Rs.750 for 2yrs is the same as the True Discount on Rs.960 due 2yrs hence . If the rate of interest is same in both cases,it is:

A) 12% B) 14%
C) 15% D) 16
 
Answer & Explanation Answer: B) 14%

Explanation:

S.I on Rs.750= T.D on Rs. 960 

This means P.W of Rs. 960 due 2 years hence is Rs.750 

Therefore , T.D= Rs. (960 - 750) = Rs. 210 

Thus, S.I on Rs. 750 for 2 years is Rs. 210 

Rate =[ (100 x 210) / (750 x 2) ] % = 14%

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Filed Under: True Discount

1 9673
Q:

The market value of a 10.5% stock, in which an income of Rs. 756 is derived by investing Rs. 9000, brokerage being 14%  is :

A) Rs.108.25 B) Rs.112.20
C) Rs.124.75 D) Rs.125.25
 
Answer & Explanation Answer: C) Rs.124.75

Explanation:

For an income of Rs.756, investment = Rs.9000 

 

For an income of Rs.212, investment = Rs.9000756*212 = Rs.125 

 

For a Rs.100 stock, investment = Rs.125.

 

Market value of Rs. 100 stock  = Rs.125-14 = Rs. 124.75

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Filed Under: Stocks and Shares

4 9629
Q:

A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B ?

A) 10 yrs B) 11 yrs
C) 12 yrs D) 13 yrs
 
Answer & Explanation Answer: A) 10 yrs

Explanation:

Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25 => x = 5
Hence, B's age = 2x = 10 years.

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

4 9628
Q:

45 men working 9 hours per day dig 40 m deep. How many extra men should be put to dig to a depth of 56 m working 7 hours per day ?

A) 36 B) 61
C) 48 D) 54
 
Answer & Explanation Answer: A) 36

Explanation:

(45 x 9)/40 = (M x 7)/56 => M = 81

=> 81 – 45 = 36

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Filed Under: Time and Work
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

6 9628
Q:

Courier charges for packages to a certain destination are 65 cents for the first 250 grams and 10 cents for each additional 100 grams or part thereof. What could be the weight in grams of a package for which the charge is $1.55 ?

A) 1155 B) 1145
C) 1040 D) None
 
Answer & Explanation Answer: B) 1145

Explanation:

The weight will be 250g plus (1.55 - 0.65)/0.10 units of 100g

250 + 900 = 1150

This is the maximum weight that can be sent at that price. But, weights exceeding

250 + 800 will also get charged this amount (that is what the ‘part thereof’ implies).

Hence a package weighing 1145 will be charged $1145

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Filed Under: Numbers
Exam Prep: GRE

9 9624
Q:

Train X crosses a stationary train Y in 60 seconds and a pole in 25 seconds with the same speed. The length of the train X is 300 m. What is the length of the stationary train Y ?

A) 360 m B) 420 m
C) 460 m D) 320 m
 
Answer & Explanation Answer: B) 420 m

Explanation:

Let the length of the stationary train Y be LY
Given that length of train X, LX = 300 m
Let the speed of Train X be V.
Since the train X crosses train Y and a pole in 60 seconds and 25 seconds respectively.
=> 300/V = 25 ---> ( 1 )
(300 + LY) / V = 60 ---> ( 2 )
From (1) V = 300/25 = 12 m/sec.
From (2) (300 + LY)/12 = 60
=> 300 + LY = 60 (12) = 720
=> LY = 720 - 300 = 420 m
Length of the stationary train = 420 m

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

7 9606