6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

In a certain Business, the profit is 220% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit ?

A) 61%	B) 75%
C) 55%	D) 81%

Answer & Explanation Answer: A) 61%

Explanation:

Let C.P.= Rs. 100.

Then, Profit = Rs.220,

S.P. = Rs.320.

New C.P. = 125% of Rs. 100 = Rs. 125

New S.P. = Rs.320.

Profit = Rs. (320 - 125) = Rs. 195

Required percentage = $\frac{195}{320} \times 100$ == 60.9 =~ 61%

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Filed Under: Profit and Loss
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7 9606

Q:

If 4th december 1999 is Monday then what day is 3rd january 2000 ?

A) Sunday	B) Monday
C) Tuesday	D) Wednesday

Answer & Explanation Answer: D) Wednesday

Explanation:

Here from 4th December 1999 to 3rd January 2000,
there is a difference of 30 days.
Number of odd days = 30/7 = 2 odd days

Then no. of odd days = 2 => tuesday and wednesday(from monday).

Hence on 3rd january it is wednesday.

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Filed Under: Calendar
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17 9603

Q:

A loan shark made a loan of $100 to be repaid with $120 at the end of one month. What was the annual interest rate?

A) 210%	B) 220%
C) 230%	D) 240%

Answer & Explanation Answer: D) 240%

Explanation:

r=I/PT

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Filed Under: Simple Interest
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5 9597

Q:

$17 \frac{4}{7} + 13 \frac{2}{12} - ? = 11 \frac{2}{3}$

A) 16	B) 17
C) 18	D) 19

Answer & Explanation Answer: D) 19

Explanation:

$17 \frac{4}{7} + 13 \frac{2}{12} - ? = 11 \frac{2}{3}$

$\frac{123}{7} + \frac{158}{12} - ? = \frac{35}{3}$

=> $? = \frac{123}{7} + \frac{158}{12} - \frac{35}{3}$

=> ? = $\frac{1476 + 1106 - 980}{84}$

=> ? = 19.07

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Filed Under: Simplification
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13 9592

Q:

In a charity show tickets numbered consecutively from 101 through 350 are placed in a box. What is the probability that a ticket selected at random (blindly) will have a number with a hundredth digit of 2?

A) 0.25	B) 0.5
C) 0.75	D) 0.40

Answer & Explanation Answer: D) 0.40

Explanation:

250 numbers between 101 and 350 i.e. n(S)=250

n(E)=100th digits of 2 = 299−199 = 100

P(E)= n(E)/n(S) = 100/250 = 0.40

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Filed Under: Probability

3 9589

Q:

5 men and 3 boys can together cultivate a 23 acre field in 4 days and 3 men and 2 boys together can cultivate a 7 acre field in 2 days. How many boys will be needed together with 7 men, if they cultivate 45 acre of field in 6 days.

A) 6	B) 4
C) 2	D) 3

Answer & Explanation Answer: C) 2

Explanation:

Let work done by 1 man in i day be m

and Let work done by 1 boy in 1 day be b

From the given data,

4(5m + 3b) = 23

20m + 12b = 23....(1)

2(3m + 2b) = 7

6m + 4b = 7 ....(2)

By solving (1) & (2), we get

m = 1, b = 1/4

Let the number of required boys = n

6(7 1 + n x 1/4) = 45

=> n = 2.

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Filed Under: Time and Work
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7 9583

Q:

The probability of occurance of two two events A and B are 1/4 and 1/2 respectively. The probability of their simultaneous occurrance is 7/50. Find the probability that neither A nor B occurs.

A) 25/99	B) 39/100
C) 61/100	D) 17/100

Answer & Explanation Answer: B) 39/100

Explanation:

P ( neither A nor B) = $P (A a n d B)$

= $P (A \cap B)$ = $P (A \cup B)$ = $1 - P (A \cup B)$

= $1 - \frac{61}{100} = \frac{39}{100}$

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Filed Under: Probability

8 9555

Q:

88 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be ?

A) 112 mts	B) 84 mts
C) 96 mts	D) 108 mts

Answer & Explanation Answer: B) 84 mts

Explanation:

Vol of silver = ${πR}^{2} h$ = 66 C.C

Given D= 1mm => R = D/2 = 1/20 cm

=> $\frac{22}{7} \times {(\frac{1}{20})}^{2} \times h$ = 66

= 66 x 400 x (7/22) = 8400 cm = 84 mtrs.

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Filed Under: Volume and Surface Area
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11 9550

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