Quantitative Aptitude - Arithmetic Ability Questions

Q:

Find the missing number in the given number series?

514, 470, ?, 415, 404

A) 441 B) 437
C) 426 D) 420
 
Answer & Explanation Answer: B) 437

Explanation:

Given number series is 514   470   ?   415   404

 

 

 

Here the pattern it follows is

 

514

 

514 - 44 = 470

 

470 - 33 = 437

 

437 - 22 = 415

 

415 - 11 = 404

 

Hence, the missing number in the given number series is 437.

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Filed Under: Odd Man Out
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4 80161
Q:

Solve the following :

 

(-4){19 - (-2) x (-8)} = ?

A) 12 B) -140
C) 140 D) -12
 
Answer & Explanation Answer: D) -12

Explanation:
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0 79821
Q:

A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: C) 3

Explanation:

Area of the park = (60 x 40) = 2400m2

Area of the lawn = 2109m2 

Area of the crossroads = (2400 - 2109) = 291m2 

Let the width of the road be x metres. Then,

60x+40x-X2=291 

x2-100x+291=0 

  (x - 97)(x - 3) = 0
   x = 3.

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Filed Under: Area
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86 79669
Q:

Consider the following for real numbers α, β, γ and δ ?

1) sec α = 1/4

2) tan β = 20

3) cosec γ = 1/2

4) cos δ = 2

How many of the above statements are not possible?

 

A) one  B) two
C) three D) four
 
Answer & Explanation Answer: C) three

Explanation:
Sec of any number can never be less than 1
tan can take any value from -∞ to + ∞
cosec of any number can never be less than 1
cos of any number can never be greater than 1
so option 1,3,4 are not possible
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1 79448
Q:

If the diagonal of a rectangle is 17cm long and its perimeter is 46 cm. Find the area of the rectangle.

A) 110 B) 120
C) 130 D) 140
 
Answer & Explanation Answer: B) 120

Explanation:

let length = x and breadth = y then  

2(x+y) = 46         =>   x+y = 23  

x²+y² = 17² = 289  

now (x+y)² = 23² 

=> x²+y²+2xy= 529 

=> 289+ 2xy = 529

=> xy = 120  

area = xy = 120 sq.cm

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287 79222
Q:

Solve the following : 80÷[48−56−(60−36÷12×4)]=?

 

A) 5 B) 8
C) 4 D) 2
 
Answer & Explanation Answer: D) 2

Explanation:
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2 79155
Q:

Find the odd man out in the following number series?

71, 88, 113, 150, 203, 277

A) 277 B) 203
C) 150 D) 113
 
Answer & Explanation Answer: A) 277

Explanation:

The given number series is 

 

71      88       113       150       203          277

   +17    +25       +37      +53        +74

        +8      +12        +16       +21

            +4          +4         +5

 

The series should be  71  88  112   150    203   276 i.e, the differences of the difference should be +4.

 

Hence, the odd man in the given series is 277.

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2 79083
Q:

A clock is set right at 5 a.m. The clock loses 16 minutes in 24 hours.What will be the true time when the clock indicates 10 p.m. on 4th day?

A) 11pm B) 12pm
C) 1pm D) 2pm
 
Answer & Explanation Answer: A) 11pm

Explanation:

Time from 5 am. on a day to 10 pm. on 4th day = 89 hours.

Now 23 hrs 44 min. of this clock = 24 hours of correct clock.

356/15 hrs of this clock = 24 hours of correct clock

89 hrs of this clock = (24 x 31556 x 89) hrs of correct clock.

= 90 hrs of correct clock.

So, the correct time is 11 p.m.

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Filed Under: Clocks
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241 78933