Quantitative Aptitude - Arithmetic Ability Questions

Let the total work be 'W'

As per the given information,

P can complete the work 'W' in 24 days.

=> one day work of P = W/24

And also given that,

The time taken by P to complete one-third of work is equal to time taken by Q to complete half of the work

=> PW/3 = QW/2

=> P's

1 day =    W/24

   ?    =      W/3

=>  ?  = 24W/3W  = 8

=> QW/2 = 8 days

=> Q alone can complete the work W in 16 days

=> P + Q can complete the work in

1/24 + 1/16 = 5/48

=> 48/5 days = 9 3/5 days.

S.P of Rs. 5000 stock = Rs.156100*5000= Rs. 7800. 

Income from this stock = Rs.12100*5000 = Rs. 600.  

Let investment in 8 % stock be x and that in 9 % stock = (7800 - x).

Therefore,  

x*890+7800-x*9108=600+70  

4x45+7800-x12=670⇔x=3600 

Therefore,  Money invested in 8 % stock at 90 = Rs. 3600.

Money invested in 9 % at 108 = Rs. (7800-3600) = Rs. 4200.

As we know we have 10 letter and 10 different address and one more information given that exactly 9 letter will at the correct address....so the remaining one letter automatically reach to their correct address
P(E) = favorable outcomes /total outcomes
Here favorable outcomes are '0'.
So probability is '0'.

Given = (0.2 * 0.2 + 0.01) / ( 0.1 * 0.1 + 0.02) = (0.04 + 0.01) / (0.01 + 0.02) = 0.05 / 0.03 = 5/3...

Let the quantity of alcohol and water be 4x liters and 3x liters respectively. Then,

(4x)/(3x+5) = 4/5

=> 20x = 4(3x+5) 

=> x = 2.5 

Quantity of alcohol = (4 * 2.5) liters = 10 liters.

35+125=17.88 ⇒35+55=17.88

⇒5=2.235

∴80+65=45+65=105=10×2.235=22.35

Given A alone can fill the tank of capacity 240 lit in 16 hrs.

=> A can fill in 1 hr = 240/16 = 15 lit

=> B alone can fill the tank of capacity 240 lit in 12 hrs.

=> B can fill in 1 hr = 240/12 = 20 lit

Now, (A + B) in 1 hr = 15 + 20 = 35 lit

But they are opened for 2 hrs

=> 2 x 35 = 70 lit rae filled

Remaining water to be filled in tank of 240 lit = 240 - 70 = 170 lit.