6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

The last day of a century cannot be

A) Monday	B) Wednesday
C) Tuesday	D) Friday

Answer & Explanation Answer: C) Tuesday

Explanation:

A century means 100 years => 76 normal years and 24 leap years

We know that, a normal year contain 1 odd day (365/7 = 52 weeks + 1 odd day)

a leap year contain 2 odd days (365/7 = 52 weeks + 2 odd days)

100 years => 76 x 1 + 24 x 2 = 124 odd days = 124/7 = (17 weeks + 5 odd days)

200 years => 2 x 5 = 10 = 1 week + 3 odd days

300 years => 3 x 5 = 15 = 2 weeks + 1 odd day

400 years => 4 x 5 = 20 + 1 odd day (leap year) = 3 weeks + 0 odd days

500 years => 5 x 5 = 25+1 = 26/7 = 3 weeks + 5 odd days

Again repeats...

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Filed Under: Calendar

6 7901

Q:

K and L start the business, with L investing the total capital of Rs. 40,000 on the condition that K pays L interest @ 8% per annum on his half of the capital. L is a working partner and receives Rs.1200 per month from the total profit and any profit reamaining is equally shared by both of them. At the end of the year, it was found that the income of L is twice that of K. Find the total profit for the year ?

A) Rs.44000	B) Rs.46400
C) Rs.480800	D) Rs.46000

Answer & Explanation Answer: B) Rs.46400

Explanation:

Interest received by L from K = 8% of half of Rs.40,000

$\Rightarrow \frac{8}{100} \times 20000 = 1600$

Amount received by L per annum for being a working partner = 1200 x 12 = Rs.14,400

Let 'A' be the part of remaing profit that 'L' receives as his share.

Total income of 'K' = only his share from the reamaing profit

= 'A', as both share equally.

Given income of L = Twice the income of K

--> (1600 + 14400 + A ) = 2A

--> A= Rs.16000

Thus total profit = 2A + Rs.14,400= 2(16000) + 14400

= 32000 +14400 = Rs.46,400.

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Filed Under: Partnership
Exam Prep: CAT
Job Role: Bank PO

13 7897

Q:

$9 \frac{3}{4} + 7 \frac{2}{17} - 9 \frac{1}{15} = ?$

A) 7 + 719/1020	B) 9 + 817/1020
C) 9 + 719/1020	D) 7 + 817/1020

Answer & Explanation Answer: D) 7 + 817/1020

Explanation:

$g i v e n s u m = 9 + \frac{3}{4} + 7 + \frac{2}{17} - (9 + \frac{1}{15})$

$(9 + 7 + 9) + (\frac{3}{4} + \frac{2}{17} - \frac{1}{15})$

=> $\frac{7 + (765 + 120 - 68)}{1020}$ => $7 + \frac{817}{1020}$

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Filed Under: Numbers

4 7897

Q:

The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period (in years) is

A) 2years	B) 3years
C) 4years	D) 5years

Answer & Explanation Answer: A) 2years

Explanation:

Amount = Rs(30000 + 4347) = Rs.34347.

Let the time be n years. Then,

$30000 {[1 + \frac{7}{100}]}^{n} = 34347$

$\Leftrightarrow$ ${(\frac{107}{100})}^{n} = \frac{34347}{30000} = \frac{11449}{10000} = {(\frac{107}{100})}^{2}$

n= 2years.

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

1 7891

Q:

What would be the least number of years in which the simple interest on Rs.2600 at % will be an exact number of rupees ?

A) 2	B) 3
C) 4	D) 5

Answer & Explanation Answer: B) 3

Explanation:

$S . I = R s . [2600 * \frac{20}{3} * \frac{1}{100} * t]$

$S . I = R s . [\frac{520}{3} * t]$

t=3

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

6 7880

Q:

A number is selected from the numbers 1,2,3,4.......25.The probability for it to be divisible by 4 or 7 is:

A) 3/25	B) 9/25
C) 1/25	D) None of these

Answer & Explanation Answer: B) 9/25

Explanation:

Total numbers = 25

Numbers divisible by 4 or 7 are 4, 7, 8, 12, 14, 16, 20, 21, 24 = 9

The probability (divisible by 4 or 7) = 9/25

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Filed Under: Probability

3 7879

Q:

The average marks of a student in 7 subjects is 85. His average marks in 6 subjects except English is 83. What is his marks in English ?

A) 97	B) 98
C) 92	D) 93

Answer & Explanation Answer: A) 97

Explanation:

Marks in English = 85×7 – 83×6

= 595 – 498

= 97

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Filed Under: Average
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

22 7872

Q:

The Age of Ashok , Deepak and Ramu are in the proportion of 3:5:6. If the difference between the ages of Deepak and Ramu is 5 years . what is Ashok's age in years?

Answer

Suppose the ages of Ashok, Deepak and Ramu are 3x, 5x and 6x years respectively.

$6x-5x=5\: \: \Rightarrow x=5$