6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

The cost of Type 1 rice is Rs. 15 per kg and Type 2 rice is Rs.20 per kg. If both Type 1 and Type 2 are mixed in the ratio of 2 : 3, then the price per kg of the mixed variety of rice is

A) Rs. 19.50	B) Rs. 19
C) Rs. 18	D) Rs. 18.50

Answer & Explanation Answer: C) Rs. 18

Explanation:

Let the price of the mixed variety be Rs. x per kg. By the rule of alligation, we have :

Cost of 1 kg of type 1 rice Cost of 1 kg of type 2 rice

$∴$ (20-x)/(x-15) = 2/3

$\Rightarrow$ 60 - 3x = 2x - 30

$\Rightarrow$ x = 18.

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Filed Under: Alligation or Mixture

109 48827

Q:

The length of a diagonal in cms of a rectangle of length 5 cm and width 6 cm is

A) 61	B) ±61
C) 11	D) ±11

Answer & Explanation Answer: A) 61

Explanation:

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Filed Under: Area
Exam Prep: Bank Exams

3 48712

Q:

Find the odd man out in the following number series?

5, 4, 9, 32, 273

A) 4	B) 9
C) 32	D) 273

Answer & Explanation Answer: C) 32

Explanation:

The given number series follows 5, 4, 9, 32, 308 pattern that

5

5 x 1 - 1 = 4

4 x 3 - 3 = 9

9 x 5 - 5 = 40 (not equals to 32)

40 x 7 - 7 = 273

Hence, the odd man in the given number series is 32.

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Filed Under: Odd Man Out
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4 48615

Q:

ΔDEF is right angled at E. If m∠F = 30 deg, then find the value of (cosD - 1/√2).

A) -1/2	B) (√6-1)/√3
C) (√2-2)/2√2	D) √3-2

Answer & Explanation Answer: C) (√2-2)/2√2

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

0 48572

Q:

30% of a number is 33. What is the number?

A) 120	B) 115
C) 105	D) 110

Answer & Explanation Answer: D) 110

Explanation:

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Filed Under: Percentage
Exam Prep: Bank Exams

3 48437

Q:

${Cos}^{2} 90^{°} + {Cosec}^{2} 90 ° - {Cot}^{2} 45^{°} = ?$

A) 2	B) 1
C) 1/2	D) √3/2

Answer & Explanation Answer: B) 1

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

0 48430

Q:

A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a

king of heart is:

A) 2/13	B) 1/13
C) 1/26	D) 1/52

Answer & Explanation Answer: C) 1/26

Explanation:

Here, n(S) = 52.

Let E = event of getting a queen of club or a king of heart.

Then, n(E) = 2.

P(E) =n(E)/n(S)=2/52=1/26.

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Filed Under: Probability

7 48408

Q:

A basket contains 10 apples and 20 oranges out of which 3 apples and 5 oranges are defective. If we choose two fruits at random, what is the probability that either both are oranges or both are non defective?

A) 136/345	B) 17/87
C) 316/435	D) 158/435

Answer & Explanation Answer: C) 316/435

Explanation:

$n (s) = {}^{30}C_{2}$

Let A be the event of getting two oranges and

B be the event of getting two non-defective fruits.

and $(A \cap B)$ be the event of getting two non-defective oranges

$∴ P (A) = \frac{{}^{20}C_{2}}{{}^{30}C_{2}}, P (B) = \frac{{}^{22}C_{2}}{{}^{30}C_{2}} a n d P (A \cap B) = \frac{{}^{15}C_{2}}{{}^{30}C_{2}}$

$∴ P (A \cup B) = P (A) + P (B) - P (A \cap B)$

= $\frac{{}^{20}C_{2}}{{}^{30}C_{2}} + \frac{{}^{22}C_{2}}{{}^{30}C_{2}} - \frac{{}^{15}C_{2}}{{}^{30}C_{2}} = \frac{316}{435}$

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Filed Under: Probability

109 48370

Quantitative Aptitude - Arithmetic Ability Questions

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