Quantitative Aptitude - Arithmetic Ability Questions

Q:

In the given figure, if  QR/XY = 14/9 and PY = 18 cm, then what is the value (in cm) of PQ?

 

 

A) 28 B) 18
C) 21 D) 24
 
Answer & Explanation Answer: A) 28

Explanation:
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Q:

Ram sell his goods 25% cheaper than Shyam and 25% dearer than Bram. How much % is Bram's good cheaper than Shyam ?

A) 60% B) 40%
C) 50% D) 30%
 
Answer & Explanation Answer: B) 40%

Explanation:

Lets say shyam sells at 100,

 

Since Ram sells 25% cheaper than Shyam,

 

Therefor Ram sells at less than 25% of100 or 75 rs.

 

Ram sells 25% dearer than Bram or 125% of Ram =100% of Bram or

 

125% of x (say x price of bram )=75rs.
or 100% of x =60rs.
hence price of bram is 60rs.

 

now Bram's good is cheaper than Shyam's as (100-60)x100/100% or 40%.

 

Hence Brams Good is 40% cheaper than that of Shyam's good.

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Q:

DEF is right angled at E. If m∠F = 60 deg, then find the value of (cotD - 2/√3).

 

A) 1 - √2 B) 1/√3
C) (2 - √3)/2√3 D) (2 - 2√3)/√3
 
Answer & Explanation Answer: B) 1/√3

Explanation:
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Q:

If the value of θ = 30°, then the value of tan2θ + cot2θ.

 

A) 1/3 B) 4/3
C) 9/3 D) 10/3
 
Answer & Explanation Answer: D) 10/3

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Q:

If p & q = p2 + 4pq - q2 then find the value of (3 & 6) + (4 & 5).

 

A) 98 B) 106
C) 116 D) 126
 
Answer & Explanation Answer: C) 116

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Q:

Find the odd man out in the following number series?

5, 4, 9, 32, 273

A) 4 B) 9
C) 32 D) 273
 
Answer & Explanation Answer: C) 32

Explanation:

The given number series follows 5, 4, 9, 32, 308 pattern that

 

5

5 x 1 - 1 = 4

4 x 3 - 3 = 9

9 x 5 - 5 = 40 (not equals to 32)

40 x 7 - 7 = 273

 

Hence, the odd man in the given number series is 32.

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Q:

If  1515151515....... and x > 0, then find the value of x2 + 4.

 

A) 125 B) 179
C) 200 D) 229
 
Answer & Explanation Answer: D) 229

Explanation:
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Q:

The H.C.F and L.C.M of two numbers are 11 and 385 respectively. If one number lies between 75 and 125 , then that number is

A) 77 B) 88
C) 99 D) 110
 
Answer & Explanation Answer: A) 77

Explanation:

Product of numbers = 11 x 385 = 4235

 

Let the numbers be 11a and 11b . Then , 11a x 11b = 4235  =>  ab = 35

 

Now, co-primes with product  35 are (1,35) and (5,7)

 

So, the numbers are ( 11 x 1, 11 x 35)  and (11 x 5, 11 x 7)

 

Since one number lies 75 and 125, the suitable pair is  (55,77)

 

Hence , required number = 77

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