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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

Angles of the triangle are in the ratio of 1:2:3. Choose the correct triangle for the given ratio.

 

A) Equilateral B) Isosceles
C) Right angle D) Obtuse angled
 
Answer & Explanation Answer: C) Right angle

Explanation:
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Q:

Ian has 14 boxes of paper and divides them evenly between 4 coworkers. How many whole boxes did each coworker get?

A) 2 B) 2.5
C) 3 D) 3.5
 
Answer & Explanation Answer: C) 3

Explanation:

Given number of boxes = 14

Number of workers = 4

Now, number of whole boxes per worker = 14/4 = 3.5 

Hence, number of whole boxes per each coworker = 3

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28 38496
Q:

Solve the following :

 

72 ÷ 12{15 + 12 - 9 + 6 - 5 + 7¯} = ?

 

A) 6 B) 9
C) 12 D) 8
 
Answer & Explanation Answer: A) 6

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Q:

Solve the following :

60 ÷ 5 × 16 - 8 ÷ 2 ÷ 3 = ?

A) 3 B) 48
C) 1 D) 1/3
 
Answer & Explanation Answer: B) 48

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Q:

If a * b = 2a - 3b + ab, then 3 * 5 + 5 * 3  is equal to : 

A) 22 B) 23
C) 24 D) 25
 
Answer & Explanation Answer: A) 22

Explanation:

3 * 5 + 5 * 3 = (2 * 3 - 3 * 5 + 3 * 5) + ( 2 * 5 - 3 * 3 + 5 * 3)

                    = (6 + 10 - 9 + 15) = 22.

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87 38362
Q:

A contractor undertakes to do a piece of work in 40 days. He engages 100 men at the begining and 100 more  after 35 days and completes the work in stipulated time. If he had not  engaged  the additional men, how many days  behind schedule would it be finished?

A) 3 B) 5
C) 6 D) 9
 
Answer & Explanation Answer: B) 5

Explanation:

[(100 x 35) + (200 x 5)]men can finish the work in 1 day 

Therefore, 4500 men can finish the work in 1 day. 100 men can finish it in  4500/100= 45 days.

This is 5 days behind Schedule

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Q:

If tan4θ + tan2θ = 2, then sec4θ - sec2θ = ?

 

A) 0 B) 3
C) 2 D) 1
 
Answer & Explanation Answer: C) 2

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Q:

Two dice are thrown together .What is the probability that the sum of the number on the two faces is divided by 4 or 6.

A) 7/18 B) 14/35
C) 8/18 D) 7/35
 
Answer & Explanation Answer: A) 7/18

Explanation:

Clearly, n(S) = 6 x 6 = 36
Let E be the event that the sum of the numbers on the two faces is divided by 4 or 6.
Then,E = {(1,3),(1,5),(2,2),(2,4),(2,6),(3,1),(3,3),(3,5),(4,2),(4,4),(5,1),(5,3),(6,2),(6,6)}
n(E) = 14.
Hence, P(E) = n(E)/n(S) = 14/36 = 7/18

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Filed Under: Probability

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