Quantitative Aptitude - Arithmetic Ability Questions

Q:

Two partners investede Rs. 1250 and Rs. 850 respectively in a business. They distributed 60% of the profit equally and decide to distribute the remaining 40% as the ratio of their capitals. If one partner received Rs. 30 more than the other, find the total profit?

Answer

Let the total profit be Rs.x


60% of the profit = \inline \frac{60}{100}\times x=Rs.\frac{3x}{5}


from  this part of the profit each gets = Rs.\inline \frac{3x}{10}


40% of the profit = \inline \frac{40}{100}\times x=Rs.\frac{2x}{5}


Now, this amount of Rs.\inline \frac{2x}{5} has been divided in the ratio of capitals 1250 : 850 = 25 :17


\inline \therefore Share on first capital = \inline (\frac{2x}{5}\times \frac{25}{42})=Rs.\frac{5x}{21}


Share on second capital = \inline (\frac{2x}{5}\times \frac{17}{42})=Rs.\frac{17x}{105}


Total money received by 1st investor = \inline [\frac{3x}{10}+\frac{5x}{21}]= Rs.\frac{113x}{210}


Total money received by 2nd investor = \inline [\frac{113x}{210}+\frac{97x}{210}]=Rs.\frac{97x}{210}


\inline \therefore x = 393.75


Hence total profit = Rs. 393.75

Report Error

View answer Workspace Report Error Discuss

Subject: Partnership

102 33111
Q:

On a sum of money, the simple interest for 2 years is Rs. 660,while the compound interest is Rs.696.30,the rate of interest being the same in both the cases. The rate of interest is

A) 10% B) 11%
C) 12% D) 13%
 
Answer & Explanation Answer: B) 11%

Explanation:

Difference in C.I and S.I for 2 years

= Rs(696.30-660)

=Rs. 36.30.

 

S.I for one years = Rs330.

S.I on Rs.330 for 1 year =Rs. 36.30 

 

Rate

= (100x36.30/330x1)%

= 11%

Report Error

View Answer Report Error Discuss

Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

42 33078
Q:

The number of diagonals in a decagon is:

 

A) 20 B) 10
C) 25 D) 35
 
Answer & Explanation Answer: D) 35

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: Bank Exams

0 32998
Q:

At a game of billiards, A can give B 15 points in 60 and A can give C to 20 points in 60. How many points can B give C in a game of 90?

A) 30 points B) 20 points
C) 10 points D) 12 points
 
Answer & Explanation Answer: C) 10 points

Explanation:

A : B = 60 : 45.

 

A : C = 60 : 40.

 

B/C = (B/A*A/C) = (45/60*60/45) = 45/40 = 90/80 = 90:80

 

B can give C 10 points in a game of 90.

Report Error

View Answer Report Error Discuss

Filed Under: Races and Games

28 32988
Q:

What time between 4 and 5 o'clock will the hands of a clock be at rightangle?

A) 3 5/11 B) 4 5/11
C) 5 5/11 D) 6 5/11
 
Answer & Explanation Answer: C) 5 5/11

Explanation:

this type of problems the formulae is
(5*x + or -15)*(12/11)
Here x is replaced by the first interval of given time
here i.e 4
Case 1 : (5*x + 15)*(12/11)
(5*4 +15)*(12/11)
(20+15)*(12/11)
35*12/11=420/11=38 2/11 min.
Therefore they are right angles at 38 2/11 min .past4
Case 2 : (5*x-15)*(12/11)
(5*4-15)*(12/11)
(20-15)*(12/11)
5*12/11=60/11 min=5 5/11min
Therefore they are right angles at 5 5/11 min.past4.

Report Error

View Answer Report Error Discuss

Filed Under: Clocks
Exam Prep: Bank Exams
Job Role: Bank PO

49 32967
Q:

If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction is 25/51. What is the original fraction ?

A) 31/25 B) 15/17
C) 14/25 D) 11/16
 
Answer & Explanation Answer: B) 15/17

Explanation:

The original fraction is  2551 × 350+100150+100  = 15/17.

Report Error

View Answer Report Error Discuss

Filed Under: Percentage
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

61 32955
Q:

From a container, 6 liters milk was drawn out and was replaced by water. Again 6 liters of mixture was drawn out and was replaced by the water. Thus the quantity of milk and water in the container after these two operations is 9:16. The quantity of mixture is:

A) 15 B) 16
C) 25 D) 31
 
Answer & Explanation Answer: A) 15

Explanation:

Let quantity of mixture be x liters.

 

Suppose a container contains x units of liquid from which y units are taken out and replaced by Water. After operations , the quantity of pure liquid = x1-yxn units, Where n = no of operations . 

 

So, Quantity of Milk = x1-6x2  

 

Given that, Milk : Water = 9 : 16 

 

=> Milk : (Milk + Water) = 9 : (9+16)

 

=> Milk : Mixture = 9 : 25 

 

 Therefore, x1-6x2x=925

 

=> x = 15 liters

Report Error

View Answer Report Error Discuss

Filed Under: Alligation or Mixture

67 32917
Q:

How many cubes of 3cm edge can be cut out of a cube of 18cm edge

A) 36 B) 232
C) 216 D) 484
 
Answer & Explanation Answer: C) 216

Explanation:

number of cubes=(18 x 18 x 18) / (3 x 3 x 3) = 216

Report Error

View Answer Report Error Discuss

Filed Under: Volume and Surface Area
Exam Prep: Bank Exams
Job Role: Bank PO

93 32874