6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

The reflex angle between the hands of a clock at 10.25 is

A) 197 1/2	B) 167 1/2
C) 157 1/2	D) 187 1/2

Answer & Explanation Answer: A) 197 1/2

Explanation:

Angle traced by hour hand in 125/12 hrs = (360/12 * 125/12) = $312 \frac{1^{0}}{2}$

Angle traced by minute hand in 25 min = (360/60 * 25) = $150^{0}$

$\therefore$ Reflex angle = $360^{0} - {(312 \frac{1}{2} - 150)}^{0} = 360^{0} - 162 \frac{1^{0}}{2} = 197 \frac{1^{0}}{2}$

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Filed Under: Clocks
Exam Prep: Bank Exams
Job Role: Bank PO

65 30805

Q:

Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran's share in the profit ?

A) 10110	B) 10500
C) 12000	D) 13000

Answer & Explanation Answer: B) 10500

Explanation:

Simran : Nanda = (50000 * 36) : (80000 * 30) = 3 : 4.

Simran's share = Rs. ( 24500 * 3/7) = Rs. 10500.

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Filed Under: Partnership

27 30715

Q:

A Contractor employed a certain number of workers to finish constructing a road in a certain scheduled time. Sometime later, when a part of work had been completed, he realised that the work would get delayed by three-fourth of the scheduled time, so he at once doubled the no of workers and thus he managed to finish the road on the scheduled time. How much work he had been completed, before increasing the number of workers?

A) 10 %	B) 14 ( 2/7 )%
C) 20 %	D) Can't be determined

Answer & Explanation Answer: B) 14 ( 2/7 )%

Explanation:

Let he initially employed x workers which works for D days and he estimated 100 days for the whole work and then he doubled the worker for (100-D) days.

D * x +(100- D) * 2x= 175x

=> D= 25 days

Now , the work done in 25 days = 25x

Total work = 175x

Therefore, workdone before increasing the no of workers = $\frac{25 x}{175 x} \times 100$ % = $14 \frac{2}{7} %$

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Filed Under: Time and Work

107 30681

Q:

A letter lock consists of three rings each marked with six different letters. The number of distinct unsuccessful attempts to open the lock is at the most ?

A) 215	B) 268
C) 254	D) 216

Answer & Explanation Answer: A) 215

Explanation:

Since each ring consists of six different letters, the total number of attempts possible with the three rings is = 6 x 6 x 6 = 216. Of these attempts, one of them is a successful attempt.

Maximum number of unsuccessful attempts = 216 - 1 = 215.

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Filed Under: Permutations and Combinations
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

27 30675

Q:

A number when divided by 296 leaves 75 as remainder.When the same number is divided by 37,the remainder will be:

A) 1	B) 3
C) 5	D) 2

Answer & Explanation Answer: A) 1

Explanation:

Let the Number be Y.

Then Y = 296 q + 75

= (37 x 8)q +( 37 x 2) + 1

= 37 (8q + 2) + 1

Thus, when the number is divided by 37, the remainder is 1

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Filed Under: Numbers

76 30646

Q:

Bhajan Singh purchased 120 reams of paper at Rs 80 per ream. He spent Rs 280 on transportation, paid octroi at the rate of 40 paise per ream and paid Rs 72 to the coolie. If he wants to have a gain of 8 %, what must be the selling price per ream?

A) 90	B) 89
C) 87.48	D) 86

Answer & Explanation Answer: A) 90

Explanation:

Total investment = Rs. (120 * 80 + 280 + (40/100) * 120 + 72).
= Rs. (9600 + 280+48 + 72) = Rs, 10000.
Sell price of 120 reams = 108% of Rs. 10000 = Rs. 10800.
Sell Price per ream = Rs. [10800/120] = Rs. 90.

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Filed Under: Profit and Loss

58 30620

Q:

The cost of fencing a square field @ Rs. 20 per metre is Rs.10.080.How much will it cost to lay a three meter wide pavement along the fencing inside the field @ Rs. 50 per sq m

A) 53800	B) 43800
C) 83800	D) 73800

Answer & Explanation Answer: D) 73800

Explanation:

perimeter = total cost / cost per m = 10080 /20 = 504m
side of the square = 504/4 = 126m
breadth of the pavement = 3m
side of inner square = 126 - 6 = 120m
area of the pavement = (126 x126) - (120 x 120) = 246 x 6 sq m
cost of pavement = 246*6*50 = Rs. 73800

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

30 30619

Q:

The circumference of a circle is 66 cm. Find its radius (in cm).

A) 21	B) 10.5
C) 4.5	D) 9

Quantitative Aptitude - Arithmetic Ability Questions

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