Quantitative Aptitude - Arithmetic Ability Questions

Let p be the principle amount

And R% be the rate of interest

Then, required ratio =P×4×R100P×6×R100 

⇒4PR6PR= 2:3

Total weight of 50 boys = 45 X 50 = 2250

Average weight of 49 boys = 44.9

Total weight of 49 boys = 44.9 X 49 = 2200.1

Weight of boy who left the class=2250–2200.1=49.9

Let the salary of B be 100

Salary of A = 150%

B’s salary less than A = (150-100)/150 X 100 = 100/3 = 33.33%

We know, the perimeter of a triangle = sum of all the sides of a triangle = a + b + c

Here given that sides a = 38, b= 36 and c = 18

Now, perimeter of the triangle = a + b + c = 38 + 36 + 18 = 92 units.

Working efficiency of both typist together = 100/6 = 16.66%

Let the efficiency of first typist be x and second typist be (16.66 –x)

First typist for 4 minute + second tyoistfor 6 minute = 80% work

⇒4x + (16.66 –x) X 6 = 80%

⇒4x + 100% -6x = 80%,

⇒x = 10%

First typist typed 10% per minute, second typst typed (16.66 –10) = 6.66% per minute

Slowest is second typist complete whole job in 100/6.66 = 15.01 = 15 minute

Here we have 25 divided by 7.

25 will not go directly in 7

Hence, we get the result in decimals.

25/7 = 3.571.