Quantitative Aptitude - Arithmetic Ability Questions

Q:

In a computer game, a builder can build a wall in ten hours while a destroyer can demolish such a wall completely in fourteen hours. Both, the builder and the destroyer were initially set to work together on level ground. But after 7 hours the destroyer was taken out. What was the total time (in hrs) taken to build the wall ?

A) 17 B) 15
C) 24 D) 35
 
Answer & Explanation Answer: B) 15

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Q:

The area of a square is 100 sq cm, find length of its diagonal?

A) 10√2 cm B) 10 cm
C) 20 cm D) 20√2 cm
 
Answer & Explanation Answer: A) 10√2 cm

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Filed Under: Area
Exam Prep: Bank Exams

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Q:

If two successive discounts of 25% and 30% are given, then what will be the ratio of marked price to selling price?

A) 20 : 7 B) 40 : 21
C) 20 : 17 D) 40 : 33
 
Answer & Explanation Answer: B) 40 : 21

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Filed Under: Ratios and Proportions
Exam Prep: Bank Exams

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Q:

What is the value of cosec 11π/6?

A) -2/√3 B) √2
C) -2 D) -√2
 
Answer & Explanation Answer: C) -2

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Filed Under: Simplification
Exam Prep: Bank Exams

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Q:

A trader marks up his goods by 120% and offers 30% discount. What will be the selling price (in Rs) if the cost price is Rs 750?

A) 1225 B) 1080
C) 1280 D) 1155
 
Answer & Explanation Answer: D) 1155

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Filed Under: Percentage
Exam Prep: Bank Exams

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Q:

The difference of squares of two numbers is 180. The square of the smaller number is 8 times the larger number. Find two numbers.

A) 10 & 12 B) 10 & 18
C) 12 & -18 D) -12 & 18
 
Answer & Explanation Answer: D) -12 & 18

Explanation:

Given, difference of the squares of two numbers is 180.

k2 - l2 - 180

 

Also, square of the smaller number is 8 times the larger.

= l= 8k

 

Thus, k2 - 8a - 180 = 0

k2 – 18k + 10k - 180 = 0

→  k(k - 18) + 10(k – 18) = 0

= (k + 10)(k – 18) = 0

→  k = -10, 18

 

Thus, the other number is

324 - 180 = l2 

 

→ Numbers are 12, 18 or -12, 18.

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Filed Under: Numbers
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Q:

A starts a business, after 6 months B also join him with Rs.4500 and after 2 months of B’s joining C also join them with Rs.4500. If A gets approx. Rs 4900 out of total annual profit of Rs. 10,000 then find the approximate value of initial investment of A.

A) Rs.4800 B) Rs.4200
C) Rs.3600 D) Rs.4400
 
Answer & Explanation Answer: C) Rs.3600

Explanation:

Let initial investment of A = x
Ratio of profit A : B : C = 12 × x : 6×4500 :4×4500
A :B:C = x : 2250: 1500
Now ATQx/(x+2250+1500) = 4900/10000
solving this we get,x ≈ Rs 3600

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Q:

An item is sold at two successive gains of 30% and 20%. If the final selling price is Rs 31200, then what is the cost price (in Rs)?

 

A) 15000 B) 20000
C) 22250 D) 24000
 
Answer & Explanation Answer: B) 20000

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Filed Under: Profit and Loss
Exam Prep: Bank Exams

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