6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

The maximum gap between two successive leap year is?

A) 4	B) 8
C) 2	D) 1

Answer & Explanation Answer: B) 8

Explanation:

This can be illustrated with an example.

Ex: 1896 is a leap year.The next leap year comes in 1904 (1900 is not a leap year).

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Filed Under: Calendar

187 33130

Q:

A, B, C hired a car for Rs. 520 and used it for 7, 8 and 11 hours respectively. Hire charges paid by B were :

A) 150	B) 160
C) 170	D) 180

Answer & Explanation Answer: B) 160

Explanation:

A : B : C = 7 : 8 : 11.

Hire charges paid by B = Rs. (520 * 8/26) = Rs. 160.

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Filed Under: Partnership

21 33126

Q:

Find the curved surface area (in cm2) of a right circular cylinder of diameter 14 cm and height 8 cm.

A) 308	B) 352
C) 327	D) 371

Answer & Explanation Answer: B) 352

Explanation:

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

0 32986

Q:

If 15% of x = 20% of y, then x:y is ___?

A) 4:3	B) 5:4
C) 4:5	D) 3:4

Answer & Explanation Answer: A) 4:3

Explanation:

Given 15% of x = 20% of y

=> 15x = 20y

=> x/y = 20/15

=> x : y = 4 : 3

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

77 32950

Q:

In the following question, select the related number from the given alternatives.

8 : 27 : : 64 : ?

A) 190	B) 144
C) 125	D) 72

Answer & Explanation Answer: C) 125

Explanation:

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Filed Under: Ratios and Proportions

0 32944

Q:

A can run 22.5 m while B runs 25 m. In a kilometre race B beats A by:

A) 100 m	B) 75 m
C) 25 m	D) 50m

Answer & Explanation Answer: A) 100 m

Explanation:

When B runs 25 m, A runs 45/2 m

When B runs 1000 m, A runs (45/2*1/25*1000)m = 900 m.

B beats A by 100 m.

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Filed Under: Races and Games

44 32852

Q:

The difference between the simple interest on a certain sum at the rate of 10%per annum for 2 years and compound interest which is compounded every 6 months is Rs.124.05. what is the principal sum

A) Rs.6000	B) Rs.8000
C) Rs.12000	D) none of these

Answer & Explanation Answer: B) Rs.8000

Explanation:

Compound Interest on P at 10% for 2 years when interest is compounded half-yearly

= $P {(1 + \frac{\frac{R}{2}}{100})}^{2 T} - P = P {(1 + \frac{1}{20})}^{4} - P = P {(\frac{21}{20})}^{4} - P$

Simple Interest on P at 10% for 2 years = $\frac{P R T}{100} = \frac{P \times 10 \times 2}{100} = \frac{P}{5}$

Given that difference between compound interest and simple interest = 124.05

$P * {(\frac{21}{20})}^{4} - P - \frac{P}{5} = 124.05$

=> $P [{(\frac{21}{20})}^{4} - 1 - \frac{1}{5}] = 124.05$

P=8000

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

61 32831

Q:

Rohit crosses a 700 metres wide road in 35 seconds. What is his speed (in km/hr)?

A) 54	B) 76
C) 72	D) 84

Quantitative Aptitude - Arithmetic Ability Questions

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