6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Find the odd word/letters/number from the given alternatives.

A) Potato	B) Tomato
C) Ginger	D) Carrot

Answer & Explanation Answer: B) Tomato

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

0 29037

Q:

The least number that must be subtracted from 7577 to get a perfect square is

A) 7	B) 6
C) 5	D) 8

Answer & Explanation Answer: D) 8

Explanation:

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Filed Under: Problems on Numbers
Exam Prep: Bank Exams

4 28972

Q:

Entry fee in an exhibition was Rs. 1. Later, this was reduced by 25% which increased the sale by 20%. The percentage increase in the number of visitors is :

A) 20 %	B) 40 %
C) 60 %	D) 80 %

Answer & Explanation Answer: C) 60 %

Explanation:

Let the total original sale be Rs. 100. Then, original number of visitors = 100.

New number of visitors = 120/0.75 = 160.

Increase % = 60 %.

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Filed Under: Percentage

95 28966

Q:

The average temperature of the town in the first four days of a month was 58 degrees. The average for the second, third, fourth and fifth days was 60 degrees. If the temperatures of the first and fifth days were in the ratio 7 : 8, then what is the temperature on the fifth day ?

A) 62 degrees	B) 64 degrees
C) 65 degrees	D) 66 degrees

Answer & Explanation Answer: B) 64 degrees

Explanation:

Sum of temperatures on 1st, 2nd, 3rd and 4th days = (58 * 4) = 232 degrees ... (1)

Sum of temperatures on 2nd, 3rd, 4th and 5th days - (60 * 4) = 240 degrees ....(2)

Subtracting (1) From (2), we get :

Temp, on 5th day - Temp on 1st day = 8 degrees.

Let the temperatures on 1st and 5th days be 7x and 8x degrees respectively.

Then, 8x - 7x = 8 or x = 8.

Temperature on the 5th day = 8x = 64 degrees.

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Filed Under: Average

56 28961

Q:

The length of a diagonal in cm of a rectangle of length 9 cm and width 5 cm is

A) 106	B) ±106
C) 2√14	D) ±214

Answer & Explanation Answer: A) 106

Explanation:

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Filed Under: Area
Exam Prep: Bank Exams

1 28958

Q:

The base of a triangular field is three times its altitude. If the cost of cultivating the field at Rs. 24.68 per hectare be Rs. 333.18, find its base and height.

A) B=900;H=300	B) B=300;H=900
C) B=600;H=700	D) B=500;H=900

Answer & Explanation Answer: A) B=900;H=300

Explanation:

Area of the field = Total cost/rate = (333.18/25.6) = 13.5 hectares
$13.5 * 10000 m^{2} = 135000 m^{2}$
Let altitude = x metres and base = 3x metres.
Then, $\frac{1}{2} * 3 x * x = 135000 \Rightarrow x^{2} = 90000 \Rightarrow x = 300$

Base = 900 m and Altitude = 300 m.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

62 28934

Q:

For any two real numbers a and b.

$\sqrt{{(a - b)}^{2}} + \sqrt{{(b - a)}^{2}}$ is

A) always zero	B) never zero
C) positive only if a ≠ b	D) positive if an only if a > b

Answer & Explanation Answer: C) positive only if a ≠ b

Explanation:

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams

1 28898

Q:

In the following question, select the odd word from the given alternatives.

A) Register	B) Pen
C) Pencil	D) Writer

Quantitative Aptitude - Arithmetic Ability Questions

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