6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A rectangular plot measuring 90 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed?

A) 65m	B) 45m
C) 55m	D) 56m

Answer & Explanation Answer: D) 56m

Explanation:

perimeter of the plot = 2(90+50) = 280m
no of poles =280/5 =56m

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Filed Under: Area
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19 26915

Q:

Consider the following statements:

1) The perimeter of a triangle is greater than the sum of its three medinas.

2) In any triangle ABC, if D is any point on BC, then AB + BC + CA > 2AD.

Which of the above statements is/are correct?

A) 1 only	B) 2 only
C) Both 1 and 2	D) Neither 1 nor 2

Answer & Explanation Answer: C) Both 1 and 2

Explanation:

Let ABC be the triangle and D. E and F are midpoints of BC, CA and AB respectively.

Recall that the sum of two sides of a triangle is greater than twice the median bisecting the third side,(Theorem to be remembered)

Hence in ΔABD, AD is a median

⇒

AB + AC > 2(AD)

Similarly, we get

BC + AC > 2CF

BC + AB > 2BE

On adding the above inequations, we get

(AB + AC) + (BC + AC) + (BC + AB )> 2AD + 2CD + 2BE

2(AB + BC + AC) > 2(AD + BE + CF)

∴

AB + BC + AC > AD + BE +CF

2.

To prove: AB + BC + CA > 2AD

Construction: AD is joined

Proof: In triangle ABD,

AB + BD > AD [because, the sum of any two sides of a triangle is always greater than the

third side]

----

1

In triangle ADC,

AC + DC > AD [because, the sum of any two

sides of a tri

angle is always greater than the

third side]

----

2

Adding 1 and 2 we get,

AB + BD + AC + DC > AD + AD

=> AB + (BD + DC) + AC > 2AD

=> AB + BC + AC > 2AD

Hence proved

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Filed Under: Volume and Surface Area
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1 26901

Q:

Select the pair that does NOT belong in the following group.

$(\sqrt{64}, 9), (\sqrt{81}, 10), (\sqrt{36}, 8), (\sqrt{121}, 12)$

A) 121, 12	B) 36, 8
C) 81, 10	D) 64, 9

Answer & Explanation Answer: B) 36, 8

Explanation:

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Filed Under: Odd Man Out
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0 26885

Q:

In the following question, select the odd word pair from the given alternatives.

A) Cup – Tea	B) Jug – Water
C) Bowl – Curd	D) Pen – Butter

Answer & Explanation Answer: D) Pen – Butter

Explanation:

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0 26825

Q:

A boat sails 15 km of a river towards upstream in 5 hours. How long will it take to cover the same distance downstream, if the speed of current is one-fourth the speed of the boat in still water:

A) 1.8h	B) 3h
C) 4h	D) 5h

Answer & Explanation Answer: B) 3h

Explanation:

Upstream speed = B-S

Downstream speed = B+s

B-S = 15/5 = 3 km/h

Again B= 4S

Therefore B-S = 3= 3S

=> S = 1 and B= 4 km/h

Therefore B+S = 5km/h

Therefore, Time during downstream = 15/5 = 3h

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Filed Under: Boats and Streams

126 26818

Q:

In the following question, select the odd letter/letters from the given alternatives.

A) PNLJ	B) USQO
C) MKIG	D) QNKH

Answer & Explanation Answer: D) QNKH

Explanation:

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2 26807

Q:

A room is half as long again as it is broad. The cost of carpeting the at Rs. 5 per sq.m is Rs. 270 and the cost of papering the four walls at Rs. 10 per sq.m is Rs. 1720. If a door and 2 windows occupy 8 sq. m, find the dimensions of the room.

A) b=6; l=18; H=6	B) b=5; l=6; H=18
C) l=6; b=18; H=15	D) l=5; b=18; H=18

Answer & Explanation Answer: A) b=6; l=18; H=6

Explanation:

Let breadth = x metres, length = 3x metres, height = H metres.

Area of the floor=(Total cost of carpeting)/(Rate) = (270/5) sq.m = 54 sq.m

$x \times \frac{3 x}{2} = 54 \Rightarrow x^{2} = 54 \times 2 \Rightarrow x = 6$

So, breadth = 6 m and length = $\frac{3 (6)}{2}$ = 9 m.

Now, papered area = (1720/10) = 172 sq.m

Area of 1 door and 2 windows = 8 sq.m

Total area of 4 walls = (172 + 8) sq.m = 180 sq.m

$2 \times (9 + 6) H = 180 \Rightarrow H = 6$

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Filed Under: Area
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33 26739

Q:

Select the odd figure out of the given series.

A) 2	B) 3
C) 4	D) 1

Quantitative Aptitude - Arithmetic Ability Questions

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