6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A number is increased by 20% and then decreased by 20%, the final value of the number is ?

A) increase by 2%	B) decrease by 3%
C) decrease by 4%	D) increase by 5%

Answer & Explanation Answer: C) decrease by 4%

Explanation:

Here, x = 20 and y = - 20
Therefore, the net % change in value
= $x + y + \frac{x y}{100}$ %
= $20 + (- 20) + \frac{20 \times - 20}{100}$ % or - 4%

Since the sign is negative, there is a decrease in value by 4%.

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Filed Under: Percentage
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34 21331

Q:

An agent, gets a commission of 2.5% on the sales of cloth. If on a certain day, he gets Rs. 12.50 as commission, the cloth sold through him on that day is worth

A) 300	B) 500
C) 700	D) 900

Answer & Explanation Answer: B) 500

Explanation:

Let the total sale be Rs. x.

Then, 2.5%. of x = 12.50

=> (25/100 * 1/100 * x) = 125/10

=> x = 500.

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Filed Under: Percentage

31 21315

Q:

A cistern has a leak which would empty the cistern in 20 minutes. A tap is turned on which admits 4 liters a minute into the cistern, and it is emptied in 24 minutes. How many liters does the cistern hold ?

A) 360 lit	B) 480 lit
C) 320 lit	D) 420 lit

Answer & Explanation Answer: B) 480 lit

Explanation:

1/k - 1/20 = -1/24

k = 120

120 x 4 = 480

Therefore, the capacity of the cistern is 480 liters.

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Filed Under: Pipes and Cistern
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15 21203

Q:

A milk man has 20 liters of milk. If he mixes 5 liters of water, which is freely available, in 20 liters of pure milk.If the cost of pure milk is Rs.18 per liter,then the profit of the milkman, when he sells all the mixture at cost price is:

A) 20%	B) 25%
C) 33.33%	D) 18%

Answer & Explanation Answer: B) 25%

Explanation:

when the water is freely available and all the water is sold at the price of the milk, then the water gives the profit on the cost of 20 liters of milk.

Therefore, profit percentage = (5/20) x 100 =25 % [ Profit %= (Profit/C.P)*100]

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Filed Under: Profit and Loss

55 21151

Q:

In a competitive exam, the number of passed students was four times the number of failed students. If there had been 35 fewer appeared students and 9 more had failed, the ratio of passed and failed students would have been 2 : 1, then the total number of students appered for the exam ?

A) 175	B) 165
C) 155	D) 145

Answer & Explanation Answer: C) 155

Explanation:

Let the number of failed students be x

=> Number of passed students = 4x

So total number of students was 5x

From the given data,

If total number of students be 5x – 35

=> 4x-35-9/x+9 = 2/1

=> 4x – 44 = 2(x + 9)

=> 4x – 2x = 18 + 44

=> x = 31

Total number = 31×5

= 155

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Filed Under: Ratios and Proportions
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43 21107

Q:

A,B and C enter into a partnership in the ratio $\frac{7}{2} : \frac{4}{3} : \frac{6}{5}$ . After 4 months, A increases his share by 50%. If the total profit at the end of one year be Rs. 21600, then B's share in the profit is :

A) Rs. 4000	B) Rs. 6000
C) Rs. 9000	D) Rs. 3000

Answer & Explanation Answer: A) Rs. 4000

Explanation:

Given ratio of initial investments = $\frac{7}{2} : \frac{4}{3} : \frac{6}{5}$ = 105 : 40 : 36.

Let the initial investments be 105x, 40x and 36x.

$∴ A : B : C = (105 x \times 4 + \frac{150}{100} \times 105 x \times 8) : (40 x \times 12) : (36 x \times 12)$

= 1680x : 480x : 432x = 35 : 10 : 9.

Hence, B's share = $(21600 \times \frac{10}{54})$ = Rs. 4000.

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Filed Under: Partnership
Exam Prep: CAT
Job Role: Bank PO

18 21071

Q:

A sum of money invested for a certain number of years at 8% p.a. simple interest grows to Rs.180. The same sum of money invested for the same number of years at 4% p.a. simple interest grows to Rs.120 only. For how many years was the sum invested?

A) 25years	B) 15years
C) 20years	D) 22years

Answer & Explanation Answer: A) 25years

Explanation:

From the information provided we know that,

Principal + 8% p.a. interest on principal for n years = 180 …….. (1)

Principal + 4% p.a. interest on principal for n years = 120 ……… (2)

Subtracting equation (2) from equation (1), we get

4% p.a. interest on principal for n years = Rs.60.

Now, we can substitute this value in equation (2),

i.e Principal + 60 = 120

= Principal = Rs.60.

We know that SI = , where p is the principal, n the number of years and r the rate percent of interest.

In equation (2), p = Rs.60, r = 4% p.a. and the simple interest = Rs.60.

Therefore, 60 =(60*n*4)/100

=> n = 100/4 = 25 years.

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Filed Under: Simple Interest
Exam Prep: Bank Exams
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17 21065

Q:

A rectangular grassy plot 110m by 65cm has a gravel path .5cm wide all round it on the inside. Find the cost of gravelling the path at 80 paise per sq.mt

A) 680rs	B) 480rs
C) 340rs	D) 320rs

Answer & Explanation Answer: A) 680rs

Explanation:

area of theplot = 110 * 65 = 7150 sq.m
area of the plot excluding the path = (110-5)* (65-5) = 6300 sq.m
area of the path = 7150 - 6300 =850 sq.m
cost of gravelling the path = 850 x (80/100) = 680 Rs

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

11 21050

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