Quantitative Aptitude - Arithmetic Ability Questions

Q:

Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?

A) 3/4 B) 3/8
C) 5/16 D) 2/7
 
Answer & Explanation Answer: A) 3/4

Explanation:

In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.

Then, E= {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3,4),(3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1),6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

n(E) = 27.

P(E) = n(E)/n(S) = 27/36 = 3/4.

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Filed Under: Probability

44 20353
Q:

3 : 12 :: 5 : ?

A) 17 B) 30
C) 26 D) 32
 
Answer & Explanation Answer: B) 30

Explanation:

332 + 3 = 12552 + 5 = 30

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Filed Under: Ratios and Proportions
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

78 20334
Q:

A can give B 100 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race?

A) 110.12 meters B) 111.12 meters
C) 112.12 meters D) 113.12 meters
 
Answer & Explanation Answer: B) 111.12 meters

Explanation:

A runs 1000 meters while B runs 900 meters and C runs 800 meters.

Therefore, B runs 900 meters while C runs 800 meters.

So, the number of meters that C runs when B runs 1000 meters = (1000 x 800)/900 = 8000/9 = 888.88 meters

Thus, B can give C (1000 - 888.88) = 111.12 meters start

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Filed Under: Races and Games

22 20312
Q:

When A, B and C are deployed for a task , A and B together do 70% of the work and B and C together do 50% of the work. who is most efficient?

A) A B) B
C) C D) can't be determined
 
Answer & Explanation Answer: A) A

Explanation:

A + B= 70%   

B + C =50%   

  (A+B)+(B+C)-(A+B+C)= B

=> B= 20%     A= 50%        and   C=30%

Hence A is most efficient

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Filed Under: Time and Work

31 20255
Q:

Taps X and Y can fill a tank in 30 and 40 minutes respectively.Tap Z can empty the filled tank in 60 minutes.If all the three taps are kept open for one minute each,how much time will the taps take to fill the tank?

A) 48min B) 72min
C) 24min D) None of these
 
Answer & Explanation Answer: C) 24min

Explanation:

Given taps X and Y can fill the tank in 30 and 40 minutes respectively. Therefore,

 

part filled by tap X in 1 minute = 1/30

 

part filled by tap Y in 1 minute = 1/40

 

Tap Z can empty the tank in 60 minutes. Therefore,

 

part emptied by tap Z in 1 minute = 1/60

 

Net part filled by Pipes X,Y,Z together in 1 minute = [1/30 +1/40 - 1/60] = 5/120 = 1/24

 

i.e., the tank can be filled in 24 minutes.

 

 

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Filed Under: Pipes and Cistern
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

25 20207
Q:

Find the total surface area (in cm2) of a hemisphere of diameter 21 cm.

 

A) 1039.5   B) 844.5  
C) 637   D) 472
 
Answer & Explanation Answer: A) 1039.5  

Explanation:
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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

2 20206
Q:

Find the appropriate relation for quantity1 and quantity2 in the following question:

Quantity 1: In an examination, Ankita scored 35 marks less than Puneeta. Puneeta scored 65 more marks than Meenakshi. Rakhi scored 115 marks, which is 20 marks more than Meenakshi's. Simpy scored 108 marks less than the maximum marks of the test. What approximate percentage of marks did Simpy score in the examination, if she got 67 marks more than Ankita?

Quantity 2: The length of a rectangle is increased by 60%. By what percent would the width have to be decreased to maintain the same area?

A) Quantity1 < Quantity2 B) Quantity1 ≤ Quantity2
C) Quantity1 ≥ Quantity2 D) Quantity1 > Quantity2
 
Answer & Explanation Answer: D) Quantity1 > Quantity2

Explanation:

Quantity1-
Rakhi’s marks= 115
Meenakshi’s marks= 115 - 20 = 95
Puneeta’s marks= 95 + 65= 160
Ankita’s marks=160 - 35= 125
Simpy’s marks= 125+ 67= 192
Total maximum marks= 192 + 108= 300
Required percentage marks of Simpy
192300×100=64%
Quantity2-
Let length and breadth be 100.

After increase in length it become 160, then
reduction in breadth be ‘x’
Now, 160*x= 100*100
Hence, x = 10000160=62.5

100-62.5=37.5%

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2 20184
Q:

Find the unit digit of 4198 + 612345 + 34866 + 2411 + 1.

A) 3 B) 2
C) 1 D) 0
 
Answer & Explanation Answer: C) 1

Explanation:

Given that, 4198+612345+34866+2411+1


Now Power Cycle of

4 is 4, 6 

6 is 6 

8 is 8, 4, 2, 6

1 is 1

 

4198- 198 is even number , So the unit digit value is 6 

 

612345 - It is always 6

 

34866-  66/4 the remainder is 2 , So the second value is 4

 

2411- 11 is odd number, So the unit digit value is 4

 

1 - It is always 1 


Total = 21

 

Therefore, The unit digit is 1

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Filed Under: Numbers
Exam Prep: CAT
Job Role: Bank PO

26 20178