6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

If a number 657423547X46 is divisible by 11, then find the value of X.

A) 7	B) 9
C) 8	D) 6

Answer & Explanation Answer: B) 9

Explanation:

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Filed Under: Problems on Numbers
Exam Prep: Bank Exams

1 20187

Q:

At what time, in minutes, between 3 o'clock and 4 o'clock, both the needles will coincide each other?

A. $5 \frac{1}{11}$

B. $15 \frac{4}{15}$

C. $16 \frac{4}{11}$

D. $4 \frac{4}{15}$

A) Option A	B) Option B
C) Option C	D) Option D

Answer & Explanation Answer: C) Option C

Explanation:

At 3 o'clock, the minute hand is 15 min. spaces apart from the hour hand.

To be coincident, it must gain 15 min. spaces.

55 min. are gained in 60 min.

Then 15 min spaces are gained in = $\frac{60}{55} \times 15$ min.

Therefore, The hands are coincident at $16 \frac{4}{11}$ min. past 3 o'clock.

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Filed Under: Clocks
Exam Prep: Bank Exams
Job Role: Bank Clerk

18 20138

Q:

The probability of success of three students X, Y and Z in the one examination are 1/5, 1/4 and 1/3 respectively. Find the probability of success of at least two.

A) 1/4	B) 1/2
C) 1/6	D) 1/3

Answer & Explanation Answer: C) 1/6

Explanation:

P(X) = $\frac{1}{5}$ , P(Y) = $\frac{1}{4}$ , P(Z) = $\frac{1}{3}$

Required probability:

= [ P(A)P(B){1−P(C)} ] + [ {1−P(A)}P(B)P(C) ] + [ P(A)P(C){1−P(B)} ] + P(A)P(B)P(C)

= $(\frac{1}{4} * \frac{1}{3} * \frac{4}{5}) + (\frac{3}{4} * \frac{1}{3} * \frac{1}{5}) + (\frac{2}{3} * \frac{1}{4} * \frac{1}{5}) + (\frac{1}{4} * \frac{1}{3} * \frac{1}{5})$

= $\frac{4}{60} + \frac{3}{60} + \frac{2}{60} + \frac{1}{60}$ = $\frac{10}{60}$ = $\frac{1}{6}$

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Filed Under: Probability

19 20134

Q:

How many window coverings are necessary to span 50 windows, if each window covering is 15 windows long?

A) 4	B) 15
C) 3	D) 50

Answer & Explanation Answer: A) 4

Explanation:

Given that,

Number of windows = 50

Each window covering covers 15 windows

=> 50 windows requires 50/15 window coverings

= 50/15 = 3.333

Hence, more than 3 window coverings are required. In the options 4 is more than 3.

Hence, 4 window coverings are required to cover 50 windows of each covering covers 15 windows.

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Filed Under: Average
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

13 20105

Q:

The no of revolutions a wheel of diameter 40cm makes in traveling a distance of 176m is

A) 240	B) 140
C) 40	D) 340

Answer & Explanation Answer: B) 140

Explanation:

distance covered in 1 revolution = $2 πr$ = 2 x (22/7) x 20 = 880/7 cm
required no of revolutions = 17600 x (7/880) = 140

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

21 20072

Q:

The breadth of a rectangular field is 60% of its length. If the perimeter of the field is 800 m.What is the area of the field?

A) 47500	B) 37500
C) 57500	D) 77500

Answer & Explanation Answer: B) 37500

Explanation:

Let length = x meters, then breadth = 0.6x

Given that perimeter = 800 meters

=> 2[ x + 0.6x] = 800

=> x = 250 m

Length = 250m and breadth = 0.6 x 250 = 150m

Area = 250 x 150 = 37500 sq.m

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

19 20063

Q:

Find the appropriate relation for quantity 1 and quantity 2 in the following question:

An artificial kund is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the kund at the same time during which the kund is filled by the third pipe alone. The second pipe fills the kund 5 hours faster than the first pipe and 4 hours slower than the third pipe.

Quantity 1: The time required by the first pipe?

Quantity 2: Time taken by all three pipes to fill the Kund simultaneously

A) Quantity 1 > Quantity 2	B) Quantity 1 ≥ Quantity 2
C) Quantity 1 < Quantity 2	D) Quantity 1 ≤ Quantity 2

Answer & Explanation Answer: A) Quantity 1 > Quantity 2

Explanation:

Quantity 1:
Let the first pipe alone takes x hours to fill the
tank.
⇒The second and third pipes will take (x-5) and
(x-9) hours respectively.
According to the given information:
∴ $\frac{1}{x - 9}$

⇒ (x-9)(2x-5) = x2 – 5x
⇒ 2x2 – 5x – 18x + 45 = x2 – 5x
⇒ x
2 -18x + 45 = 0
⇒ (x-15) (x-3) = 0
⇒ x = 15, 3

The first pipe can take 15 hours to fill the kund.
∵ 3 hours doesn’t satisfy the statement.
Quantity 2:
∴ Time taken by second pipe = x-5
⇒ Time taken by second pipe = 15-5 = 10hours
∴ Time taken by third pipe = x -9
⇒ Time taken by third pipe = 15- 9 = 6 hours
Now,

Net part filled in 1 hour = $\frac{1}{15} + \frac{1}{10} + \frac{1}{6}$
⇒ Net part filled in 1 hour = $\frac{4 + 6 + 10}{60}$
⇒Net part filled in 1 hour = $\frac{20}{60} = \frac{1}{3}$
∴The Kund will be full in 3/1 hours if all the pipes are opened simultaneously
Now, comparing
15 > 3
Thus, Quantity 1 > quantity 2