6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

If every seconds Saturday and all Sundays are holidays in a 30 days month beginning on Saturday, then how many working days are there in that month ? (Month starts from Saturday)

A) 25	B) 22
C) 24	D) 23

Answer & Explanation Answer: D) 23

Explanation:

As month begins on Saturday, so 2nd, 9th, 16th, 23rd, 30th days will be Sundays. While 8th and 22nd days are second Saturdays. Thus, there are 7 holidays in all.

Hence, no. of working days = 30 – 7 =23

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Filed Under: Calendar
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55 17971

Q:

If log 64 = 1.8061, then the value of log 16 will be (approx)?

A) 1.9048	B) 1.2040
C) 0.9840	D) 1.4521

Answer & Explanation Answer: B) 1.2040

Explanation:

Given that, log 64 = 1.8061

i.e $\log (4^{3}) = 1.8061$

--> 3 log 4 = 1.8061

--> log 4 = 0.6020

--> 2 log 4 = 1.2040

$\Rightarrow \log (4^{2}) = 1.2040$

Therefore, log 16 = 1.2040

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Filed Under: Logarithms
Exam Prep: CAT
Job Role: Bank Clerk

51 17932

Q:

What will come in place of the question mark in the series below?

3, 5, 15, 45, 113, ?

A) 250	B) 243
C) 247	D) 261

Answer & Explanation Answer: B) 243

Explanation:

Ans.
5 = 3 + (13 + 1)
15 = 5 + (23 + 2)
45 = 15 + (33 + 3)
113 = 45 + (43 + 4)
? = 113 + (53 + 5), i.e. ? = 243

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Filed Under: Numbers
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0 17931

Q:

A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered.If the area of the field is 680 sq.ft, how many feet of fencing will be required?

A) 44ft	B) 88ft
C) 22ft	D) 11ft

Answer & Explanation Answer: B) 88ft

Explanation:

Given that length and area, so we can find the breadth.

Length x Breadth = Area

=> 20 x Breadth = 680

=> Breadth = 34 feet

Area to be fenced = 2B + L = 2 (34) + 20 = 88 feet

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

18 17930

Q:

Milk and water are mixed in a vessel A as 4:1 and in vessel B as 3:2. For vessel C, if one takes equal quantities from A and B, find the ratio of milk to water in C.

A) 1:9	B) 9:1
C) 3:7	D) 7:3

Answer & Explanation Answer: D) 7:3

Explanation:

Ratio of Milk and water in a vessel A is 4 : 1

Ratio of Milk and water in a vessel B is 3 : 2

Ratio of only milk in vessel A = 4 : 5

Ratio of only milk in vessel B = 3 : 5

Let 'x' be the quantity of milk in vessel C

Now as equal quantities are taken out from both vessels A & B

=> 4/5 : 3/5
x
3/5-x x - 4/5

=> $\frac{\frac{3}{5} - x}{x - \frac{4}{5}}$ = $\frac{1}{1}$ (equal quantities)

=> x = 7/10

Therefore, quantity of milk in vessel C = 7

=> Water quantity = 10 - 7 = 3

Hence the ratio of milk & water in vessel 3 is 7 : 3

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Filed Under: Alligation or Mixture
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33 17921

Q:

The amount of water (in ml) that should be added to reduce 9 ml lotion, containing 50% alcohol, to a lotion containing 30% alcohol is ?

A) 6 ml	B) 11 ml
C) 15 ml	D) 9 ml

Answer & Explanation Answer: A) 6 ml

Explanation:

Let us assume that the lotion has 50% alcohol and 50% water.
ratio = 1:1
As the total solution is 9ml
alcohol = water = 4.5ml
Now if we want the quantity of alcohol = 30%
The quantity of water = 70%
The new ratio = 3:7
Let x ml of water be added
We get,
$\frac{4.5}{4.5 + x} = \frac{3}{7}$
=> x=6
Hence 6ml of water is added.

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Filed Under: Alligation or Mixture
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30 17899

Q:

There are 6 bowlers and 9 batsmen in a cricket club. In how many ways can a team of 11 be selected so that the team contains at least 4 bowlers?

A) 1170	B) 1200
C) 720	D) 360

Answer & Explanation Answer: A) 1170

Explanation:

Possibilities Bowlers Batsmen Number of ways

6 9

1 4 7 $(6 C_{4} * 9 C_{7})$

2 5 6 $(6 C_{5} * 9 C_{6})$

3 6 5 $(6 C_{6} * 9 C_{5})$

$(6 C_{4} * 9 C_{7})$ = 15 x 36 = 540

$(6 C_{5} * 9 C_{6})$ = 6 x 84 = 504

$(6 C_{6} * 9 C_{5})$ = 1 x 126 = 126

Total = 1170

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Filed Under: Permutations and Combinations

15 17896

Q:

A train covers a distance between station A and station B in 45 min.If the speed of the train is reduced by 5 km/hr,then the same distance is covered in 48 min.what is the distance between the stations A and B ?

A) 80 kms	B) 60 kms
C) 45 kms	D) 32 kms

Answer & Explanation Answer: B) 60 kms

Explanation:

Let 'd' be the distance and 's' be the speed and 't' be the time
d=sxt
45 mins = 3/4 hr and 48 mins = 4/5 hr
As distance is same in both cases;
s(3/4) = (s-5)(4/5)
3s/4 = (4s-20)/5
15s = 16s-80
s = 80 km.
=> d = 80 x 3/4 = 60 kms.

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Filed Under: Problems on Trains
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19 17883

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