Quantitative Aptitude - Arithmetic Ability Questions

The possible outcomes are as follows :

5H, 5T, (H, 4T), (T, 4H), (2H, 3T) (3H, 2T), i.e. 6 outcomes in all.

Therefore the probability that head appears an odd number of times = 3/6 =1/2 (In only three outcomes out of the six outcomes, head appears an odd number of times).

To earn Rs. 10, money invested = Rs. 100.

To earn Rs. 12, money invested =Rs.10010*12 = Rs. 120.

Market value of Rs. 100 stock = Rs. 120.

(5m + 9w)10 = (6m + 12w)8 

=> 50m + 90w = 48w + 96 w    => 1m = 3w

5m + 9w = 5m + 3m = 8m

8 men can do the work in 10 days.

3m +3w = 3m + 1w = 4m

So, 4 men can do the work in (10 x 8)/4 = 20 days.

u = k , v= 3k 

∴2uvu+v ⇒2×k×3kk+3k=12  => k = 8km/h

First,we count the number of odd days for the left over days in the given period.Here,given period is 09-07-2013 to 07-01-2014

 Therefore, No. of Odd Days =  1 + 3 + 2 + 3 + 2 + 3 + 0 = 14 = 0 odd days

So, given day Sunday + 0 = Saturday is the required result.

Let the diagonals of the squares be 2x and 5x respectively.
Ratio of their areas =  12*2x2:12*5x2=4:25

perimeter of window = πr+2r 

= [(22/7) x (63/2) + 63] = 99+63 = 162 cm

Relative Speed = 60 -40 = 20 x 5/18 = 100/18

Time = 50

Distance = 50 x 100/18 = 2500/9

Relative Speed = 60 + 40 = 100 x 5/18

Time = 2500/9 x 18/500 = 10 sec.