6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

In a palace, three different types of coins are there namely gold, silver and bronze. The number of gold, silver and bronze coins is 18000, 9600 and 3600 respectively. Find the minimum number of rooms required if in each room should give the same number of coins of the same type ?

A) 26	B) 24
C) 18	D) 12

Answer & Explanation Answer: A) 26

Explanation:

Gold coins = 18000 , Silver coins = 9600 , Bronze coins = 3600

Find a number which exactly divide all these numbers

That is HCF of 18000, 9600& 3600

All the value has 00 at end so the factor will also have 00.

HCF for 180, 96 & 36.

Factors of

180 = 3 x 3 x 5 x 2 x 2

96 = 2 x 2 x 2 x 2 x 2 x 3

36 = 2 x 2 x 3 x 3

Common factors are 2x2×3=12

Therefore, Actual HCF is 1200

Gold Coins 18000/1200 will be in 15 rooms

Silver Coins 9600/1200 will be in 8 rooms

Bronze Coins 3600/1200 will be in 3 rooms

Total rooms will be (15+8+3) = 26 rooms.

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Filed Under: HCF and LCM
Exam Prep: CAT
Job Role: Bank Clerk

13 13359

Q:

What will be compounded amount?
I. Rs. 200 was borrowed for 192 months at 6% compounded annually.
II. Rs. 200 was borrowed for 16 years at 6%.

A) I alone sufficient while II alone not sufficient to answer	B) II alone sufficient while I alone not sufficient to answer
C) Either I or II alone sufficient to answer	D) Both I and II are not sufficient to answer

Answer & Explanation Answer: C) Either I or II alone sufficient to answer

Explanation:

I. Amount = $R s . [200 * {(1 + \frac{6}{100})}^{16}]$

II. Amount = $R s [200 * {(1 + \frac{6}{100})}^{16}]$

Thus, I as well as II gives the answer.

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

2 13352

Q:

If 50 is subtracted from two-third of a number, the result is equal to sum of 40 and one-fourth of that number. What is the number ?

A) 156	B) 179
C) 198	D) 216

Answer & Explanation Answer: D) 216

Explanation:

Let the number be x.

Then, 2/3x-50 = 1/4x +50

=> 5/12x = 90

x = (90 x 12) / 5 = 216

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Filed Under: Problems on Numbers

6 13343

Q:

If $3 x + 7 = x^{2} + p = 7 x + 5$ , what is the value of P ?

A) 17/2	B) 25/3
C) 33/4	D) 41/5

Answer & Explanation Answer: A) 17/2

Explanation:

$3 x + 7 = 7 x + 5 = > 7 x - 3 x = 2 = > 4 x = 2 = > x = 2$

Now, $3 x + 7 = x^{2} + p = \frac{3}{2} + 7 = \frac{1}{4} + p = > p = \frac{17}{2}$

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Filed Under: Simplification

11 13321

Q:

In Veeru Bhai Pvt.limited company 60% of the employees are men and 48% of the employees are Engineer and 66.6% of these are men. The percentage of women who are not engineers:

A) 33.33%	B) 60%
C) 52%	D) 46.66%

Answer & Explanation Answer: B) 60%

Explanation:

Men Women

600x 400x

Total engineers = 480x

Male engineers = 480x X 0.66 = 320

Women who are Engineers = 160x

Women are not Engineers = 400x - 160x = 240x

Required percentage = $\frac{240}{400} x 100$ = 60%

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

14 13307

Q:

In How many ways is it possible to make a selection by taking any number of 15 fruits, namely 3 oranges, 5 apples and 7 mangoes?

A) 131	B) 191
C) 68	D) 3720

Answer & Explanation Answer: B) 191

Explanation:

Out of 15 fruits, 7 are alike of one kind, 5 are alike of a second kind and 3 are alike of a third kind.

Hence, the required number of ways = [ (7+1) (5+1) (3+1) -1] =191

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Filed Under: Permutations and Combinations

19 13307

Q:

If a box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains no defective bulbs.

A) 5/12	B) 7/12
C) 3/14	D) 1/12

Answer & Explanation Answer: D) 1/12

Explanation:

Total number of elementary events = $10 C_{5}$

Number of ways of selecting no defective bulbs i.e., 5 non-defective bulbs out of 7 is $7 C_{5}$ .

So,required probability = $7 C_{5}$ / $10 C_{5}$ = 1/12.

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Filed Under: Probability

20 13262

Q:

The highest score in an inning was 3/11 of the total and the next highest was 3/11 of the reminder . If the score differ by 9, the total score was :

A) 110	B) 121
C) 132	D) 143

Answer & Explanation Answer: B) 121

Explanation:

Let the score be x. Then the highest score = 3x/11.

Reminder = (x - 3x/11) = 8x/11 .Next the highest score = 3/11 of 8x/11 = 24x/121.

Quantitative Aptitude - Arithmetic Ability Questions

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