Quantitative Aptitude - Arithmetic Ability Questions

Q:

Water flows into a tank 200 m x 160 m through a rectangular pipe of 1.5m x 1.25 m @ 20 kmph . In what time (in minutes) will the water rise by 2 meters?

A) 92min B) 93min
C) 95min D) 96min
 
Answer & Explanation Answer: D) 96min

Explanation:

Volume required in the tank = (200 x 150 x 2) cu.m = 60000 cu.m 

Length of water column flown in1 min =(20 x 1000)/60 m =1000/3 m 

Volume flown per minute = 1.5 x 1.25 x (1000/3) cu.m= 625 cu.m. 

Required time = (60000/625)min = 96min

Report Error

View Answer Report Error Discuss

12 12994
Q:

In how many ways can an animal trainer arrange 5 lions and 4 tigers in a row so that no two lions are together?

A) 2800 B) 2880
C) 2600 D) 3980
 
Answer & Explanation Answer: B) 2880

Explanation:

They have to be arranged in the following way :

                                                                    L  T  L  T  L  T  L  T  L

The 5 lions should be arranged in the 5 places marked ‘L’.

This can be done in 5! ways.

The 4 tigers should be in the 4 places marked ‘T’.

This can be done in 4! ways.

Therefore, the lions and the tigers can be arranged in 5!´ 4! ways = 2880 ways.

Report Error

View Answer Report Error Discuss

5 12989
Q:

The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero ?

A) 14th element B) 9th element
C) 12th element D) 7th element
 
Answer & Explanation Answer: C) 12th element

Explanation:

If we consider the third term to be ‘x”
The 15th term will be (x + 12d)
6th term will be (x + 3d)
11th term will be (x + 8d) and
13th term will be (x + 10d).
Thus, as per the given condition, 2x + 12d = 3x + 21d.Or x + 9d = 0.
x + 9d will be the 12th term.

Thus, 12th term of the A.P will be zero.

Report Error

View Answer Report Error Discuss

Filed Under: Chain Rule
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

35 12972
Q:

In how many different ways can the letters of the word 'CORPORATION' be arranged so that the vowels always come together

A) 50000 B) 40500
C) 5040 D) 50400
 
Answer & Explanation Answer: D) 50400

Explanation:

In the word 'CORPORATION', we treat the vowels OOAIO as one letter.

 

Thus, we have CRPRTN (OOAIO).

 

This has 7 (6 + 1) letters of which R occurs 2 times and the rest are different.

 

Number of ways arranging these letters =7!/2!= 2520.

 

Now, 5 vowels in which O occurs 3 times and the rest are different, can be arranged in 3!/5!= 20 ways.

 

Required number of ways = (2520 x 20) = 50400.

Report Error

View Answer Report Error Discuss

1 12967
Q:

When a women sells 20 articles for Rs. 160, there is 40% loss. How many articles should she sell for Rs. 240 in order to earn 20% profit ?

A) 16 B) 15
C) 17 D) 14
 
Answer & Explanation Answer: B) 15

Explanation:

Given when she sells at Rs. 160 for 20 articles, she get 40% loss.

 

Then, to get 20% profit selling at Rs. 240 for let 'P' articles

 

=> 1602060=240p120

 

=> 120 x 160 x P = 20 x 70 x 240

 

=> P =  15 articles.

Report Error

View Answer Report Error Discuss

Filed Under: Profit and Loss
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

26 12961
Q:

Helpers are needed to prepare for the fete. Each helper can make either 2 large cakes or 35 small cakes per hour. The kitchen is available for 3 hours and 20 large cakes and 700 small cakes are needed. How many helpers are required?

A) 10 B) 15
C) 20 D) 25
 
Answer & Explanation Answer: A) 10

Explanation:

20 large cakes will require the equivalent of 10 helpers working for one hour. 700 small cakes will require the equivalent of 20 helpers working for one hour. This means if only one hour were available we would need 30 helpers. But since three hours are available we can use 10 helpers.

Report Error

View Answer Report Error Discuss

Filed Under: Percentage
Exam Prep: GRE

10 12935
Q:

The calendar of year 1989 was same as which year?

A) 1978 B) 1970
C) 1980 D) 1985
 
Answer & Explanation Answer: A) 1978

Explanation:

 

Given year 1989, when divided by 4 leaves a remainder of 1.

NOTE: When remainder is 1, 11 is subtracted to the given year to get the result.

So, 1989 - 11 = 1978

 

Report Error

View Answer Report Error Discuss

Filed Under: Calendar

38 12932
Q:

The price of commodity X increases by 40 paise every year, while the price of commodity Y increases  by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity?

A) 2010 B) 2011
C) 2012 D) 2013
 
Answer & Explanation Answer: B) 2011

Explanation:

Suppose commodity X wil cost 40 paise more than Y after Z  years. Then,

        (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40

=>  0.25Z = 0.40 + 2.10  => Z= 2.50/0.25 = 10

Therefore, X will cost 40 paise more than Y 10  years after 2001 . i.e in 2011

Report Error

View Answer Report Error Discuss

Filed Under: Decimal Fractions

9 12920