Quantitative Aptitude - Arithmetic Ability Questions

Q:

Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case ?

A) 1020 B) 1040
C) 1060 D) 1022
 
Answer & Explanation Answer: D) 1022

Explanation:

Lowest 4-digit number is 1000.
LCM of 3, 4 and 5 is 60.
Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 - 40) = 1020.
Now, add the remainder 2 that's required. Thus, the answer is 1022.

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Filed Under: Problems on Numbers
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11 10318
Q:

The minimum number of half years in which a sum of money kept at 60% compound interest will be quadrupled is ?

A) 2 B) 4
C) 3 D) 6
 
Answer & Explanation Answer: D) 6

Explanation:

Let us assume Amount be 100 Rs and we calculate in CI

 First year 60% of 100 = 60 amount (100+60) is 160

 Second year 60% of 160 = 96 amount (160+96) is 256

 Third year 60% of 256 =153.6 amount (256+153.6) is 409.6

 Here the Amount of 100 Rs is quadrapled in 3 years.

 One year contains 2 half years

 Three year has 6 half years.

 Therefore,  It takes 6 half years.

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Filed Under: Compound Interest
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14 10312
Q:

An industrial loom weaves 0.128 metres of cloth every second. Approximately, how many seconds will it take for the loom to weave 25 metre of cloth ?

A) 194 seconds B) 195 seconds
C) 196 seconds D) 197seconds
 
Answer & Explanation Answer: B) 195 seconds

Explanation:

Let the time required by x seconds.

Then, More cloth means More time (Direct Proportion)

So, 0.128 : 1 :: 25 : x

x=1×250.128 => x = 195.31

 So time will be approx 195 seconds

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Filed Under: Chain Rule

7 10311
Q:

The calendar of year 1939 is same as which year?

A) 1943 B) 1964
C) 1950 D) 1956
 
Answer & Explanation Answer: C) 1950

Explanation:

Given year 1939, when divided by 4 leaves a remainder of 3.

NOTE: When remainder is 3, 11 is added to the given year to get the result.

So, 1939 + 11 = 1950

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Filed Under: Calendar

21 10298
Q:

A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. The number of days for which the remaining food will last, is:

A) 29 B) 37
C) 42 D) 54
 
Answer & Explanation Answer: C) 42

Explanation:

After 10 days : 150 men had food for 35 days.

 

Suppose 125 men had food for x days.

 

Now, Less men, More days (Indirect Proportion)

 

 125 : 150 :: 35 : x       125 x x = 150 x 35

 

 x=150×35125=42

 

 

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Filed Under: Chain Rule

16 10279
Q:

How many ways are there to select a subcommittee of 7 members from among a committee of 17?

A) 19000 B) 19448
C) 19821 D) 19340
 
Answer & Explanation Answer: B) 19448

Explanation:

Since it does not matter what order the committee members are chosen in, the combination formula is used.

 

Committees are always a combination unless the problem states that someone like a president has higher hierarchy over another person. If the committee is ordered, then it is a permutation.

 

C(17,7)= 19,448

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1 10269
Q:

Solve 30 + (.0825 x 30) + (15% x 30)

A) 24.750 B) 36.975
C) 34.652 D) 26.354
 
Answer & Explanation Answer: B) 36.975

Explanation:

30 + (.0825 x 30) + (15% x 30)

 

Now

=> 0.0825 x 30 = 2.475 -----(1)

=> 15% of 30 = 450/100 = 4.5 -----(2) 

 

Hence, from (1) & (2)

30 + (.0825 x 30) + (15% x 30)

= 30 + 2.475 + 4.5

30 + (.0825 x 30) + (15% x 30) = 36.975.

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Filed Under: Percentage
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19 10269
Q:

A man walks at a speed of 2 km/hr and runs at a speed of 6 km/hr. How much time will the man require to cover a distance of 20 1/2 km, if he completes half of the distance, i.e., (10 1/4) km on foot and the other half by running ?

A) 12.4 hrs B) 11.9 hrs
C) 10.7 hrs D) 9.9 hrs
 
Answer & Explanation Answer: B) 11.9 hrs

Explanation:

We know that

Time = Distance/speed
Required time = (10 1/4)/2 + (10 1/4)/6
= 41/8 + 41/6
= 287/24 = 11.9 hours.

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Filed Under: Time and Distance
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9 10267