Quantitative Aptitude - Arithmetic Ability Questions

A's spending 90%                 saving = 10%

B's spending 75%                 saving = 25%

C's spending 60%                 saving = 40%

Let us suppose A, B and C saves Rs. 3.5 and 6 respectively.

 10% of A's saving = Rs.3

100% of A's saving =  = Rs. 30

25% of B's saving = Rs. 5

100% of B's saving =  = Rs. 20

40% of C's saving = Rs.6

100% of C's saving =  = Rs. 15

Divide Rs. 6500 in the ratio of 30 : 20 : 15 as

A's Share  =   = Rs. 3000

B's Share   =  = Rs. 2000

C's Share  =  = Rs. 1500

Let the present ages of Arun and Harish be 4x and 3x years respectively.

Then, 4x + 6 = 26 => x = 5

Harish's age = 3x = 15 years.

Speed =[ 78 x ( 5/18 ) ] m/sec = 65/3 m/sec.

Time = 1 minute = 60 sec.

Let the length of the tunnel be x metres.

Then, [ (800 + x )/ 60 ]= 65/3

3(800 + x) = 3900

 x = 500.

Let the length of the stationary train Y be LY
Given that length of train X, LX = 300 m
Let the speed of Train X be V.
Since the train X crosses train Y and a pole in 60 seconds and 25 seconds respectively.
=> 300/V = 25 ---> ( 1 )
(300 + LY) / V = 60 ---> ( 2 )
From (1) V = 300/25 = 12 m/sec.
From (2) (300 + LY)/12 = 60
=> 300 + LY = 60 (12) = 720
=> LY = 720 - 300 = 420 m
Length of the stationary train = 420 m

Let the principle be Rs. P
As the amount double itself the interest is Rs. P too
So P = P x r x 15/100
=> r = 100/15 = 20/3 % = 6.66 %.

For an income of Rs.756, investment = Rs.9000 

For an income of Rs.212, investment = Rs.9000756*212 = Rs.125 

For a Rs.100 stock, investment = Rs.125.

Market value of Rs. 100 stock  = Rs.125-14 = Rs. 124.75

There is a meal for 200 children. 150 children have taken the meal.

Remaining meal is to be catered to 50 children.

Now, 200 children = 120 men.

50 children = 12020050 =30men