6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A drink vendor has 368 liters of Maaza, 80 liters of Pepsi and 144 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required ?

A) 47	B) 46
C) 37	D) 35

Answer & Explanation Answer: C) 37

Explanation:

The number of liters in each can = HCF of 80, 144 and 368 = 16 liters.
Number of cans of Maaza = 368/16 = 23
Number of cans of Pepsi = 80/16 = 5
Number of cans of Sprite = 144/16 = 9
The total number of cans required = 23 + 5 + 9 = 37 cans.

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Filed Under: HCF and LCM
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31 9964

Q:

Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes?

A) 5 kmph	B) 6 kmph
C) 7.5 kmph	D) 8 kmph

Answer & Explanation Answer: A) 5 kmph

Explanation:

Let p be the speed of man in kmph

According to the given data in the question,

Distance travelled by bus in 10 min with 20 kmph == Distance travelled by man in 8 min with (20 + p) kmph in opposite direction

=> 20 x 10/60 = 8/60 (20 + p)

=> 200 = 160 + 8p

=> p = 40/8 = 5 kmph.

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Filed Under: Time and Distance
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14 9904

Q:

The market value of a 10.5% stock, in which an income of Rs. 756 is derived by investing Rs. 9000, brokerage being $\frac{1}{4}$ % is :

A) Rs.108.25	B) Rs.112.20
C) Rs.124.75	D) Rs.125.25

Answer & Explanation Answer: C) Rs.124.75

Explanation:

For an income of Rs.756, investment = Rs.9000

For an income of Rs. $\frac{21}{2}$ , investment = $R s . (\frac{9000}{756} * \frac{21}{2})$ = Rs.125

For a Rs.100 stock, investment = Rs.125.

Market value of Rs. 100 stock = $R s . (125 - \frac{1}{4})$ = Rs. 124.75

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Filed Under: Stocks and Shares

4 9904

Q:

$17 \frac{4}{7} + 13 \frac{2}{12} - ? = 11 \frac{2}{3}$

A) 16	B) 17
C) 18	D) 19

Answer & Explanation Answer: D) 19

Explanation:

$17 \frac{4}{7} + 13 \frac{2}{12} - ? = 11 \frac{2}{3}$

$\frac{123}{7} + \frac{158}{12} - ? = \frac{35}{3}$

=> $? = \frac{123}{7} + \frac{158}{12} - \frac{35}{3}$

=> ? = $\frac{1476 + 1106 - 980}{84}$

=> ? = 19.07

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Filed Under: Simplification
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13 9887

Q:

A loan shark made a loan of $100 to be repaid with $120 at the end of one month. What was the annual interest rate?

A) 210%	B) 220%
C) 230%	D) 240%

Answer & Explanation Answer: D) 240%

Explanation:

r=I/PT

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Filed Under: Simple Interest
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5 9886

Q:

In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered to with remaining meal?

A) 50	B) 40
C) 30	D) 20

Answer & Explanation Answer: C) 30

Explanation:

There is a meal for 200 children. 150 children have taken the meal.

Remaining meal is to be catered to 50 children.

Now, 200 children = 120 men.

50 children = $(\frac{120}{200}) 50$ =30men

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Filed Under: Chain Rule

8 9875

Q:

A jogger is running at 9 kmph alongside a railway track is 240 meters ahead of the engine of a 120 meters long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ?

A) 48 sec	B) 36 sec
C) 18 sec	D) 72 sec

Answer & Explanation Answer: B) 36 sec

Explanation:

Speed of the train relative to jogger = (45-9) km/hr = 36 km/hr =(36*5/18) m/sec = 10 m/sec

Distance to be covered =(240 + 120)m = 360 m

$\therefore$ Time taken = 360/10 sec = 36 sec

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Filed Under: Problems on Trains

11 9866

Q:

An Engine length 1000 m moving at 10 m/s. A bird is flying from engine to end with 'x' m/s and coming back at '2x' m/s. Take total time of bird travelling as 187.5 s. Find x and 2x in km/hr ?

A) 21.4 and 42.8	B) 25.2 and 50.4
C) 31.4208 and 62.8416	D) 33.12 and 66.24

Answer & Explanation Answer: C) 31.4208 and 62.8416

Explanation:

Birds speeds in mtrs/sec is 'x' and '2x' .
While flying from Engine to end, relative speed = (x+10) m/sec
from end to engine, flying speed = (2x - 10) mtr/sec
so
1000/(x+10) + 1000/(2x-10) = 187.5 secs
solving it, we get
so x = 8.728 m/sec and 2x= 17.456 m/sec

x = 31.4208 km/hr and 2x = 62.8416 km/hr.

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Filed Under: Problems on Trains
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11 9856

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