6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

The number of permutations of the letters of the word 'MESMERISE' is ?

A) 9!/(2!)^{2}x3!	B) 9! x 2! x 3!
C) 0	D) None

Answer & Explanation Answer: A) 9!/(2!)^{2}x3!

Explanation:

n items of which p are alike of one kind, q alike of the other, r alike of another kind and the remaining are distinct can be arranged in a row in n!/p!q!r! ways.
The letter pattern 'MESMERISE' consists of 10 letters of which there are 2M's, 3E's, 2S's and 1I and 1R.
Number of arrangements = $\frac{9!}{(2!)^{2} \times 3!}$

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Filed Under: Permutations and Combinations
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3 9536

Q:

How many minutes does a watch lose per day, if its hands coincide every 64 minutes ?

A) 36 7/9 min	B) 32 8/11 min
C) 34 3/11 min	D) 65 5/11 min

Answer & Explanation Answer: B) 32 8/11 min

Explanation:

55 min. spaces are covered in 60 min.

60 min. spaces are covered in $open parentheses 60 over 55 cross times 60 close parentheses$ min. = $65 5 over 11$ min.

Loss in 64 min. = $open parentheses 65 5 over 11 minus 64 close parentheses equals 16 over 11$ min.

Loss in 24 hrs = $open parentheses 16 over 11 cross times 1 over 64 cross times 24 cross times 60 close parentheses$ min. = $32 8 over 11$ min.

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Filed Under: Clocks
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36 9535

Q:

The angle between the minute hand and the hour hand of a clock when the time is 4.15 is

A) 0	B) 37.5
C) 27	D) 15

Answer & Explanation Answer: B) 37.5

Explanation:

Angle between hands of a clock

When the minute hand is behind the hour hand, the angle between the two hands at M minutes past H 'o clock

=> $30 (H - \frac{M}{5}) + \frac{M}{2}$ degrees

Here H = 4, M = 15 and the minute hand is behind the hour hand.

Hence the angle

= 30[4-(15/5)]+15/2 = 30(1)+7.5 = 37.5 degrees

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Filed Under: Clocks
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24 9532

Q:

Two pipes A and B can fill a tank in 15 min and 20 min respectively. Both the pipes are opened together but after 4 min, pipe A is turned off. What is the total time required to fill the tank ?

A) 15 min 20 sec.	B) 16 min 40 sec.
C) 13 min 10 sec.	D) 14 min 40 sec.

Answer & Explanation Answer: D) 14 min 40 sec.

Explanation:

Part filled in 4 minutes = 4(1/15 + 1/20) = 7/15

Remaining part = 1 - 7/15 = 8/15

Part filled by B in 1 minute = 1/20

1/20 : 8/15 :: 1 : k

k = (8/15 )x 1 x 20 = 10( 2/3) min = 10 min 40 sec.

The tank will be full in (4 min. + 10 min. 40 sec) = 14 min 40 sec.

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Filed Under: Pipes and Cistern
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7 9532

Q:

Pooja, Shipra and Mounika are three sisters .Pooja and Shipra are twins. The ratio of sum of the ages of Pooja and Shipra is same as that of Mounika alone. Three years earlier the ratio of age of Pooja and Mounika was 2:7 . what will be the age of Shipra 3 years hence?

A) 21 years	B) 16 years
C) 8 years	D) 12 years

Answer & Explanation Answer: C) 8 years

Explanation:

Since Pooja and Shipra are twins so their ages be same. Let their ages be x and age of Mounika be y , then

x+x = y -------(1)

and $\frac{x - 3}{y - 3} = \frac{2}{7} \Rightarrow 7 x - 2 y = 15$

Now, from equation (1),

7x - 4x = 15 => x = 5

So the age of Shipra 3 years hence will be 5+3 = 8 years

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Filed Under: Ratios and Proportions

12 9524

Q:

Three taps I, J and K can fill a tank in 20,30and 40 minutes respectively. All the taps are opened simultaneously and after 5 minutes tap A was closed and then after 6 minutes tab B was closed .At the moment a leak developed which can empty the full tank in 70 minutes. What is the total time taken for the completely full ?

A) 24.315 minutes	B) 26.166 minutes
C) 22.154 minutes	D) 24 minutes

Answer & Explanation Answer: B) 26.166 minutes

Explanation:

Upto first 5 minutes I, J and K will fill => 5[(1/20)+(1/30)+(1/40)] = 65/120

For next 6 minutes, J and K will fill => 6[(1/30)+(1/40)] = 42/120

So tank filled upto first 11 minutes = (65/120) + (42/120) = 107/120
So remaining tank = 13/120

Now at the moment filling with C and leakage @ 1/60 per minute= (1/40) - (1/70) = 3/280.
So time taken to fill remaining 13/120 tank =(13/120) /(3/280) = 91/6 minutes

Hence total time taken to completely fill the tank = 5 + 6 + 91/6 = 26.16 minutes.

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Filed Under: Pipes and Cistern
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13 9523

Q:

If a trader sold two cars each at Rs. 325475 and gains 12% on the first and loses 12% on the second, then his profit or loss percent on the whole is ?

A) 1.44% loss	B) 14.4% loss
C) 0%	D) 14.4% profit

Answer & Explanation Answer: A) 1.44% loss

Explanation:

SP of each car is Rs. 325475, he gains 12% on first car and losses 12% on second car.
In this case, there will be loss and percentage of loss is given by

= [(profit%)(loss%)]/100 = (12)(12)/100 % = 1.44%

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Filed Under: Profit and Loss
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2 9518

Q:

A certain amount is divided among P, Q and R in the ratio of 3 : 7 : 6 respectively. If the difference between share of P and Q is Rs. 2700, what is R's share?

A) Rs. 4050	B) Rs. 2121
C) Rs. 5040	D) Rs. 3550

Answer & Explanation Answer: A) Rs. 4050

Explanation:

Let the ratio amount be 'p'

7p - 3p = 2700

4p = 2700

p = 675

R's Share = 675 × 6 = Rs. 4050

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Filed Under: Partnership
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14 9514

Quantitative Aptitude - Arithmetic Ability Questions

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