Quantitative Aptitude - Arithmetic Ability Questions

Q:

1.12.91 is the first Tuesday. Which is the fourth Thursday of December 91  ?

A) 22.12.91 B) 25.12.91
C) 24.12.91 D) 23.12.91
 
Answer & Explanation Answer: B) 25.12.91

Explanation:

Given that 2.12.91 is the first Tuesday
Hence we can assume that 4.12.91 is the first Thursday

If we add 7 days to 4.12.91, we will get second Thursday
If we add 14 days to 4.12.91, we will get third Thursday
If we add 21 days to 4.12.91, we will get fourth Thursday

=> fourth Thursday = (4.12.91 + 21 days) = 25.12.91.

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Filed Under: Calendar
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32 8674
Q:

Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30º and 45º respectively. If the lighthouse is 100 m high, the distance between the two ships is:

A) 173 m B) 200 m
C) 273 m D) 300 m
 
Answer & Explanation Answer: C) 273 m

Explanation:

 Let AB be the lighthouse and C and D be the positions of the ships.

 

 

Then, AB = 100m, ACB = 30°andADB =45°

 

ABAC=tan30°=13=>AC=AB*3=1003m

 

 

 ABAD=tan45°=1=>AD=AB=100m

CD=(AC+AD)=1003+100m=1003+1=100*2.73=273m

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Filed Under: Height and Distance

17 8672
Q:

The odds favouring the event of a person hitting a target are 3 to 5. The odds against the event of another person hitting the target are 3 to 2. If each of them fire once at the target, find the probability that both of them hit the target.

A) 1/20 B) 4/20
C) 1/20 D) 3/20
 
Answer & Explanation Answer: D) 3/20

Explanation:

Let A be the event of first person hitting the target,

P(A) =33+5=38  (odd in favour)

Let B be the event of Second person hitting a target.

P(B)=23+2=25 (odd against)

Since both events are independent and both will hit the target so,

P(AB)= P(A)P(B)=38×25=320

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Filed Under: Probability

3 8666
Q:

The total weight of a tin and the cookies it contains is 2 pounds. After ¾ of the cookies are eaten, the tin and the remaining cookies weigh 0.8 pounds. What is the weight of the empty tin in pounds?

A) 0.2 B) 0.3
C) 0.4 D) 0.5
 
Answer & Explanation Answer: C) 0.4

Explanation:

Let the weight of the empty tin = w

(2 - w) = weight of the cookies; and one quarter of the cookies weigh (2 - w)/4

One quarter of the cookies + tin = 0.8 = w + (2 - w)/4

Multiply through by 4; 3.2 = 4w + 2 - w

1.2 = 3w; w = 0.4

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Filed Under: Problems on Numbers
Exam Prep: GRE

1 8655
Q:

Find the number of ways in which 21 balls can be distributed among 3 persons such that each person does not receive less than 5 balls.

A) 28 B) 14
C) 21 D) 7
 
Answer & Explanation Answer: A) 28

Explanation:

Let x, y, z be the number of balls received by the three persons, then

  

x5, y5, z5 and x+y+z=21

 

Let u0, v0, w0 then

 

 x + y + z =21

 

 u + 5 + v + 5 + w + 5 = 21

 

 u + v + w = 6 

 

Total number of solutions = C3-16+3-1=C28=28

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18 8617
Q:

A batsman scores 26 runs and increases his average from 14 to 15. Find the runs to be made if he wants top increasing the average to 19 in the same match ?

A) 74 B) 79
C) 72 D) 60
 
Answer & Explanation Answer: A) 74

Explanation:

Number of runs scored more to increse the ratio by 1 is 26 - 14 = 12
To raise the average by one (from 14 to 15), he scored 12 more than the existing average.
Therefore, to raise the average by five (from 14 to 19), he should score 12 x 5 = 60 more than the existing average. Thus he should score 14 + 60 = 74.

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Filed Under: Average
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9 8616
Q:

Rs. 69 were divided among 115 family members so that each lady gets 50 paise less than each gentleman, and each gentleman received twice the paise as each lady received. Find the number of  gentlemen in the family?

A) 23 B) 92
C) 48 D) 52
 
Answer & Explanation Answer: A) 23

Explanation:

Total number of female members = 115

Let the number of males = x

Number of females = y

=> x + y = 115  ......(1)

According to the given data,

x + y(0.50) = 69 ......(2)

From (1) & (2), we get

0.5y = 46

=> y = 46 x 2 = 92

=> x = 115 - 92 = 23

 

Hence, required number of gentlemen in the family = x = 23.

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Filed Under: Percentage
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8 8610
Q:

Ten women can do a work in six days. Six men can complete the same work in five days. What is the ratio between the capacity of a man and a woman?

A) 1:2 B) 2:1
C) 2:3 D) 3:2
 
Answer & Explanation Answer: B) 2:1

Explanation:

(10 * 6) women can complete the work in 1 day.

 Therefore, 1 woman's  1 day's work = 1/60

 

(6 * 5) men can complete the work in 1 day.

 Therefore, 1 man's  1 day's work = 1/30

 

so, required ratio =1/30 : 1/60 = 2:1

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Filed Under: Time and Work

4 8599